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Bunuel
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Bunuel
1. The sum of n consecutive positive integers is 45. What is the value of n?
(1) n is even
(2) n < 9

1. n could be 2 or 6 or 10
a + a+1 = 45
a = 22
n = 2

a + a+1 + a+2 + a+3 + a+4 + a+5 = 45
a = 5
n = 6

2. n could be 2, 3, 5 or 6

1&2: n could be 2 or 6. E.


Bunuel
10. The sum of n consecutive positive integers is 45. What is the value of n?
(1) n is even
(2) n >= 9

1. n could be 2 or 6 or 10

n = 2:
a + a+1 = 45
a = 22

n = 6:
a + a+1 + a+2 + a+3 + a+4 + a+5 = 45
a = 5

2. n could be 9 or 10 or 14 or 15 or 18 & so on...

1&2: n could be 10 or 14 or 18. E.
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Bunuel

TIP: many of these problems act in GMAT zone, so beware of ZIP trap.

1. The sum of n consecutive positive integers is 45. What is the value of n?
(1) n is even
(2) n < 9

2. Is a product of three integers XYZ a prime?
(1) X=-Y
(2) Z=1

What is the ZIP trap?

Q1)
Statement 1) n = 2,4,6 etc
n = 2 => x+(x+1)=45 => x=22 (works)
n = 4 => x+(x+1)+(x+2)+(x+3)=45 => 4x+6=45 => x=39/4 (doesn't work)
n = 6 => Take above equation+(x+4)+(x+5) => 6x+15=45 => x=5 (works)
Not suff.
Statement 2) n < 9. This is proven insufficient from the working above since both n=2 and n=6 n<9.
1 and 2 together still prove insufficient due to above working.

ANS = E.

Q2)
Statement 1) X=-Y
This means Z needs to be negative and for XYZ to have a chance of being prime. Z can be anything.
Insufficient.
Statement 2) Z=1
X and Y could be anything such as 2 and 3 (non prime multiple) or 1 and 2 (prime).
Insufficient.
1 and 2 Together) Z = 1. X=-Y
1*Y*(-Y) = -Y^2 which cannot be prime as it is negative.

ANS = C

Edited: Got the right working but wrote E instead of C. I gotta stop doing that :(
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Bunuel
2. Is a product of three integers XYZ a prime?

(1) X=-Y
(2) Z=1

(1) If x=-y = 2 and z = -1, yes. Otherwise, no..
(2) If z = 1, x could be 2 and y = 1. xyz is a price. If something else, no.

From 1 and 2: x = -y and z = 1, xyz is always a -ve integer, which cannot be a prime....C.
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Bunuel

4. Is y – x positive?
(1) y > 0
(2) x = 1 – y

Statement 1) y>0 Not suff, X could be anything larger or smaller than X.
Statement 2) x=1-y
x+y=1
Let x=3 and y=-2 then y-x < 0.
But if x=1/4 and y=3/4 then y-x >0
Not suff.

1 and 2 together)
From the example above we have:
if x=1/4 and y=3/4 then y-x >0
but if we flip it around:
if x=3/4 and y=1/4 then y-x <0
not suff.

ANS = E
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Bunuel

6. If M and N are integers, is (10^M + N)/3 an integer?
1. N = 5
2. MN is even

Statement 1) N=5
If M>=0 then it is always divisible by 3. Since the number will always consist of 1, trailing 0's and a 5. Of which the sum of digits =6 which is the rule for divisibility by 3.
If M<0 then the equation is not divisble by 3. For example if M=-1.
Insufficient

Statement 2) MN is even. Again this means M could still be negative so insufficient. For example M could be -1 and N could be 2 which is not divisible by 3. Or n=5 but m=-2 which is not.

Statements together) Still insuff. m=2 n=5 works. But m=-2 n=5 doesn't work.

ANS = E
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Bunuel

7. If b, c, and d are constants and x^2 + bx + c = (x + d)^2 for all values of x, what is the value of c?
(1) d = 3
(2) b = 6

Expanding it out we get :
x^2 + bx + c = x^2 + 2dx + d^2

Statement 1) d = 3
d^2 = c = 9
Suff.
Statement 2) b=6
b=6=2d
d=3
d^2=c=9
Suff

ANS = D
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Bunuel

9. Is the integer n odd
(1) n is divisible by 3
(2) 2n is divisible by twice as many positive integers as n

10. The sum of n consecutive positive integers is 45. What is the value of n?
(1) n is odd
(2) n >= 9


Q9)
Statement 1)
N is a multiple of 3. N could be 3 or 6.
Insufficient.
Statement 2)
I am not sure how to prove this except by examples:
Example 1:n=9 factors={1,3,9}, 2n=18 factors={1,2,3,6,9,18}
N is odd is true.
Example 2:n=6 factors={1,2,3,6} 2n=12 factors={1,2,3,4,6,12} Does not have twice as many factors.
Example 3: n=3 factors={1,3} 2n=6 factors={1,2,3,6}
N is odd is true.

ANS = B

Q10)
Statement 1) N is odd.
N could be 1. 45
N could also be 3. x+(x+1)+(x+2)=45 => 3x=42 x=14
Insufficient.
Statement 2) N>=9
Let n=9.
9x+8+7+6+5+4+3+2+1=45 => 9x+36=45 => 9x=9 x=1
we cannot use n>10 because adding anymore positive integers means sum > 45.
Sufficient.

ANS = B
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Bunuel

3. Multiplication of the two digit numbers wx and cx, where w,x and c are unique non-zero digits, the product is a three digit number. What is w+c-x?
(1) The three digits of the product are all the same and different from w c and x.
(2) x and w+c are odd numbers.


WX x CX = IJK

1.) I,J,K are the same and not equal to W,C or X.

so 3 digit numbers with all digit same are 111,222,...., 999.

basically multiples of 111 (37x3).

so we get 1 number = 37

conditions the second number has to meet = last digit = 7, multiple of 3, double digit.

so we get 27.

27 x 37 = 999

So suff.

2.) x and w+c are odd.

this gives multiple values.

So A.
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Bunuel

5. If a and b are integers, and a not= b, is |a|b > 0?
(1) |a^b| > 0
(2) |a|^b is a non-zero integer

|a|b > 0?

|a| is always +ve. So we need to know if b is +ve or -ve.

1.) mod of any number is +ve. Insuff.

2.) |a|^b is an integer.

we know a and b are integers.

so |a| is a +ve integer.

any +ve integer raised to a -ve integer will give us a fraction.

e.g. 4 ^ -3 = 1/ (4^3)

which will never be an integer.

so for |a|^b to be an integer b has to be +ve.

So its suff.

So B.
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Bunuel

8. If x and y are non-zero integers and |x| + |y| = 32, what is xy?
(1) -4x - 12y = 0
(2) |x| - |y| = 16

1.) -4x = 12y
or -x = 3y

so we get x and y to be = 24,-8 or -24,8

xy = -192 in both cases

so suff.

2.) |x| - |y| = 16

we can get |x| and |y|.

but the signs of x and y cannot be determined. So insuff.

IMO A.
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Bunuel

3. Multiplication of the two digit numbers wx and cx, where w,x and c are unique non-zero digits, the product is a three digit number. What is w+c-x?
(1) The three digits of the product are all the same and different from w c and x.
(2) x and w+c are odd numbers.


WX x CX = IJK

1.) I,J,K are the same and not equal to W,C or X.

so 3 digit numbers with all digit same are 111,222,...., 999.

basically multiples of 111 (37x3).

so we get 1 number = 37

conditions the second number has to meet = last digit = 7, multiple of 3, double digit.

so we get 27.

27 x 37 = 999

So suff.

2.) x and w+c are odd.

this gives multiple values.

So A.

Though answer is right and one number indeed is 37, but it was not the only possibility for it. So you got the right answer with right numbers, but missed one case to consider.
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5. If a and b are integers, and a not= b, is |a|b > 0?
(1) |a^b| > 0
(2) |a|^b is a non-zero integer

Basically the question asks, is b>0?

stmt1: b can be -ve or +ve or 0. Insuff.
stmt2: b can be +ve or 0. Insuff.
Combining, b can be +ve or 0. Insuff.

E.
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Bunuel
Yes and about the ZIP trap:

GMAT likes to act in the zone -1<=x<=1. So I always ask myself:

Did I assumed, with no ground for it, that variable can not be Zero? Check 0!
Did I assumed, with no ground for it, that variable is an Integer? Check fractions!
Did I assumed, with no ground for it, that variable is Positive? Check negative values!

I called it ZIP trap. Helps me a lot especially with number property problems.

Thats cool. 8-)

You can say PINZF (or better) trap as well:

P = positive
I = integer
N = negative
Z = zero
F = fraction
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Bunuel
10. The sum of n consecutive positive integers is 45. What is the value of n?
(1) n is even
(2) n >= 9

1. n could be 2 or 6 or 10

n = 2:
a + a+1 = 45
a = 22

n = 6:
a + a+1 + a+2 + a+3 + a+4 + a+5 = 45
a = 5

2. n could be 9 or 10 or 14 or 15 or 18 & so on...

1&2: n could be 10 or 14 or 18. E.

Did you say "consecutive positive integers"? not only "consecutive integers"?

Agree with B if "consecutive positive integers". If only "consecutive integers", B is correct.

Seems you said "consecutive positive integers"! :oops:
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Bunuel
Yes and about the ZIP trap:

GMAT likes to act in the zone -1<=x<=1. So I always ask myself:

Did I assumed, with no ground for it, that variable can not be Zero? Check 0!
Did I assumed, with no ground for it, that variable is an Integer? Check fractions!
Did I assumed, with no ground for it, that variable is Positive? Check negative values!

I called it ZIP trap. Helps me a lot especially with number property problems.

Thats cool. 8-)

You can say PINZF (or better) trap as well:

P = positive
I = integer
N = negative
Z = zero
F = fraction

Sure you can call whatever suits you, no copyright on that term, for me ZIP sounds good.)))
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Bunuel
ANSWERS:



10. The sum of n consecutive positive integers is 45. What is the value of n?
(1) n is odd
(2) n >= 9

Look at the Q 1 we changed even to odd and n<9 to n>=9

(1) not sufficient see Q1.
(2) As we have consecutive positive integers max for n is 9: 1+2+3+...+9=45. (If n>9=10 first term must be zero. and we are given that all terms are positive) So only case n=9. Sufficient.

Answer: B.

sum of n integers = (n*(n+1))/2

(n*(n+1))/2 = 45 which yields n = 9 could be the only answer :lol:

Stmt 1 and 2 (D) are both sufficient.

Does GMAT assume that we would not indulge in any formula? Just curious :roll:
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I like the concept of ZIP trap

check for 0,-ve and fractions.
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