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# The table above gives the distribution of two genetic characteristics,

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Math Expert
Joined: 02 Sep 2009
Posts: 52295
The table above gives the distribution of two genetic characteristics,  [#permalink]

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05 Feb 2018, 05:58
00:00

Difficulty:

15% (low)

Question Stats:

91% (01:19) correct 9% (01:45) wrong based on 45 sessions

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The table above gives the distribution of two genetic characteristics, X and Y, in a population of 100 subjects. What is ratio of (number of subjects having X)/(number of subjects having Y)?

(A) 7/5
(B) 1/1
(C) 5/7
(D) 7/10
(E) 1/4

Attachment:

2018-02-05_1755.png [ 28.94 KiB | Viewed 490 times ]

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Manager
Joined: 05 Dec 2016
Posts: 243
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: The table above gives the distribution of two genetic characteristics,  [#permalink]

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05 Feb 2018, 06:08
Hav X, Hav Y + Hav X, Lack Y = 25 + 10 = 35
Hav Y, Hav X + Hav y, Lack X = 25 + 25 = 50

35/50=7/10

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Re: The table above gives the distribution of two genetic characteristics,  [#permalink]

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05 Feb 2018, 06:38
Having X and Having Y = Both = 25
Having X and Lacking Y = Only X = 10
Having Y and Lacking X = Only Y = 25
Lacking X and Lacking Y = Neither = 40

Ratio of X to Y = (25 + 10)/(25 + 25) = 35/50 = 7/10

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Re: The table above gives the distribution of two genetic characteristics,  [#permalink]

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05 Feb 2018, 06:44
Bunuel wrote:

The table above gives the distribution of two genetic characteristics, X and Y, in a population of 100 subjects. What is ratio of (number of subjects having X)/(number of subjects having Y)?

(A) 7/5
(B) 1/1
(C) 5/7
(D) 7/10
(E) 1/4

Attachment:
2018-02-05_1755.png

Venn Diagram:

X only = 10 (Having X lacking Y)
Y only = 25 (Having Y Lacking X)
Both = 25 (Having X Having Y)
So Having X = 10 + 25 = 35
Having Y = 25+25 = 50
Asked $$\frac{Having X}{Having Y}$$= $$\frac{35}{50}$$=$$\frac{7}{10}$$
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Re: The table above gives the distribution of two genetic characteristics, &nbs [#permalink] 05 Feb 2018, 06:44
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