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26 Feb 2024, 05:36
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Dropdown 1: 10/24
Dropdown 2: 21
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
61% (03:18) correct
39%
(03:12)
wrong
based on 259
sessions
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Not Attempted Yet
There are exactly three types of newspapers in country Z: Newspaper A, Newspaper B, and Newspaper C, and every citizen reads at least one of these three newspapers.
An initial analysis by an agency on the number of citizens and the newspaper they read is given below.
A second study that carried out the survey in detail reported the following:-
1. The number of people who read newspaper B were correct.
2. The number of people who read newspaper C were also correctly determined by the initial analysis. However, all those who read newspaper C also read newspaper A.
The survey was finally released after taking above two points in consideration. Select the correct option from the dropdown menu based on the final survey released.
A. If one citizen is randomly selected from the newspaper readers above, the probability that a person reads exactly two of the newspapers is .
B. The percentage of population not reading newspaper A is approx .
An initial analysis by an agency on the number of citizens and the newspaper they read is given below.
A second study that carried out the survey in detail reported the following:-
1. The number of people who read newspaper B were correct.
2. The number of people who read newspaper C were also correctly determined by the initial analysis. However, all those who read newspaper C also read newspaper A.
The survey was finally released after taking above two points in consideration. Select the correct option from the dropdown menu based on the final survey released.
A. If one citizen is randomly selected from the newspaper readers above, the probability that a person reads exactly two of the newspapers is .
B. The percentage of population not reading newspaper A is approx .
ShowHide Answer
Official Answer
Dropdown 1: 10/24
Dropdown 2: 21
27 Feb 2024, 04:15
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The initial analysis:
Only A - 7
Only B - 5
Only C - 5
Only (B&C) - 1
Only (B&A) - 2
Only (C&A) - 3
All three - 1
Final Survey:
All those who read C also read A, so wherever C is there, A gets added. Changes in Red
Only C - 5 becomes Only (C&A)
Only (B&C) - 1 becomes All three
Because of above the new distribution will be
Only A - 7
Only C - 5-5 = 0
Only B - 5
Only (C&B) - 1-1 = 0
Only (C&A) - 2+5 = 7
Only (B&A) - 3
All three - 1+1 = 2
A. If one citizen is randomly selected from the newspaper readers above, the probability that a person reads exactly two of the newspapers is
Exactly two = Only (B&C) + Only (B&A) + Only (A&C) = 0+3+7 = 10. Hence P = \(\frac{10}{24}\)
B. The percentage of population not reading newspaper A is approx
'Only B' are the ones not reading A => Hence P = \(\frac{5}{24}*100=20.83\) ~ 21%
Only A - 7
Only B - 5
Only C - 5
Only (B&C) - 1
Only (B&A) - 2
Only (C&A) - 3
All three - 1
Final Survey:
All those who read C also read A, so wherever C is there, A gets added. Changes in Red
Only C - 5 becomes Only (C&A)
Only (B&C) - 1 becomes All three
Because of above the new distribution will be
Only A - 7
Only C - 5-5 = 0
Only B - 5
Only (C&B) - 1-1 = 0
Only (C&A) - 2+5 = 7
Only (B&A) - 3
All three - 1+1 = 2
A. If one citizen is randomly selected from the newspaper readers above, the probability that a person reads exactly two of the newspapers is
Exactly two = Only (B&C) + Only (B&A) + Only (A&C) = 0+3+7 = 10. Hence P = \(\frac{10}{24}\)
B. The percentage of population not reading newspaper A is approx
'Only B' are the ones not reading A => Hence P = \(\frac{5}{24}*100=20.83\) ~ 21%
Aryaa03
Joined: 12 Jun 2023
Last visit: 23 Jul 2025
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Location: India
Schools: ISB '27 (A) IIM Calcutta '26 (A) IIMA '26 (D)
GMAT Focus 1: 645 Q86 V81 DI78 
27 Feb 2024, 22:36
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chetan2u
As per question stem-2
2. The number of people who read newspaper C were also correctly determined by the initial analysis. However, all those who read newspaper C also read newspaper A.
chetan2u Shouldn't C and A be considered instead of B and A ? Pleae pardon me if my below reasoning is incorrect.
a) Only C moves to only(A and C), which becomes 3 + 5 = 8
b) Only(B and C) moves to (A and B and C) = 1+1 = 2
For first prompt -
Exactly 2 = Only (B and A) and Only (C and A) = 2 + 8 = 10 ==> P(Exactly 2) = 10/24
For second prompt -
Not reading A = only B = 5 , which is equalt to ~21% of 24.
