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The positive integer k has exactly two positive prime factor

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The positive integer k has exactly two positive prime factor [#permalink]

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The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of K?

(1) 3^2 is a factor of k
(2) 7^2 is NOT a factor of k


[Reveal] Spoiler:
I searched thru 6-7 pages using keywords, but I did not find this question asked, I think this could be a newly added question in the gmatprep software.

somewhat of a tricky wording question, especially when time is running short. oa is d.

correction: oa is D.
[Reveal] Spoiler: OA

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Last edited by Bunuel on 03 Nov 2013, 05:08, edited 2 times in total.
Renamed the topic, edited the question and added the OA.

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Re: Gmatprep DS: the positive integer k has exactly two [#permalink]

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Based on stem, the 6 factors of k are 1,3,7,21, x and k . where 7 < x < k.

If statement (1) is used, the factors are, 1, 3, 7, 9, 21, k. k = 63. sufficient
Since stem says 3,7 are the only prime factors, x has to be 3^2 since x cannot be 7^2. - sufficient

Answer (C)

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Re: Gmatprep DS: the positive integer k has exactly two [#permalink]

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New post 28 Feb 2008, 06:19
gmatnub wrote:
Gmatprep DS: the positive integer k has exactly two positive prime factors, 3 and 7. If K has a total of 6 positive factors, including 1 and k, what is the value of K?

1) 3^2 is a factor of k

2) 7^2 is NOT a factor of k



I searched thru 6-7 pages using keywords, but I did not find this question asked, I think this could be a newly added question in the gmatprep software.

somewhat of a tricky wording question, especially when time is running short. oa is a.


K has 6 factors: 1,3,7,21,X,K (different factors) Essentially we need to find X then we will know K.

1: X must be 9. b/c K has two 3's as factors.

2: if 7^2 is not a factor of K then X cannot be 49. Since we only have 3 and 7 as prime factors, 3 must be the other factor and X would be 9.

I get D

Im not sure why OA is A... =(

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Re: Gmatprep DS: the positive integer k has exactly two [#permalink]

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New post 16 Feb 2009, 21:55
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Good question. I have a different way of solving this.


Let P1 = Power of first factor
Let P2 = Power of second factor
The number of factors can be found using the equation (P1 + 1)(P2 + 1). This is a rule, I didn't come up with this.
Therefore here we have:
2*3 or 3*2, both equal 6.

statement 1: says that 3*2 is out, therefore sufficient
statement 2: says that 3*2 is out, therefore sufficient.

note that we cannot use 6*1, because then we have a 7^0 or a 3^0, which is not the case here.

Answer D.

What do you think?

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Re: Gmatprep DS: the positive integer k has exactly two [#permalink]

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New post 19 Feb 2009, 10:07
x1050us wrote:
Based on stem, the 6 factors of k are 1,3,7,21, x and k . where 7 < x < k.

If statement (1) is used, the factors are, 1, 3, 7, 9, 21, k. k = 63. sufficient
Since stem says 3,7 are the only prime factors, x has to be 3^2 since x cannot be 7^2. - sufficient

Answer (C)



I don't understand why k=63, why can't it be 27 (due to 3 x 9)??

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Re: Gmatprep DS: the positive integer k has exactly two [#permalink]

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New post 19 Feb 2009, 11:11
DaveGG wrote:
x1050us wrote:
Based on stem, the 6 factors of k are 1,3,7,21, x and k . where 7 < x < k.

If statement (1) is used, the factors are, 1, 3, 7, 9, 21, k. k = 63. sufficient
Since stem says 3,7 are the only prime factors, x has to be 3^2 since x cannot be 7^2. - sufficient

Answer (C)



I don't understand why k=63, why can't it be 27 (due to 3 x 9)??


In that case, k would have 3^3 as factor. If so, the k would have more than 6 factors as under: 1, 3, 7, 9, 21, 27, 42, 63, and 189


gmatnub wrote:
Gmatprep DS: the positive integer k has exactly two positive prime factors, 3 and 7. If K has a total of 6 positive factors, including 1 and k, what is the value of K?

1) 3^2 is a factor of k
2) 7^2 is NOT a factor of k


We need one more either 3 or 7 to have 6 +ve factors of k.

a: 3^2 makes 6 +ve factors.
b. if there is no 7^2 as a factor of k, then it also makes sure that 3^3 is a factor of k.
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Re: What is the value of K - Confusing one [#permalink]

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From the stem, we know that K's factors are 1, 3, 7, 21 (3*7), __, and K.

1) This tells us there are two factors of 3, so 9 is also a factor of K. K's factors are 1, 3, 7, 9, 21, and K. Since there are two 3's and a 7 in K's factors, then 3*3*7 = 63 is also a factor.

Therefore K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

2) If there are not 2 7's in K's factors, and there are exactly 6 factors total, there must be two factors of 3. Otherwise, if we were to use a non-prime factor, then K would have more than 6 factors. (Remember 'K' has exactly two positive prime factors)

Therefore, K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

Answer is D.

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Re: What is the value of K - Confusing one [#permalink]

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Positive integer 'K' has exactly two positive prime factors, 3 and 7. If 'K' has a total of 6 factors, including 1 and 'K', what is the value of 'K'?

(1) 3^2 is a factor of 'K'

(2) 7^2 is not a factor of 'K'.


Soln:
Since k has two positive prime factors
k = 3^a * 7^b
k has a total of 6 factors meaning
(a+1) * (b+1) = 6
this can be either
(a+1) * (b+1) = 1 * 6
or
(a+1) * (b+1) = 2 * 3

1 * 6 is not possible because one of the factors will become 0. In tat case k will have just one prime factor. Hence the only option is 2 * 3
So when a = 2, b = 1 and when a = 1, b = 2
thus k can be either 3^2 * 7^1 or 3^1 * 7^2

Now considering statement 1 alone,
3^2 is a factor of 'K'. This will be true only when k = 3^2 * 7^1
Thus statement 1 alone is sufficient

Now considering statement 2 alone,
7^2 is not a factor of 'K'. This will be true only when k = 3^2 * 7^1
Thus statement 2 alone is sufficient

Hence D

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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 09 Nov 2013, 16:06
gmatnub wrote:
The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of K?

(1) 3^2 is a factor of k
(2) 7^2 is NOT a factor of k


[Reveal] Spoiler:
I searched thru 6-7 pages using keywords, but I did not find this question asked, I think this could be a newly added question in the gmatprep software.

somewhat of a tricky wording question, especially when time is running short. oa is d.

correction: oa is D.


K=3^a * 7^b

and (a+1) *(b+1) = 6

so either a=1, b=2, or a=2, b=1

both statements would help us get K=3^2 * 7= 63

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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 16 Nov 2013, 13:43
gmatnub wrote:
The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of K?

(1) 3^2 is a factor of k
(2) 7^2 is NOT a factor of k



The solutions that try to name each factor are dangerous because one can always run the risk to overlook one or two factors. Oddly enough, I feel that the best way to approach this problem is through "combinatories"! It is just a matter of seeing that the total number of factors in K (6 as mentioned in the stem) is the product of the "group of possible factors including 3" and "the group of possible factors including 7".

Statement one is sufficient: As per the statement, the group of possible factors including 3 is 3 (0, 1 or 2 times) - therefore 3 possibilities. We do know that total number of factors of K is 6, so the group of possible factors including 7 has to be two - when 7 appears 0 or 1 time. So group of three - three elements (0,1 or 2) times group of 7 - two elements (0 or 1) equals 6!

Statement two is also sufficient: The only possible factors of K is 6, so either "the group of factors including 7" is two (7^1) or three (7^2) possibilities. The statement rules out the later, that leaves you with two possibilities for "the group of factors including 7".

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Re: What is the value of K - Confusing one [#permalink]

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New post 30 Dec 2013, 18:14
samiam7 wrote:
From the stem, we know that K's factors are 1, 3, 7, 21 (3*7), __, and K.

1) This tells us there are two factors of 3, so 9 is also a factor of K. K's factors are 1, 3, 7, 9, 21, and K. Since there are two 3's and a 7 in K's factors, then 3*3*7 = 63 is also a factor.

Therefore K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

2) If there are not 2 7's in K's factors, and there are exactly 6 factors total, there must be two factors of 3. Otherwise, if we were to use a non-prime factor, then K would have more than 6 factors. (Remember 'K' has exactly two positive prime factors)

Therefore, K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

Answer is D.



The bold part is what I do not understand. I am sorry, but I dont get the factors part where it says "there are two 3's and a 7 in K's factors".

Can someone please explain why is this the case? What allows us to say this? I mean what allows us to say two 3's and a 7? 9 is 3^2, 21 is 3*7, but....?

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Re: What is the value of K - Confusing one [#permalink]

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jjack0310 wrote:
samiam7 wrote:
From the stem, we know that K's factors are 1, 3, 7, 21 (3*7), __, and K.

1) This tells us there are two factors of 3, so 9 is also a factor of K. K's factors are 1, 3, 7, 9, 21, and K. Since there are two 3's and a 7 in K's factors, then 3*3*7 = 63 is also a factor.

Therefore K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

2) If there are not 2 7's in K's factors, and there are exactly 6 factors total, there must be two factors of 3. Otherwise, if we were to use a non-prime factor, then K would have more than 6 factors. (Remember 'K' has exactly two positive prime factors)

Therefore, K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

Answer is D.



The bold part is what I do not understand. I am sorry, but I dont get the factors part where it says "there are two 3's and a 7 in K's factors".

Can someone please explain why is this the case? What allows us to say this? I mean what allows us to say two 3's and a 7? 9 is 3^2, 21 is 3*7, but....?


Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

Back to the original question:

The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of K?

"k has exactly two positive prime factors 3 and 7" --> \(k=3^m*7^n\), where \(m=integer\geq{1}\) and \(n=integer\geq{1}\);
"k has a total of 6 positive factors including 1 and k" --> \((m+1)(n+1)=6\). Note here that neither \(m\) nor \(n\) can be more than 2 as in this case \((m+1)(n+1)\) will be more than 6.

So, there are only two values of \(k\) possible:
1. if \(m=1\) and \(n=2\) --> \(k=3^1*7^2=3*49\);
2. if \(m=2\) and \(n=1\) --> \(k=3^2*7^1=9*7\).

(1) 3^2 is a factor of k --> we have the second case, hence \(k=3^2*7^1=9*7\). Sufficient.

(2) 7^2 is NOT a factor of k --> we have the second case, hence \(k=3^2*7^1=9*7\). Sufficient.

Answer: D.

Hope it's clear.
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Re: What is the value of K - Confusing one [#permalink]

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New post 01 Jan 2014, 08:58
Bunuel wrote:
jjack0310 wrote:
From the stem, we know that K's factors are 1, 3, 7, 21 (3*7), __, and K.

1) This tells us there are two factors of 3, so 9 is also a factor of K. K's factors are 1, 3, 7, 9, 21, and K. Since there are two 3's and a 7 in K's factors, then 3*3*7 = 63 is also a factor.

Therefore K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

2) If there are not 2 7's in K's factors, and there are exactly 6 factors total, there must be two factors of 3. Otherwise, if we were to use a non-prime factor, then K would have more than 6 factors. (Remember 'K' has exactly two positive prime factors)

Therefore, K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

Answer is D.



The bold part is what I do not understand. I am sorry, but I dont get the factors part where it says "there are two 3's and a 7 in K's factors".

Can someone please explain why is this the case? What allows us to say this? I mean what allows us to say two 3's and a 7? 9 is 3^2, 21 is 3*7, but....?

Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

Back to the original question:

The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of K?

"k has exactly two positive prime factors 3 and 7" --> \(k=3^m*7^n\), where \(m=integer\geq{1}\) and \(n=integer\geq{1}\);
"k has a total of 6 positive factors including 1 and k" --> \((m+1)(n+1)=6\). Note here that neither \(m\) nor \(n\) can be more than 2 as in this case \((m+1)(n+1)\) will be more than 6.

So, there are only two values of \(k\) possible:
1. if \(m=1\) and \(n=2\) --> \(k=3^1*7^2=3*49\);
2. if \(m=2\) and \(n=1\) --> \(k=3^2*7^1=9*7\).

(1) 3^2 is a factor of k --> we have the second case, hence \(k=3^2*7^1=9*7\). Sufficient.

(2) 7^2 is NOT a factor of k --> we have the second case, hence \(k=3^2*7^1=9*7\). Sufficient.

Answer: D.

Hope it's clear.



Thank you much Bunuel.

Just one last question, and the reason that we are not acounting for the case when m = 0, and n = 5 is because 3^0 or 7^0 would be 1, and in that case, 3 is not a prime factor of k. Correct?

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Re: What is the value of K - Confusing one [#permalink]

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New post 02 Jan 2014, 04:19
jjack0310 wrote:
Bunuel wrote:
jjack0310 wrote:
From the stem, we know that K's factors are 1, 3, 7, 21 (3*7), __, and K.

1) This tells us there are two factors of 3, so 9 is also a factor of K. K's factors are 1, 3, 7, 9, 21, and K. Since there are two 3's and a 7 in K's factors, then 3*3*7 = 63 is also a factor.

Therefore K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

2) If there are not 2 7's in K's factors, and there are exactly 6 factors total, there must be two factors of 3. Otherwise, if we were to use a non-prime factor, then K would have more than 6 factors. (Remember 'K' has exactly two positive prime factors)

Therefore, K's factors are 1, 3, 7, 9, 21, 63.
SUFFICIENT

Answer is D.



The bold part is what I do not understand. I am sorry, but I dont get the factors part where it says "there are two 3's and a 7 in K's factors".

Can someone please explain why is this the case? What allows us to say this? I mean what allows us to say two 3's and a 7? 9 is 3^2, 21 is 3*7, but....?

Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

Back to the original question:

The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of K?

"k has exactly two positive prime factors 3 and 7" --> \(k=3^m*7^n\), where \(m=integer\geq{1}\) and \(n=integer\geq{1}\);
"k has a total of 6 positive factors including 1 and k" --> \((m+1)(n+1)=6\). Note here that neither \(m\) nor \(n\) can be more than 2 as in this case \((m+1)(n+1)\) will be more than 6.

So, there are only two values of \(k\) possible:
1. if \(m=1\) and \(n=2\) --> \(k=3^1*7^2=3*49\);
2. if \(m=2\) and \(n=1\) --> \(k=3^2*7^1=9*7\).

(1) 3^2 is a factor of k --> we have the second case, hence \(k=3^2*7^1=9*7\). Sufficient.

(2) 7^2 is NOT a factor of k --> we have the second case, hence \(k=3^2*7^1=9*7\). Sufficient.

Answer: D.

Hope it's clear.



Thank you much Bunuel.

Just one last question, and the reason that we are not acounting for the case when m = 0, and n = 5 is because 3^0 or 7^0 would be 1, and in that case, 3 is not a prime factor of k. Correct?


Absolutely, m and n must be greater than zero because if they are not then 3 and 7 are not the factors of k.
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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 24 Feb 2015, 06:06
Stem says that

3^x*7^y=k

(x+1)*(y+1)=6 with at least one 3 and 7
xy+x+y+1=6
x(y+1)+y=5
only possibility is x=2 and y=1, so k=3^2*7=63

No need in any statement

D

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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 08 Jan 2017, 21:39
Given : \(k=3^n * 7^m\) --------(1), where m & n are powers of prime factors, 3 and 7.
also we know that k has a total of 6 positive factors, including 1 and k

this can be represented as (n+1)(m+1)=6 --------(2)

statement (1) : 3^2 is a factor of k
n=2 , substitute in (2) , we get m=1
put n=2 & m=1 in (1) , we get \(k=3^2 * 7^1\) >> k=63 >> sufficient.

statement (2) : \(7^2\) is NOT a factor of k
as from the question stem , we know that 7 is among the prime factors of k, hence ,the minimum power of 7 is 1.
therefore m=1 , substitute in (2) , we get n=2
put n=2 & m=1 in (1) , we get \(k=3^2 * 7^1\) >> k=63 >> sufficient.

Ans : D

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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 29 Jan 2017, 16:24
statement (1)
if 3^2 is a factor of k, then so is 3^1.
therefore, we already have four factors: 1, 3^1, 3^2, and 7.
but we also know that (3^1)(7) and (3^2)(7) must be factors, since 3^2 and 7 are both part of the prime factorization of k.
that's already six factors, so we're done: k must be (3^2)(7). if it were any bigger, then there would be more than these six factors.
sufficient.

statement (2)
if 7 is a factor of k, but 7^2 isn't, then the prime factorization of k contains EXACTLY one 7.
therefore, we need to find out how many 3's will produce six factors when paired with exactly one 7.
in fact, it's data sufficiency, so we don't even have to find this number; all we have to do is realize that adding more 3's will always increase the number of factors, so, there must be exactly one number of 3's that will produce the correct number of factors. (as already noted above, that's two 3's, or 3^2.)
sufficient.
Hence D.
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Re: The positive integer k has exactly two positive prime factors, 3 and 7 [#permalink]

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New post 25 Jun 2017, 18:32
suntorytea wrote:
The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of k?

(1) 3^2 (3 squared) is a factor of k.
(2) 7^2 (7 squared) is NOT a factor of k.

Help would be appreciated! Thanks.

Best regards,
ST



Hint :- if k has 6 factors
then k must be 3^2 *7
or k = 3* 7^2

now try yourself :)

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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 25 Jun 2017, 20:57
suntorytea wrote:
The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of k?

(1) 3^2 (3 squared) is a factor of k.
(2) 7^2 (7 squared) is NOT a factor of k.

Help would be appreciated! Thanks.

Best regards,
ST


Hi suntorytea,

This question has already been discussed on the forum. If you check the following thread then you'd see really good solutions provided by others:
https://gmatclub.com/forum/the-positive-integer-k-has-exactly-two-positive-prime-factor-60634.html

Suggestion:
First google or use gmatclub search to check whether question already exist on the forum or not
If you have specific query then post on that existing thread.
To tag people use "@"before username

Here are the RULES of posting to help you further on this:
https://gmatclub.com/forum/rules-for-posting-please-read-this-before-posting-133935.html

Hope this helps :)
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Re: The positive integer k has exactly two positive prime factor [#permalink]

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New post 25 Jun 2017, 21:02
Bunuel wrote:
suntorytea wrote:
The positive integer k has exactly two positive prime factors, 3 and 7. If k has a total of 6 positive factors, including 1 and k, what is the value of k?

(1) 3^2 (3 squared) is a factor of k.
(2) 7^2 (7 squared) is NOT a factor of k.

Help would be appreciated! Thanks.

Best regards,
ST


Merging topics. Please refer to the discussion above.


Thanks Bunuel for merging. By the time i could post my suggestion, topic was merged. But In general when we're previewing the answer, we get to see if someone has posted in meanwhile or not. but nothing like this in this case.
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Re: The positive integer k has exactly two positive prime factor   [#permalink] 25 Jun 2017, 21:02

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