Bunuel wrote


Saumya2403 -
On the front axle (rod/pole), there is only one wheel on each side, and hence a total of two wheels on that axle.

On the other four axles, there are two wheels on each side, for a total of four wheels each those four axles.

If the setup is sketched such that "0" is a wheel and "--" is an axle:

front axle:
• one wheel on each axle SIDE
• two wheels total on the axle rod (pole)

other axles:
• two wheels on each axle SIDE
• four wheels total on the axle rod (pole)

SKETCH:

0--0

00--00
00--00
00--00
00--00

There are five axles. Hope it helps.
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Number of wheels in truck = 18
Number of wheels on its front axle =2
number of wheels remaining = 16
number of axles remaining axles = 16/4 = 4
Total number of axles = 5

T = 1.50 + 0.50( x − 2)
= 1.50 + .5*3
= 1.5 +1.5 = 3 $
Answer B
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Total number of wheels on the truck = 18
Number of wheels on front axle = 2
Remaining number of wheels is 16
but each of the other axles have 4 wheels on each of them
so remaining number of axles = \(\frac{16}{4}\) = 4 axles
so the truck has 5 axles in total i.e x= 5
substituting this value in given formula
T = 1.50 + 0.50( x − 2)
T = 1.50 + 0.50 (5 - 2)
T = 1.50 + 0.50 * 3
T = 1.50 + 1.50
T = $3.00

Correct Answer - B

Hi GMATters,

Here's a video explanation I created for this problem:



Enjoy!

Rowan
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Hi all,

Kindly explain solution to this question once more as I couldn't understand how there are 5 axels

Genexer123: Thanks for your explanation, yeah understood it now

We need to determine the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles.

Since there are 18 wheels and 2-wheels on the front axle and 4 wheels on the other, we have 1 axle for the front 2-wheels and 16/4 = 4 axles for the other wheels. Thus, the truck has a total of 5 axles and its toll is:

T = 1.5 + 0.5(5 - 2)

T = 1.5 + 1.5 = 3.00

Answer: B
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for front one axel we have 2 wheels
so for other 16 wheels we have 4 wheels per axle ie 4 axle
total axel = 4+1 ; 5=x
hence the toll T = 1.50 + 0.50( x − 2) ' 1.5+1.5= 3
option B ; $3