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Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45

The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 24 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?

A. 4
B. 6
C. 9
D. 15
E. 20

Current range = highest - lowest --->112-45 = 67

After selling 20 shares of X and buying 24 shares of Y , the new share composition will be
V = 68 No change
W= 112 No change
X= 36 (because 56-20=36)
Y =118 (because 94+24 =118)
Z = 45No change

Now new range = highest - lowest ----> 118- 36= 82

Increase = new range -old range = 82-67 = 15

ANSWER IS D
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Check out below :-

Range before transaction:
112-45=67
Range after transaction:
(94+24)-(56-20)=118-36=82
The difference is: 82-67=15
Answer is D
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Original Range = 112 - 45
new Range = 118 - 36
so increase in range = 15
Answer D
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piyushksharma
Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45

The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 24 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?

A. 4
B. 6
C. 9
D. 15
E. 20

Attachment:
The table shows the nu.png

We recall that the formula for range is:

Range = greatest value - least value

Since the greatest number of shares is 112 and the least number of shares is 45, before selling stock X and buying stock Y, the current range is 112 - 45 = 67.

After 20 shares of stock X are sold and 24 shares of stock Y are purchased, the greatest number of shares is 94 + 24 = 118 and the least number of shares is 56 - 20 = 36. The new range would be118 - 36 = 82. Thus, the increase in the range is 82 - 67 = 15 shares.

Answer: D
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Original range= 112-45=67
New range=118-36=82

82-67=15 Answer: D
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