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Manager  G
Joined: 01 Nov 2017
Posts: 67
Location: India
The smallest integer n for which 4^n > 17^19 holds, is closest to  [#permalink]

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Difficulty:   25% (medium)

Question Stats: 74% (01:26) correct 26% (01:35) wrong based on 102 sessions

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The smallest integer n for which $$4^n$$ > $$17^{19}$$ holds, is closest to

(a) 31
(b) 33
(c) 35
(d) 37
(e) 39

Source: testbook.com

Originally posted by raghavrf on 23 Feb 2019, 05:09.
Last edited by u1983 on 23 Feb 2019, 19:30, edited 2 times in total.
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NUS School Moderator V
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Re: The smallest integer n for which 4^n > 17^19 holds, is closest to  [#permalink]

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since 17 is close to 16. $$17^{19}$$ is approximately = $$16^{19}$$ = $$4^{2(19)}$$ = $$4^{38}$$
If $$4^n$$ has to be greater than $$17^{19}$$, n has to greater than 38, hence n = 39.

E is the answer.
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Senior Manager  S
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The smallest integer n for which 4^n > 17^19 holds, is closest to  [#permalink]

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$$2^{2n}>17^{19} = (2^{4}+1)^{19}$$

$$2^{2n}>2^{76}$$

n must be more than 38.

E

Originally posted by jfranciscocuencag on 23 Feb 2019, 14:43.
Last edited by jfranciscocuencag on 18 Apr 2019, 18:36, edited 2 times in total.
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Joined: 24 Aug 2016
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GMAT 1: 540 Q49 V16 GMAT 2: 680 Q49 V33 The smallest integer n for which 4^n > 17^19 holds, is closest to  [#permalink]

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$$17^{19}$$ > $$16^{19}$$ or $$17^{19}$$ > $$4^{38}$$
So for the inequality $$4^n$$ > $$17^{19}$$ to hold true, n must be GT 38
Hence n is closest to 39 (out of the given choices )
Ans E
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Re: The smallest integer n for which 4^n > 17^19 holds, is closest to  [#permalink]

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raghavrf wrote:
The smallest integer n for which $$4^n$$ > $$17^{19}$$ holds, is closest to

(a) 31
(b) 33
(c) 35
(d) 37
(e) 39

Source: testbook.com

$$4^n$$ > [m]17^{19}[/m
4^n>(16)^19+1^19
4^n>4^38+1^19
n>=38
n=39
IMOE Re: The smallest integer n for which 4^n > 17^19 holds, is closest to   [#permalink] 03 May 2019, 22:07
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