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The price was increased by x % and then decreased by y %. Is [#permalink]
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02 Mar 2008, 03:22
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The price was increased by x % and then decreased by y %. Is the new price higher than the original? 1. x>y 2. x=1.2y



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Re: Inequalities [#permalink]
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02 Mar 2008, 06:53
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Suppose original Price was 100. So Price after increase by X% = 100 + X Price after decrease by Y% = 100 + X  Y  XY/100
New Price  Old Price = 100 + X  Y XY/100  100 = X  Y XY/100
So we need to answer whether or not this entity is +ve or negative X  Y XY/100
Statement 1: Say X=0.2,Y=0.1 So Entity = 0.1  .0002 = +ve entity Say X=100, Y=1, so Entity = 99  1 = +ve entity
So question can be Answered with A
Statement 2: It is nothing but restatement of statement 1 with 1 fix value. So this also answers the questions.
Question can be answered with both the statements alone. (D)



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Re: Inequalities [#permalink]
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02 Mar 2008, 09:17
abhijit_sen wrote: Suppose original Price was 100. So Price after increase by X% = 100 + X Price after decrease by Y% = 100 + X  Y  XY/100
New Price  Old Price = 100 + X  Y XY/100  100 = X  Y XY/100
So we need to answer whether or not this entity is +ve or negative X  Y XY/100
Statement 1: Say X=0.2,Y=0.1 So Entity = 0.1  .0002 = +ve entity Say X=100, Y=1, so Entity = 99  1 = +ve entity
So question can be Answered with A
Statement 2: It is nothing but restatement of statement 1 with 1 fix value. So this also answers the questions.
Question can be answered with both the statements alone. (D) OA is E. if x is much bigger than y, the new price would be higher than the original, otherwise it wouldn't. this reasoning is true both for 1 and 2. try out.



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Re: Inequalities [#permalink]
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02 Mar 2008, 12:22
marcodonzelli wrote: abhijit_sen wrote: Suppose original Price was 100. So Price after increase by X% = 100 + X Price after decrease by Y% = 100 + X  Y  XY/100
New Price  Old Price = 100 + X  Y XY/100  100 = X  Y XY/100
So we need to answer whether or not this entity is +ve or negative X  Y XY/100
Statement 1: Say X=0.2,Y=0.1 So Entity = 0.1  .0002 = +ve entity Say X=100, Y=1, so Entity = 99  1 = +ve entity
So question can be Answered with A
Statement 2: It is nothing but restatement of statement 1 with 1 fix value. So this also answers the questions.
Question can be answered with both the statements alone. (D) OA is E. if x is much bigger than y, the new price would be higher than the original, otherwise it wouldn't. this reasoning is true both for 1 and 2. try out. huh? explain please



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Re: Inequalities [#permalink]
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02 Mar 2008, 12:44
Lets take original price = 100 and x=50 y=40 new price = 1.50x 100x 0.60= 90 hence less than original suppose x=80 y= 10 new price = 1.80x 100x .90= 162 more than original This is true for both the statements so answer E



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Re: The price was increased by x % and then decreased by y %. Is [#permalink]
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26 Jul 2012, 02:54
In this question, statement 2 is basically telling the same thing as stat 1 ( because both x and y need to positive numbers  negative values of x and y doesn't make sense in this case and we know that when both x and y are positive and x = 1.2y then we also know that x>y)
Wouldn't that mean that stat 2 is insuff since it is conveying the same info as 1 and the moment we are done testing 1 we can see how the answer is (E)
Please correct me if I am wrong?



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Re: The price was increased by x % and then decreased by y %. Is [#permalink]
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26 Jul 2012, 23:32
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E.
(1) x > y Say you start with 100, x=60 and y=50 100 incr by 60% = 160, then decr by 50% = 80 (less than 100)
Now x=12 and y=10 100 incr by 12% = 112, then decr by 10% = 11211.2 = 100.8 (greater than 100)
Insufficient.
(2) x=1.2y
The same numbers can be used resulting in one being greater than 100 and one being less than 100. Insufficient
Combined, the same percentages can be used and we would arrive at the same results. Answer is E.
Since x is always greater than y in constraint (2), you only need to test constraint (2) to see if you can get values above and below 100.



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