Last visit was: 26 Apr 2026, 15:32 It is currently 26 Apr 2026, 15:32
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
505-555 (Easy)|   Geometry|                           
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 26 Apr 2026
Posts: 6,977
Own Kudos:
16,922
 [1]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,977
Kudos: 16,922
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,054
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,054
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Jainam24
Joined: 30 Dec 2020
Last visit: 18 Dec 2022
Posts: 96
Own Kudos:
59
 [1]
Given Kudos: 332
Status:Enjoy the journey, love the process
Location: India
Posts: 96
Kudos: 59
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
avatar
dungltp9
Joined: 27 Aug 2021
Last visit: 05 Nov 2021
Posts: 5
Own Kudos:
Given Kudos: 4
Location: Viet Nam
Concentration: Accounting, General Management
Posts: 5
Kudos: 14
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can someone please explain for me why we don't subtract the smaller rectangle when calculating the enlarged lot area?

Thank you.
User avatar
Abhishek009
User avatar
Board of Directors
Joined: 11 Jun 2011
Last visit: 17 Dec 2025
Posts: 5,902
Own Kudos:
Given Kudos: 463
Status:QA & VA Forum Moderator
Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 5,902
Kudos: 5,456
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

The smaller rectangle in the figure above represents the original size of a parking lot before its length and width were each extended by w feet to make the larger rectangular lot shown. If the area of the enlarged lot is twice the area of the original lot, what is the value of w?

(A) 25
(B) 50
(C) 75
(D) 100
(E) 200



Attachment:
2015-10-16_0901.png
Original area was \(100*150 = 15000\)

Increased Area is \((100 + w)(150 + w) = 30000\)

Check the options \(30000 = 150 * 200\), hence Answer must be (B)
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,054
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,054
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
dungltp9
Can someone please explain for me why we don't subtract the smaller rectangle when calculating the enlarged lot area?

Thank you.

Hi dungltp9,

The prompt refers specifically to the "larger RECTANGULAR lot shown." If you remove the smaller rectangle from your calculation, then what's left would NOT be a rectangle.

GMAT assassins aren't born, they're made,
Rich
User avatar
khera
Joined: 29 Oct 2020
Last visit: 19 Dec 2022
Posts: 26
Own Kudos:
Given Kudos: 132
Posts: 26
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
From the given information it follows that
(100 + w)(150 + w) = 2(100)(150), or
(100 + w)(150 + w) = (200)(150). This is a
quadratic equation that can be solved by several
methods. One method is by inspection. The left
side is clearly equal to the right side when w =50.
Another method is by factoring. Expanding the left
side gives (100)(150) + 250w + v} =(200)(150), or
v} + 250w - (100)(150) = 0. Factoring the left
side gives ( w - 50)( w + 300) = 0, which has
w =50 as its only positive solution.
The correct answer is B
avatar
alpstinger
Joined: 12 Aug 2021
Last visit: 07 Feb 2023
Posts: 23
Own Kudos:
Given Kudos: 111
Location: India
Schools: ISB '23
GMAT 1: 660 Q44 V37
GMAT 2: 680 Q48 V35
GMAT 3: 690 Q47 V37
GMAT 4: 720 Q49 V39
Schools: ISB '23
GMAT 4: 720 Q49 V39
Posts: 23
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
2 x 100 x 150 = (100 + w) x (150 + w)
200 x 150 = (100 + w) x (150 + w)

Put w = 50, and voila solved:
200 x 150 = (100 + 50) x (150 + 50)
User avatar
Anubhav21
Joined: 14 Mar 2022
Last visit: 26 Feb 2023
Posts: 18
Own Kudos:
Given Kudos: 13
Location: India
Posts: 18
Kudos: 28
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel JeffTargetTestPrep I factorized the equation w^2 + 250w - 15000 = 0 into w^2 + 150w + 100w + 15000 = 0 instead of w^2 + 300w - 50w - 15000 = 0
and got w = -150 or 100. Where did I go wrong?
User avatar
egmat
User avatar
e-GMAT Representative
Joined: 02 Nov 2011
Last visit: 24 Apr 2026
Posts: 5,632
Own Kudos:
Given Kudos: 707
GMAT Date: 08-19-2020
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 5,632
Kudos: 33,435
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Anubhav21
Bunuel JeffTargetTestPrep I factorized the equation w^2 + 250w - 15000 = 0 into w^2 + 150w + 100w + 15000 = 0 instead of w^2 + 300w - 50w - 15000 = 0
and got w = -150 or 100. Where did I go wrong?

Hello Anubhav21,

I see you are not comfortable with solving quadratic equations. So, let me first explain the general way of splitting the X-coefficient to solve quadratic equations and then we shall solve this question.

“SPLITTING THE X-coefficient METHOD” TO SOLVE QUADRATIC EQUATION

The steps to solve a quadratic equation under this method involve:

  • Write the quadratic equation in the standard form, ax\(^2\) + bx + c = 0.
  • Identify the values of a, b and c.
    1. Example: In 2x\(^2\) + 5x + 2 = 0, a = 2, b = 5 and c = 2.
    2. Example: 2x\(^2\) -5x + 2 = 0. Here, a = 2, b = -5 and c = 2.
  • To simplify the quadratic equation, the coefficient of x (b) must be split into two terms b\(_1\) and b\(_2\), such that:
    1. b\(_1\) + b\(_2\) = b and
    2. b\(_1\)b\(_2\) = ac.
  • Now, the equation will have changed to ax\(^2\) + b\(_1\)x + b\(_2\)x + c = 0. Finally, we take “pair-wise common factors out” to get a completely factored form of the quadratic equation. (Read the explanation below on your equation to best understand this)

APPLYING THIS METHOD ON THE QUESTION IN HAND


In the solution to this question, we arrived at the quadratic equation: w\(^2\) + 250w – 15000 = 0.

Let me first discuss what you did incorrectly and then show the correct simplification.

  • You wrote w\(^2\) + 250w – 15000 as w\(^2\) + 150w + 100w – 15000.
    • So, you took b\(_1\) = 150 and b\(_2\) = 100.
    • Now, although the sum of 150 and 100 correctly gives us 250 (= b), their product does NOT give -15000 (= ac) as required.
  • You most likely missed the sign that the constant term came with.
    • In this equation, a = 1 and c = - 15000. Hence, product of a and c (ac) = -15000
  • To do this correctly, b (=250) had to be split such that product of b\(_1\) and b\(_2\) would be -15000 and not 15000.
    • Another try should give you that b can be split into 300 and -50.

Hence, correct split of equation w\(^2\) + 250w – 15000 = 0 is w\(^2\) + 300w -250w – 15000 = 0.

Now, continue solving the question. Reach back to us if you still have any doubt. 😊


Hope this helps!

Best Regards,
Ashish Arora
Quant Expert, e-GMAT
User avatar
huongvo277
Joined: 22 Feb 2024
Last visit: 01 Dec 2024
Posts: 5
Own Kudos:
Given Kudos: 254
Posts: 5
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post

The smaller rectangle in the figure above represents the original size of a parking lot before its length and width were each extended by w feet to make the larger rectangular lot shown. If the area of the enlarged lot is twice the area of the original lot, what is the value of w?


\(100 * 150 = 15,000\)

\(15,000 * 2 = 30,000\)

\((w+100)(w+150) = 30,000\)

\(w^{2}+250w+15,000 = 30,000\)

\(w^{2}+250w-15,000 = 0\)

\((w+300)(w-50) = 0\)

\(w=-300\)

\(w=50\)

Answer B
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,991
Own Kudos:
Posts: 38,991
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
   1   2 
Moderators:
Math Expert
109910 posts
Tuck School Moderator
852 posts