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11 Mar 2021, 09:15
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:22) correct
25%
(02:35)
wrong
based on 93
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There are 2 vessels of equal volumes. The first vessel has milk and water in the ratio 1 : 2. The second vessel has milk and water in the ratio 3 : 4. The contains of the two vessels are added to the third vessel. The third vessel is twice as big as these two vessels. What is the ratio of milk and water in the third vessel ?
(A) 7 : 9
(B) 13 : 17
(C) 8 : 11
(D) 8 : 13
(E) 8 : 15
(A) 7 : 9
(B) 13 : 17
(C) 8 : 11
(D) 8 : 13
(E) 8 : 15
22 Mar 2021, 10:53
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Bunuel
There are 2 vessels of equal volumes. The first vessel has milk and water in the ratio 1 : 2. The second vessel has milk and water in the ratio 3 : 4. The contains of the two vessels are added to the third vessel. The third vessel is twice as big as these two vessels. What is the ratio of milk and water in the third vessel ?
(A) 7 : 9
(B) 13 : 17
(C) 8 : 11
(D) 8 : 13
(E) 8 : 15
(A) 7 : 9
(B) 13 : 17
(C) 8 : 11
(D) 8 : 13
(E) 8 : 15
Taking conc. of milk only:
\(\frac{1}{3}x + \frac{3}{7}x = p *2x\)
Where \(p\) is the final concentration of Milk
\(\frac{1}{3} + \frac{3}{7} = 2p\)
\(p= \frac{16}{42}\)
So final concentration of Milk is \(\frac{16}{42}=\frac{Milk}{Total} \)
Water is: Total - Milk = \(42-16= 26\)
So Milk to water \(\frac{16}{26}\) or \(\frac{8}{13}\)
Ans-D
Hope it's clear.
30 Mar 2021, 07:21
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Given
To find:
Approach and Working out:
Let the volume of the first vessel = 3x
Let the volume of the second vessel = 7y
Volume of both the vessels are equal:
Thus, volume of the third vessel = 2 × 7y = 14y
Milk : Water in the third vessel = \(\frac{16y}{3}\) : \(\frac{26y}{3}\) = 16:26 = 8:13
Hence, option D is the correct answer.
Correct Answer: Option D
- • 2 vessels of equal volumes.
• First vessel has milk and water in the ratio 1 : 2.
• Second vessel has milk and water in the ratio 3 : 4.
- o Contains of the two vessels are added to a third vessel.
To find:
- • Ratio of milk and water in the third vessel.
Approach and Working out:
Let the volume of the first vessel = 3x
- • Quantity of milk = x
• Quantity of water = 2x
Let the volume of the second vessel = 7y
- • Quantity of milk = 3y
• Quantity of water = 4y
Volume of both the vessels are equal:
- • 3x = 7y
• x= \(\frac{7y}{3}\)
Thus, volume of the third vessel = 2 × 7y = 14y
- • Quantity of Milk in the third vessel = x+3y = \(\frac{7y}{3}\) +3y
- o \(\frac{16y}{3}\)
- o \(\frac{14y}{3}\) + 4y = \(\frac{26y}{3}\)
Milk : Water in the third vessel = \(\frac{16y}{3}\) : \(\frac{26y}{3}\) = 16:26 = 8:13
Hence, option D is the correct answer.
Correct Answer: Option D
