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# The volume of the cube in the figure above is 64. If the vertices of ∆

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Re: The volume of the cube in the figure above is 64. If the vertices of ∆ [#permalink]
Bunuel wrote:

The volume of the cube in the figure above is 64. If the vertices of ∆ PQR are midpoints of the cube's edges, what is the perimeter of ∆ PQR?

(A) 6
(B) 6√2
(C) 6√3
(D) 12
(E) 12√2

Attachment:
2017-12-01_0948.png

Volume of big cube = a^3 = 64 = 4^3

i.e. Side of big cube = 4

i.e. Base of the Cut pyramid = Equilateral triangle with sides of length = 2√2 . (Using property of 45-45-90 on one triangular face of the pyramid)

Perimeter = 3*2√2 = 6√2

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Re: The volume of the cube in the figure above is 64. If the vertices of ∆ [#permalink]
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Re: The volume of the cube in the figure above is 64. If the vertices of ∆ [#permalink]
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