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The table above shows the total sales recorded in July for the 5 sales
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05 Dec 2008, 20:31
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Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000 The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A. $30,000 B. $48,000 C. $90,000 D. $120,000 E. $140,000
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Re: The table above shows the total sales recorded in July for
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01 Feb 2012, 10:43
Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000
The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale?A. $30,000 B. $48,000 C. $90,000 D. $120,000 E. $140,000 Old sales: {Cal=190, 210, 360, Ann=450, 680}. Now, the median of a set with odd # of terms is just the middle term (when ordered in ascending /descending order). So, old median=360. We know that new median=330 and Cal's sales are still less than Ann's, hence Ann's new sales must be 330 (Ann's sales # must be reduced so that it becomes the middle term: 360 and Ann must switch places): {210, Cal, Ann=330, 360, 680}. The value of the incorrectly recorded sale is Ann's old sales  Ann's new sales = 450  330 = 120. Answer: D. Hope it's clear.
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Re: The table above shows the total sales recorded in July for the 5 sales
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06 Dec 2008, 05:21
Only Cal & Ann have the incorrect figures so $330k must be either belong to Ann or Cal
If belong to Cal, as Ann's total sales, 680k, 360k > 330k, so the median is either Ann's or 360k
Therefore 330k must be belong to Ann,
Ann 330,000 Cal 310,00



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Re: Cal Sale
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29 Apr 2011, 03:24
CAL 190,000+X DOT 210,000 ANN 450000X BOB 360,000 ED 680,000 Median is middle value if the number of terms are odd. Hence, 450000x = 330,000 x=120,000 OA. D
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Re: Cal Sale
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29 Apr 2011, 04:46
jamifahad wrote: CAL 190,000+X DOT 210,000 ANN 450000X BOB 360,000 ED 680,000
Median is middle value if the number of terms are odd.
Hence, 450000x = 330,000 x=120,000
OA. D How do you calculated that 450000  x is the median here?
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Re: Cal Sale
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29 Apr 2011, 09:06
A 4,50,000 B 3,60,000 C 1,90,000 D 2,10,000 E 6,80,000
Problem lies with sales of A & C...i.e. A' sales value 4,50,000 will have to be reduced by x and C's sales value will have to be increased by x. ( given in the problem )
After the correction/rearrangement the median value is 33,000
Keeping the other 3 sales values of B,D,E intact
?,2,10,000,3,30,000 (median),3,60,000,6,80,000
Two possibilities are there :
1.C's sales value of 1,90,000 would have been increased to 3,30,000..In that case, A's sales value becomes 3,10,000. This goes against the given information that A's sales is still higher than C.
2.So, we can conclude that A's sales value has been decreased to 3,30,000. Hence the incorrect value = 4,50,000  3,30,000 = 1,20,000
Hope I've made sense..Probably I've made it lengthy...!!!



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Re: Cal Sale
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29 Apr 2011, 09:49
ramprakash wrote: A 4,50,000 B 3,60,000 C 1,90,000 D 2,10,000 E 6,80,000
Problem lies with sales of A & C...i.e. A' sales value 4,50,000 will have to be reduced by x and C's sales value will have to be increased by x. ( given in the problem )
After the correction/rearrangement the median value is 33,000
Keeping the other 3 sales values of B,D,E intact
?,2,10,000,3,30,000 (median),3,60,000,6,80,000
Two possibilities are there :
1.C's sales value of 1,90,000 would have been increased to 3,30,000..In that case, A's sales value becomes 3,10,000. This goes against the given information that A's sales is still higher than C.
2.So, we can conclude that A's sales value has been decreased to 3,30,000. Hence the incorrect value = 4,50,000  3,30,000 = 1,20,000
Hope I've made sense..Probably I've made it lengthy...!!! Thanks...thats explains it very clearly....actually I was not able to clearly identify this scenario.
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Re: Cal Sale
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18 May 2011, 03:26
45x > 19+x
19+x , 21, 36,45x,68 median = 33 hence
45x = 33 meaning x = 12.



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Re: The table above shows the total sales recorded in July for the 5 sales
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24 Jul 2011, 21:25
snowbirdskier wrote: Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000
The table above shows the total sales recoreded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? (GMAT practice test) There are 5 values given to us and their median is 330 (Let's ignore the extra 0s). What does that mean? Say there is a list of numbers: 4, 6, 9, 12, 35 How do you get the median? It is the middle value in case you have odd number of values in increasing/decreasing order. It doesn't matter what the other values are. Median is equal to the value right in the middle. If median of a list of 5 values is 330, it means that 330 must be one of the 5 values. 2 values must be greater than 330 and 2 must be smaller than 330. Let me arrange the given list in decreasing order: Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000 680, 450, 360, 210, 190I cannot touch the other 3 values (Just the red ones (Ann's and Cal's)). Since 680 and 360 remain and are greater than 330, so my actual list should look something like this: 680, 360, 330, ....., ..... (210 occupies one of these blanks) The question now is: To whom does this 330 belong? If Ann's sales decreases from 450 to 330, Cal's sale should increase by 120 (= 450  330) i.e. Cal's actual sales should be 190 + 120 = 310. The list becomes: 680, 360, 330, 310, 210  satisfies everything. The value of the incorrectly recorded sales must have been $120,000. Could 330 belong to Cal? Then Cal's sales would have increased by 330  190 = 140 Ann's sales would have decreased by 140 to get her actual sales of 310. But it is given that Ann's sales remains higher than Cal's. Hence this is not possible.
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The table above shows the total sales recorded in July for
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01 Feb 2012, 08:01
Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000 The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A. $30,000 B. $48,000 C. $90,000 D. $120,000 E. $140,000
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Re: The table above shows the total sales recorded in July for
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01 Feb 2012, 16:20
Bunuel wrote: Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000
The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A. $30,000 B. $48,000 C. $90,000 D. $120,000 E. $140,000
Old sales: {Cal=190, 210, 360, Ann=450, 680}.
Now, the median of a set with odd # of terms is just a middle term (when ordered in ascending /descending order). So, old median=360.
We know that new median=330 and Cal's sales are still less than Ann's, hence Ann's new sales must be 330 (Ann's sales # must be reduced so that it becomes the middle term: 360 and Ann must switch places): {210, Cal, Ann=330, 360, 680}.
The value of the incorrectly recorded sale is Ann's old sales  Ann's new sales = 450  330 = 120.
Answer: D.
Hope it's clear. Hi Bunnel Here how do we now that Ann's sales=330. The question says ann's sales were higher than cal's and we are not sure about any particular value and we too don't know how much cal's sales were increased, so how can we order the list in the this way {210, Cal, Ann=330, 360, 680}. Plz correct me if i am wrong
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Re: The table above shows the total sales recorded in July for
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01 Feb 2012, 16:25
kotela wrote: Hi Bunnel
Here how do we now that Ann's sales=330. The question says ann's sales were higher than cal's and we are not sure about any particular value and we too don't know how much cal's sales were increased, so how can we order the list in the this way
{210, Cal, Ann=330, 360, 680}.
Plz correct me if i am wrong First of all either Cal's or Ann's sales must be 330. Now, if Cal's sales are 330 then as Ann>Cal then the ordering would be {210, Cal=330, Ann>Cal, 360, 680} > median={Ann's sales}>330, but we know that the median is 330, so this case is not possible. Hope it's clear.
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Re: The table above shows the total sales recorded in July for
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01 Feb 2012, 18:22
Bunuel wrote: kotela wrote: Hi Bunnel
Here how do we now that Ann's sales=330. The question says ann's sales were higher than cal's and we are not sure about any particular value and we too don't know how much cal's sales were increased, so how can we order the list in the this way
{210, Cal, Ann=330, 360, 680}.
Plz correct me if i am wrong First of all either Cal's or Ann's sales must be 330. Now, if Cal's sales are 330 then as Ann>Cal then the ordering would be {210, Cal=330, Ann>Cal, 360, 680} > median={Ann's sales}>330, but we know that the median is 330, so this case is not possible. Hope it's clear. ya that makes sense... I always miss reading small parts in a sentence...
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Re: The table above shows the total sales recorded in July for
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23 May 2013, 10:59
mydreammba wrote: Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000
The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A. $30,000 B. $48,000 C. $90,000 D. $120,000 E. $140,000
Let the transaction amount be x. Given that 450,000x>190,000+x > 2x<260,000 > x<130,000 Now the new median is 330,000. As the only 2 values changing are that of Cal's and Ann's, this new median must be either the increased sales figure of Cal, or the deflated sales figure of Ann. Cal : 330,000190,000 =x = 140,000> Not possible as x<130,000. Thus the median is the new sales figure of Ann > 450,000330,000 = 120,000. D.
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Re: The table above shows the total sales recorded in July for
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26 May 2013, 00:53
mydreammba wrote: Ann $450,000 Bob $360,000 Cal $190,000 Dot $210,000 Ed $680,000
The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A. $30,000 B. $48,000 C. $90,000 D. $120,000 E. $140,000
Can anyone please help with this...... My approach: As question stem tells that median is 330000, take a quick look for the other salesmen to match this median. None has 330000 sales. Thus this must of of either Ann's or cal's. besides that question further tells ann's and cal's amount is misplaced. so let us try to make Ann's sells 330000. Then we have to reduce 12000. this will be added to cal's and become 310000. this satisfies the condition that: Ann's sales amount > Cal's sales amount. To verify check by making Cal's amount 330000 above mentioned condition will be violated. Thus The misplaced amount is 120000.
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Re: The table above shows the total sales recorded in July for the 5 sales
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06 Mar 2015, 18:51
HI All, Karishma's explanation is spoton, so I won't rehash any of that here. I do want to point out that if the original poster had included the 5 answer choices, then we could have used them against the prompt and TESTed THE ANSWERS. That approach likely would have been easier (and taken less time) than the approach that we are all forced to take without having the answer choices. Remember that most questions on the Official GMAT can be approached in more than one way. Having the flexibility to solve problems in multiple ways can help you to score at a higher level on Test Day. GMAT assassins aren't born, they're made, Rich
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