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# The workers at a large construction company reported x

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Intern
Joined: 03 Nov 2011
Posts: 7
Location: United States
The workers at a large construction company reported x  [#permalink]

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Updated on: 14 Apr 2012, 11:57
2
8
00:00

Difficulty:

45% (medium)

Question Stats:

67% (02:21) correct 33% (02:50) wrong based on 283 sessions

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The workers at a large construction company reported x percent fewer safety incidents in 2004 than in 2003, and y percent more incidents in 2005 than in 2004. If the workers reported a total of 1,000 incidents in 2003, how many incidents did the workers report in 2005?

(1) xy=50
(2) y-x-xy/100=4.5

Originally posted by rpamecha on 14 Apr 2012, 06:18.
Last edited by Bunuel on 14 Apr 2012, 11:57, edited 1 time in total.
Edited the question
Math Expert
Joined: 02 Sep 2009
Posts: 56257
Re: The workers at a large construction company reported x  [#permalink]

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14 Apr 2012, 12:10
3
3
The workers at a large construction company reported x percent fewer safety incidents in 2004 than in 2003, and y percent more incidents in 2005 than in 2004. If the workers reported a total of 1,000 incidents in 2003, how many incidents did the workers report in 2005?

The total # of incident is 2003 was 1,000;
The total # of incident in 2004 was x percent fewer than in 2003, so in 2004 there were $$1,000*(1-\frac{x}{100})$$ incidents;
The total # of incident in 2005 was y percent more than in 2004, so in 2005 there were $$1,000*(1-\frac{x}{100})*(1+\frac{y}{100})=1,000(1+\frac{y}{100}-\frac{x}{100}-\frac{xy}{100*100)}=1,000(1+\frac{1}{100}(y-x-\frac{xy}{100}))$$ incidents.

So, as you can see we need to find the value of $$y-x-\frac{xy}{100}$$.

(1) xy=50. Not sufficient to find the required value.

(2) y-x-xy/100=4.5 --> we are directly given the value of $$y-x-\frac{xy}{100}$$. Sufficient.

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##### General Discussion
Intern
Joined: 22 Jan 2012
Posts: 30
Re: The workers at a large construction company ......  [#permalink]

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14 Apr 2012, 07:11
1
The total no. of incidents in 2003 = 1000=T
The incidents in 2004 are x% fewer, so incidents = (1-x/100) *T
The incidents in 2005 are y% more , so incidents = (1-x/100)(1+y/100)*T

= (1-x/100+y/100-xy/100)*T
=(1+(y-x-xy)/100)*T

i) A insufficient , as we require value of x,y
ii) B sufficient , as we have the value of the whole expression.
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Re: The workers at a large construction company reported x  [#permalink]

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25 Mar 2017, 00:28
there is a shortcut for these kind of questions.
If some value is increased by X% then decreased by Y% then the net effective change will be equal to
X-Y-XY/100
that is if some value(say 100) is increased by 10% then decreased by 10% then the net change will be
10-10-100/100 = -1%
the final value be .99*100 = 99

Hope this helps
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Re: The workers at a large construction company reported x  [#permalink]

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24 Dec 2018, 11:22
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Re: The workers at a large construction company reported x   [#permalink] 24 Dec 2018, 11:22
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