Bunuel wrote:
The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have?
A. 28
B. 50
C. 68
D. 76
E. 84
Sum of 5 integers = 5 x 24 = 120
Sum of 2 integers = 2 x 16 = 36
So, Sum of remaining 3 integers = 120 - 36 = 84
In order to maximize one integer, we need to minimize remaining 2 integers.As per condition, lowest value that any integer could take is 8. Thus, the sum of these 2 integers would be 16
So remaining integer would be = 84 - 16 = 68
Hence Answer C
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