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# The Orloff Candy Company packs its cylindrical candy treats

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Manager
Joined: 29 Sep 2008
Posts: 90
The Orloff Candy Company packs its cylindrical candy treats  [#permalink]

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22 Oct 2010, 11:21
2
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Difficulty:

45% (medium)

Question Stats:

61% (01:25) correct 39% (01:20) wrong based on 50 sessions

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The Orloff Candy Company packs its cylindrical candy treats in a rectangular container. The height of the container is exactly equal to the height of each treat. How many treats can be packed into each container?

(1) The circumference of the treat is 2 inches.

(2) The area of a horizontal cross-section of the container is 100 inches.

i have a question.we can find the radius of cylinder thru the stmnt 1.we are given the area of horizontal cross section i.e. I*B=100.the height of cylinder and rectangular container are equal

so we can find the volume:
Volume of cylinder=pi*r^2*h
Volume of rectangular container=100*h

we can find the no of candy treats by dividing the vol of container by vol of cylinder.

as a result the ans should be but its different.can anyone point where i am making the mistake
Intern
Joined: 20 Jul 2010
Posts: 39

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22 Oct 2010, 12:09
Sound to me you are right!

-Ravi
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Ravi

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22 Oct 2010, 15:59
mrinal2100 wrote:
The Orloff Candy Company packs its cylindrical candy treats in a rectangular container. The height of the container is exactly equal to the height of each treat. How many treats can be packed into each container?

(1) The circumference of the treat is 2 inches.

(2) The area of a horizontal cross-section of the container is 100 inches.

i have a question.we can find the radius of cylinder thru the stmnt 1.we are given the area of horizontal cross section i.e. I*B=100.the height of cylinder and rectangular container are equal

so we can find the volume:
Volume of cylinder=pi*r^2*h
Volume of rectangular container=100*h

we can find the no of candy treats by dividing the vol of container by vol of cylinder.

as a result the ans should be but its different.can anyone point where i am making the mistake

The important thing to note is that knowing the area and thus the volume is not enough.
In this case we know the radius of the cylinder is $$r=\frac{1}{\pi}$$

Now imagine case 1, that the rectangular box is 10x10, in which case clearly a few of those treats can fit inside the box

Case 2, is that the box is 0.0001x1000000, same area. But the box is so thin no treats can fit on it

Hence, to find out the number of treats, we need to know the dimensions of the box, not jsut the area. The packing arrangement is intricately related to the dimensions .. thus answer is (e)
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Re: The Orloff Candy Company packs its cylindrical candy treats  [#permalink]

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17 Aug 2017, 19:04
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: The Orloff Candy Company packs its cylindrical candy treats   [#permalink] 17 Aug 2017, 19:04
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