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22 Jan 2025, 07:00
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Dropdown 1: Tuesday
Dropdown 2: 23%
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
85% (02:10) correct
15%
(01:40)
wrong
based on 186
sessions
History
Date
Time
Result
Not Attempted Yet
IMPROVED VERSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/the-graph-ab ... 43826.html
The quality control team at a tire manufacturing factory found the number of defects and acceptable tires produced in each of the 7 days of a week over a 50-week period.
From each drop-down menu, select the option that creates the most accurate statement according to the information provided.
Percentage of defects is defined as Number of defects / (Number of defects + Accepted units)*100%. Shifts worked on produced the highest percentage of defects with a value of .
download (4).png [ 26.55 KiB | Viewed 1468 times ]
The quality control team at a tire manufacturing factory found the number of defects and acceptable tires produced in each of the 7 days of a week over a 50-week period.
From each drop-down menu, select the option that creates the most accurate statement according to the information provided.
Percentage of defects is defined as Number of defects / (Number of defects + Accepted units)*100%. Shifts worked on produced the highest percentage of defects with a value of .
Attachment:
download (4).png [ 26.55 KiB | Viewed 1468 times ]
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Official Answer
Dropdown 1: Tuesday
Dropdown 2: 23%
22 Jan 2025, 07:57
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We are looking for highest proportion of D/(D+A) { D= Defects, A= Accepted}
To look for the candidates, we look for highest D/A, these have higher probability of having highest percentage of defective tires.
Now on cursory viewing, we get two candidates: Friday (15/50) and Tuesday (15/100).
Clearly, highest defectives % = 15/(15+50) = 23.07%
To look for the candidates, we look for highest D/A, these have higher probability of having highest percentage of defective tires.
Now on cursory viewing, we get two candidates: Friday (15/50) and Tuesday (15/100).
Clearly, highest defectives % = 15/(15+50) = 23.07%
23 Jan 2025, 07:00
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1. The question asks us to find the day with the largest percentage of defects and its value.
2. Before making any calculations, notice how Tuesday has the smallest number of accepted units and the largest number of defects. This means that it has the largest percentage of defects.
3. Now let's calculate its value. \(Percentage \ of \ defects = \frac{Number \ of \ defects}{Number \ of \ defects + Accepted \ units} * 100\% = \frac{15}{15 + 50} * 100\% \approx 23.08\%\), which is closest to the answer choice 23%.
4. Our answer will be: D1 - Tuesday and D2 - 23%.
2. Before making any calculations, notice how Tuesday has the smallest number of accepted units and the largest number of defects. This means that it has the largest percentage of defects.
3. Now let's calculate its value. \(Percentage \ of \ defects = \frac{Number \ of \ defects}{Number \ of \ defects + Accepted \ units} * 100\% = \frac{15}{15 + 50} * 100\% \approx 23.08\%\), which is closest to the answer choice 23%.
4. Our answer will be: D1 - Tuesday and D2 - 23%.
