prabsahi wrote:
VeritasKarishma ,Chetan sir,
I need your help in this!!
I understood the explanation that you gave but this reminded me of an
OG problem
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?
A. 15
B. 16
C. 28
D. 56
E. 64
This problem I understand we have to make selection of 2 players out of 10..
So I was little confused ..isn't it similar to the handsake problem??
If Team A player say 8th player plays with the 7th player --that means 7th has played with 8th..(much like handsake problem)
The only difference is in handsake is done by 3 people and here game is played by two teams..
If I use that approach..which I am very tempted to..I land up with a wrong answer..
Can you please help me here?
Yes, the problems are similar, though not same. So you need to tweak the numbers a bit.
In the games problem, every team plays with "all" other teams (so each team plays with 7 other teams). In every game, exactly 2 teams are involved.
No of games = 8*7/2 = 28
In the handshake problem, every person shakes hands with 3 other people. In every handshake, exactly 2 people participate.
No of handshakes = 10*3/2 = 15
Wow..This is perfect.
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