Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2001:30 PM EST
-02:30 PM IST
Learn how Kamakshi achieved a GMAT 675 with an impressive 96th %ile in Data Insights. Discover the unique methods and exam strategies that helped her excel in DI along with other sections for a balanced and high score.
Nov 2206:30 AM PST
-08:30 AM PST
Let’s dive deep into advanced CR to ace GMAT Focus! Join this webinar to unlock the secrets to conquering Boldface and Paradox questions with expert insights and strategies. Elevate your skills and boost your GMAT Verbal Score now!
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2407:00 PM PST
-08:00 PM PST
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
72% (02:54) correct
28%
(02:57)
wrong
based on 833
sessions
History
Date
Time
Result
Not Attempted Yet
A steamer takes 4 hours and 30 minutes to travel from Town A to Town B when traveling upstream against the current. However, it only takes the steamer 3 hours to travel from Town B to Town A when traveling downstream with the current. Assuming the current flows at a constant speed, how long will it take a raft, floating downstream at the speed of the current, to travel from Town B to Town A ?
A. 10 hours
B. 12 hours
C. 15 hours
D. 18 hours
E. 20 hours
A. 10 hours
B. 12 hours
C. 15 hours
D. 18 hours
E. 20 hours
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
22 Feb 2014, 03:09
Kudos
Bookmarks
prasannajeet
Downstream speed = steamer's speed + current's speed
Upstream speed = steamer's speed - current's speed
Downstream speed - Upstream speed = (steamer's speed + current's speed) - (steamer's speed - current's speed) = 2*(current's speed). Hence to get (current's speed) we need to divide (Downstream speed - Upstream speed) by 2.
Hope it's clear.
Official Solution:
A steamer takes 4 hours and 30 minutes to travel from Town A to Town B when traveling upstream against the current. However, it only takes the steamer 3 hours to travel from Town B to Town A when traveling downstream with the current. Assuming the current flows at a constant speed, how long will it take a raft, floating downstream at the speed of the current, to travel from Town B to Town A ?
A. 10 hours
B. 12 hours
C. 15 hours
D. 18 hours
E. 20 hours
Assume the speed of the steamer in still water is \(s\) and the speed of the current to is \(c\).
When traveling upstream against the current, the steamer's speed is \(s - c\), and in 4.5 hours it covers a distance of \(4.5(s - c)\).
When traveling downstream with the current, the steamer's speed is \(s + c\), and in 3 hours it covers a distance of \(3(s + c)\).
Since both distances represent the distance between Towns A and B, we can equate them: \(4.5(s - c)=3(s + c)\), which gives \(s = 5c\). To express the distance in terms of only one unknown, substitute \(s = 5c\) in either of the above equations, to get \(3(s + c)=18c\).
To determine how long a raft, floating downstream at the speed of the current, will take to travel from Town B to Town A, we divide the distance between the towns by the speed of the raft: \(\frac{distance}{rate}=\frac{18c}{c}=18\) hours.
Answer: D
Hope it helps.
A steamer takes 4 hours and 30 minutes to travel from Town A to Town B when traveling upstream against the current. However, it only takes the steamer 3 hours to travel from Town B to Town A when traveling downstream with the current. Assuming the current flows at a constant speed, how long will it take a raft, floating downstream at the speed of the current, to travel from Town B to Town A ?
A. 10 hours
B. 12 hours
C. 15 hours
D. 18 hours
E. 20 hours
Assume the speed of the steamer in still water is \(s\) and the speed of the current to is \(c\).
When traveling upstream against the current, the steamer's speed is \(s - c\), and in 4.5 hours it covers a distance of \(4.5(s - c)\).
When traveling downstream with the current, the steamer's speed is \(s + c\), and in 3 hours it covers a distance of \(3(s + c)\).
Since both distances represent the distance between Towns A and B, we can equate them: \(4.5(s - c)=3(s + c)\), which gives \(s = 5c\). To express the distance in terms of only one unknown, substitute \(s = 5c\) in either of the above equations, to get \(3(s + c)=18c\).
To determine how long a raft, floating downstream at the speed of the current, will take to travel from Town B to Town A, we divide the distance between the towns by the speed of the raft: \(\frac{distance}{rate}=\frac{18c}{c}=18\) hours.
Answer: D
Hope it helps.
