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The value of each of 5 numbers is at least 8. The average (arithmetic
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09 Nov 2015, 23:00
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The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have? A. 28 B. 50 C. 68 D. 76 E. 84
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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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10 Nov 2015, 01:38
Number of terms , n= 5 Average = 24 a1+a2+a3+a4+a5 = 24*5=120 average of two of the numbers is 18 Sum of these 2 numbers , a3+a4 = 36 The least possible value of any number is 8 For the largest possible value (let's say a5) , the other 2 numbers a1 and a2 need to be 8 each . Therefore , a1+a2 = 16 a1+a2+a3+a4 = 36+16 = 52 Therefore a5 = 120  52 = 68 Answer C
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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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10 Nov 2015, 01:53
Bunuel wrote: The average (arithmetic mean) of these 5 numbers is 24. a + b + c + d + e = 120 Bunuel wrote: If the average of two of the numbers is 18 a + b + c + d + e = 120 36 + c + d + e = 120 c + d + e = 84 Bunuel wrote: The value of each of 5 numbers is at least 8. Replace the value of 2 numbers as 8 c + d + e = 84 8+8 + e = 84 So , the maximum possible value of e = 68 (8416) Hence , answer is C. 68
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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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10 Nov 2015, 11:36
The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have?
_________________________ Let the five numbers be a,b,c,d, and e (each being at least 8) a + b + c + d + e = 120 Let the two numbers whose average is 18 be a, and b. Therefore, a+b =36 Now, c + d + e = 120  36 = 84 Largest possible value can be achieved by giving c and d minimum possible value i.e. 8 SO, E ( maximum value ) can be 84  (8+8) = 8416 = 68 So answer should be C



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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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16 Nov 2015, 11:22
Average => (a1+a2+a3+a4+a5)/5 =24 Thus => a1+a2+a3+a4+a5 = 120 now least value is 8, so let a1 = 8
average of 2 numbers is 18 thus , let (a2+a3) /2 =18 a2+a3 = 36
This tells that sum of last 2 numbers should be : 120 836 =76
Then by elimination , eliminate 84 and 76 highest possible value of a5 should be 68 from the answer choice
Answer : C



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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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20 Jun 2017, 00:08
Bunuel wrote: The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have?
A. 28 B. 50 C. 68 D. 76 E. 84 Sum of 5 integers = 5 x 24 = 120 Sum of 2 integers = 2 x 16 = 36 So, Sum of remaining 3 integers = 120  36 = 84 In order to maximize one integer, we need to minimize remaining 2 integers.As per condition, lowest value that any integer could take is 8. Thus, the sum of these 2 integers would be 16 So remaining integer would be = 84  16 = 68 Hence Answer C
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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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20 Jun 2017, 19:12
Bunuel wrote: The value of each of 5 numbers is at least 8. The average (arithmetic mean) of these 5 numbers is 24. If the average of two of the numbers is 18, what is the largest possible value that any of these 5 numbers can have?
A. 28 B. 50 C. 68 D. 76 E. 84 We are given that 5 numbers have an average of 24 and that each number is at least 8. Using the formula average = sum/number, we see that the sum of the 5 numbers is 5 x 24 = 120. Since the average of 2 of the numbers is 18, the sum of those 2 numbers is 36. If we minimize the value of 2 more numbers, each of those numbers should be 8, and thus the sum of those 2 numbers is 16. Thus, the largest possible number in the set could be: 120  (36 + 16) = 120  52 = 68 Answer: C
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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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20 Jun 2017, 23:49
68 a+b+c+d+e=120 a+b=36 c+d+e=84 now according to the condition that each number is at least 8 keep c and d as 8 then we have e=68
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Re: The value of each of 5 numbers is at least 8. The average (arithmetic
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