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The rectangular garden with dimensions x feet by y feet, is surrounded

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The rectangular garden with dimensions x feet by y feet, is surrounded  [#permalink]

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New post 31 Jul 2019, 01:04
1
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A
B
C
D
E

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  15% (low)

Question Stats:

75% (01:39) correct 25% (01:34) wrong based on 44 sessions

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The rectangular garden with dimensions x feet by y feet, is surrounded  [#permalink]

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New post Updated on: 31 Jul 2019, 05:03
Bunuel wrote:
The rectangular garden with dimensions x feet by y feet, is surrounded by a walkway 2 feet wide. Which of the following represents the area of the walkway, in square feet?

A. 2x + 2y + 4
B. 2x + 2y +16
C. 4x - 4y + 8
D. 4x + 4y + 16
E. 4x + 4y + 32


area of the walkway= area of larger rectangle - area of the inner rectangle
= (x+4) (y+4) - xy

Originally posted by Mahi2409 on 31 Jul 2019, 04:34.
Last edited by Mahi2409 on 31 Jul 2019, 05:03, edited 2 times in total.
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Re: The rectangular garden with dimensions x feet by y feet, is surrounded  [#permalink]

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New post 31 Jul 2019, 04:56
Bunuel wrote:
The rectangular garden with dimensions x feet by y feet, is surrounded by a walkway 2 feet wide. Which of the following represents the area of the walkway, in square feet?

A. 2x + 2y + 4
B. 2x + 2y +16
C. 4x - 4y + 8
D. 4x + 4y + 16
E. 4x + 4y + 32


new length ; (x+4) and width ( y+4)
original x &y
so area of walk way ; ( x+4)*(y+4) -xy
4x + 4y + 16
IMO D
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Re: The rectangular garden with dimensions x feet by y feet, is surrounded  [#permalink]

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New post 31 Jul 2019, 05:10
Bunuel wrote:
The rectangular garden with dimensions x feet by y feet, is surrounded by a walkway 2 feet wide. Which of the following represents the area of the walkway, in square feet?

A. 2x + 2y + 4
B. 2x + 2y +16
C. 4x - 4y + 8
D. 4x + 4y + 16
E. 4x + 4y + 32


Given: The rectangular garden with dimensions x feet by y feet, is surrounded by a walkway 2 feet wide.

Asked: Which of the following represents the area of the walkway, in square feet?

Area of walkway = (x+4)(y+4) - xy
= 4x+4y+16

IOM D
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Re: The rectangular garden with dimensions x feet by y feet, is surrounded  [#permalink]

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New post 31 Jul 2019, 10:43
This is a simple question on Mensuration. You just have to draw the figure right and the answer’s gonna be right in front of you to pick.

So, let us draw a figure to represent the situation described in the question.

Attachment:
31st July 2019 - Reply 3.JPG
31st July 2019 - Reply 3.JPG [ 22.55 KiB | Viewed 290 times ]


From the diagram,

Area of the garden (the inner rectangle) = (x*y) square feet.

Area of the outer rectangle = [(x+4) * (y+4)] square feet.

So, area of the walkway = Area of the outer rectangle – Area of the inner rectangle

= (x*y) + 4x + 4y + 16 – (x*y)

= 4x + 4y + 16.

The correct answer option is D.

Hope this helps!
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Re: The rectangular garden with dimensions x feet by y feet, is surrounded  [#permalink]

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New post 05 Aug 2019, 17:21
Bunuel wrote:
The rectangular garden with dimensions x feet by y feet, is surrounded by a walkway 2 feet wide. Which of the following represents the area of the walkway, in square feet?

A. 2x + 2y + 4
B. 2x + 2y +16
C. 4x - 4y + 8
D. 4x + 4y + 16
E. 4x + 4y + 32


The area of the garden is xy square feet, and the area of the garden plus the walkway is (x + 4)(y + 4) square feet. Therefore, the area of the walkway, in square feet, is:

(x + 4)(y + 4) - xy = xy + 4y + 4x + 16 - xy = 4x + 4x + 16

Answer: D
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Re: The rectangular garden with dimensions x feet by y feet, is surrounded   [#permalink] 05 Aug 2019, 17:21
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