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The 1st kid may be a boy or a girl, we are only concerned with the gender of the other 2 kids, which must be same as the 1st kid.
Hence the Probability that the gender of the 2 kids is same as the 1st kid = 1/2 * 1/2 = 1/4

Answer: E
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campus1995
The probability of having a girl is identical to the probability of having a boy. In a family with three children, what is the probability that all the children are of the same gender?

(A) 1/8
(B) 1/6
(C) 1/3
(D) 1/5
(E) 1/4

Probability of all three children to be Boy = (1/2)*(1/2)*(1/2) = 1/8
Probability of all three children to be Girl = (1/2)*(1/2)*(1/2) = 1/8

Probability of all three children to be Same gender = (1/8) + (1/8) = 1/4

Answer: Option E
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campus1995
The probability of having a girl is identical to the probability of having a boy. In a family with three children, what is the probability that all the children are of the same gender?

(A) 1/8
(B) 1/6
(C) 1/3
(D) 1/5
(E) 1/4

Hi,
prob of same gender= prob of boy+ prob of girl= 1/2*1/2*1/2 *2=1/4..
ans E
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campus1995
The probability of having a girl is identical to the probability of having a boy. In a family with three children, what is the probability that all the children are of the same gender?

(A) 1/8
(B) 1/6
(C) 1/3
(D) 1/5
(E) 1/4

ALTERNATE METHOD

Every Child has 2 possibilities of belonging to one of the two genders (i.e. boy or girl)

Total Out comes of Three Children to have any gender = 2 x 2 x 2 = 8

Favorable Outcomes of All children to have Same Gender = Either all boys (1case) or All girls(1 case) = 2

Probability = favorable Outcomes / Total Outcomes = 2/8 = 1/4

Answer: Option E
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P(G)=1/2 and P(B)=1/2 and the event can take place in 2 ways : GGG+BBB or BBB+GGG = (1/2)^3*2
= 1/8 *2 = 1/4. Am i correct in my understanding of the problem??
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P(Girl) = P(Boy) = \(\frac{1}{2}\)

Family with three children, what is the probability that all the children are of the same gender: All three are boys or All three are girls:

=> \((\frac{1}{2} * \frac{1}{2} * \frac{1}{2})\) + \((\frac{1}{2} * \frac{1}{2} * \frac{1}{2})\)

=> \(\frac{1 }{ 8}\) + \(\frac{1 }{ 8}\) = \(\frac{2 }{ 8}\)

=> \(\frac{1}{4}\)

Answer E
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The probability of having a girl is identical to the probability of having a boy. In a family with three children, what is the probability that all the children are of the same gender?

Let the probability of having a girl = P(G)
Let the probability of having a girl = P(B)

According to given question => P(G)+P(B)=1 (P(G)=P(B))
=> 2P(G) = 1
=> P(G) = 1/2 = P(B)

Now,
Probability of 3 boys = probability of 3 girls = (1/2)*(1/2)*(1/2)=1/8
Probability of 3 children of same gender = Probability of 3 boys + probability of 3 girls = 1/8 + 1/8 = 1/4

Hence E
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Just verbalize the 2 situations:3 boys or 3 girls, and fill in the probabilities for each scenario:

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