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The table above shows the number of days worked by a certain sales rep

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The table above shows the number of days worked by a certain sales rep  [#permalink]

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New post 17 Dec 2015, 10:05
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The table above shows the number of days worked by a certain sales representative in each of three months last year. If the number of sales calls that the representative made each month was proportional to the number of days worked in that month and if the representative made a total of 168 sales calls in the three months shown, how many sales calls did the representative make in August?

(A) 50
(B) 51
(C) 56
(D) 57
(E) 60


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Re: The table above shows the number of days worked by a certain sales rep  [#permalink]

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New post 17 Dec 2015, 21:08
Sash143 wrote:
The table above shows the number of days worked by a certain sales representative in each of three months last year. If the number of sales calls that the representative made each month was proportional to the number of days worked in that month and if the representative made a total of 168 sales calls in the three months shown, how many sales calls did the representative make in August?
(A) 50
(B) 51
(C) 56
(D) 57
(E) 60


We are given the ratios of calls is same as number of days..
let the common ratio be x..
so ratio of calls =20x:17x:19x..
given the sum of calls=168=20x+17x+19x
or x=3..
therefore calls in Aug=3*19=57
D
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Re: Month - June, July August Number of days worked -  [#permalink]

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New post 08 Oct 2018, 16:17
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Re: The table above shows the number of days worked by a certain sales rep  [#permalink]

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New post 15 Jun 2019, 23:29
As the number of sale calls(S) is directly proportional to the number of days worked(W)
We can write- S=k*w where k is constant

Given s= 168
W=20+17+19=56
S=k*w
168=k*56
K=3

Asked: what is S when W is 19
S=3*19=57
D

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Re: The table above shows the number of days worked by a certain sales rep   [#permalink] 15 Jun 2019, 23:29
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