GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 19 Feb 2019, 19:17

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
  • Free GMAT Prep Hour

     February 20, 2019

     February 20, 2019

     08:00 PM EST

     09:00 PM EST

    Strategies and techniques for approaching featured GMAT topics. Wednesday, February 20th at 8 PM EST
  • Online GMAT boot camp for FREE

     February 21, 2019

     February 21, 2019

     10:00 PM PST

     11:00 PM PST

    Kick off your 2019 GMAT prep with a free 7-day boot camp that includes free online lessons, webinars, and a full GMAT course access. Limited for the first 99 registrants! Feb. 21st until the 27th.

The sides of a right triangle are consecutive even integers, and the l

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Senior Manager
Senior Manager
User avatar
Joined: 12 Aug 2015
Posts: 283
Concentration: General Management, Operations
GMAT 1: 640 Q40 V37
GMAT 2: 650 Q43 V36
GMAT 3: 600 Q47 V27
GPA: 3.3
WE: Management Consulting (Consulting)
The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 12 Sep 2015, 22:49
2
2
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

69% (01:35) correct 31% (01:38) wrong based on 135 sessions

HideShow timer Statistics

The sides of a right triangle are consecutive even integers, and the length of the longest side is p. Which of the following equations could be used to find p?

A. (p–4)^2=p^2–(p−2)^2
B. (p–2)^2=(p–4)–p^2
C. p^2+4^2+2^2=6^2
D. (p–2)^2=p^2–(p−1)^2
E. (p+2)^2+(p+4)^2=p^2

_________________

KUDO me plenty

Intern
Intern
avatar
Joined: 26 Aug 2014
Posts: 46
GMAT 1: 650 Q49 V30
GMAT 2: 650 Q49 V31
WE: Programming (Computer Software)
Re: The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 13 Sep 2015, 00:41
1
The sides are consecutive EVEN integers.
So, if longest side has a length of p, the other two sides will be (p-2) and (p-4)
And using the Pythagorean Theorem, we get: p^2 = (p-2)^2 + (p-4)^2

Ans: A
Manager
Manager
User avatar
S
Status: Math Tutor
Joined: 12 Aug 2017
Posts: 73
GMAT 1: 750 Q50 V42
WE: Education (Education)
Re: The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 12 Aug 2017, 10:11
If sides are three consecutive even integers, the right triangle in talk can have sides 6,8,10 where value of largest side p=10
thus working on all options
A - (10-4)^2 = 10^2 - (10-2)^2 / 6^2 = 10^2 - 8^2 which is true
B - (10-2)^2 = (10-4)^2 - 10^2 / 8^2 = 6^2 - 10^2which is false
C - 10^2 + 4^2 + 2^2 = 6^2 which is false
D - (10-2)^2 = 10^2 - (10-1)^2 / 8^2 = 10^2 - 9^2which is false
E - (10+2)^2 + (10+4)^2 = 10^2 / 12^2 + 14^2 = 10^2which is false
Thus answer is option A
_________________

Abhishek Parikh
Math Tutor
Whatsapp- +919983944321
Mobile- +971568653827
Website: http://www.holamaven.com

Intern
Intern
avatar
B
Joined: 11 Mar 2015
Posts: 34
The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 12 Aug 2017, 21:27
The sides of a right triangle are consecutive even integer and the longest side is P. So, other sides are p-2 & p-4. Using Pythagorean theory p^2=(p-2)^2+(p-4)^2 , => (p-4)^2=p^2-(p-2)^2.
Answer is A.
CEO
CEO
User avatar
P
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2788
Location: India
GMAT: INSIGHT
Schools: Darden '21
WE: Education (Education)
Reviews Badge
Re: The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 06 Sep 2018, 03:48
shasadou wrote:
The sides of a right triangle are consecutive even integers, and the length of the longest side is p. Which of the following equations could be used to find p?

A. (p–4)^2=p^2–(p−2)^2
B. (p–2)^2=(p–4)–p^2
C. p^2+4^2+2^2=6^2
D. (p–2)^2=p^2–(p−1)^2
E. (p+2)^2+(p+4)^2=p^2


One can use the wisdom for GMAT that GMAT uses only specific cases of right angle triangles 3-4-5 being the most frequently used pythagorean triplet

Here three consecutive even integers will be second multiple of 3-4-5 i.e. 6-8-10

As give, p = 10
p-2 = 8
p-4 = 6

Now check options

Option A: \((p–4)^2=p^2–(p−2)^2\) i.e. \(6^2 = 10^2 - 8^2\) fits well hence

Answer: Option A
_________________

Prosper!!!
GMATinsight
Bhoopendra Singh and Dr.Sushma Jha
e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772
Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi
http://www.GMATinsight.com/testimonials.html

ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION

Board of Directors
User avatar
P
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4383
Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)
GMAT ToolKit User Premium Member CAT Tests
Re: The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 06 Sep 2018, 06:15
shasadou wrote:
The sides of a right triangle are consecutive even integers, and the length of the longest side is p. Which of the following equations could be used to find p?

A. (p–4)^2=p^2–(p−2)^2
B. (p–2)^2=(p–4)–p^2
C. p^2+4^2+2^2=6^2
D. (p–2)^2=p^2–(p−1)^2
E. (p+2)^2+(p+4)^2=p^2


\(Base < Altitude < Hypotenuse\)

So, \(p - 4 < p - 2 < p\)

Now, \(p^2 = ( p - 2 )^2 + ( p - 4 )^2\) { Pythagorus Theorem }

Thus, Answer must be (A)
_________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )

CEO
CEO
User avatar
D
Joined: 11 Sep 2015
Posts: 3435
Location: Canada
Re: The sides of a right triangle are consecutive even integers, and the l  [#permalink]

Show Tags

New post 07 Feb 2019, 11:38
Top Contributor
shasadou wrote:
The sides of a right triangle are consecutive even integers, and the length of the longest side is p. Which of the following equations could be used to find p?

A. (p–4)^2=p^2–(p−2)^2
B. (p–2)^2=(p–4)–p^2
C. p^2+4^2+2^2=6^2
D. (p–2)^2=p^2–(p−1)^2
E. (p+2)^2+(p+4)^2=p^2


GIVEN: p = length of the longest side

Since the side lengths are consecutive even integers, we can say:
p - 2 = length of the 2nd longest side
p - 4 = length of the shortest side

NOTE: The longest side is the HYPOTENUSE.
So, p = length of the HYPOTENUSE
And p - 2 = length of one leg of the right triangle
And p - 4 = length of the other leg of the right triangle

By the Pythagorean Theorem, we can write: (p - 2)² + (p - 4)² = p²
Check the answers . . . not there! Looks like we need to fiddle with the equation to make it look like on of the answer choices.

Take: (p - 2)² + (p - 4)² = p²
Subtract (p - 2)² from both sides to get: (p - 4)² = p² - (p - 2)² . . . BINGO!!

Answer: A

Cheers,
Brent
_________________

Test confidently with gmatprepnow.com
Image

GMAT Club Bot
Re: The sides of a right triangle are consecutive even integers, and the l   [#permalink] 07 Feb 2019, 11:38
Display posts from previous: Sort by

The sides of a right triangle are consecutive even integers, and the l

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.