Total possible arrangements of counters = 3^4=81
Case 1- Number of cases when the all counters consist of same color= 3
m= 81-3 = 78
Case 2- when every arrangement consists of counters of each color
If this case 2 counters have same color and other 2 have different one
Total possible arrangements, n = 3C1* 4!/2! = 36
B
Bunuel wrote:
There are counters available in 3 different colors (at least four of each color). Counters are all alike except for the color. If ‘m’ denotes the number of arrangements of four counters if no arrangement consists of counters of same color and ‘n’ denotes the corresponding figure when every arrangement consists of counters of each color, then:
(A) m = 2n
(B) 6m = 13n
(C) 3m = 5n
(D) 5m = 3n
(E) 5m = 7n
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