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02 Dec 2020, 02:48
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
34% (02:57) correct
66%
(02:24)
wrong
based on 124
sessions
History
Date
Time
Result
Not Attempted Yet
There are two vessels of milk of different prices, per litre, with the volume of 220 litres and 180 litres, respectively. Equal amounts of milk were poured off simultaneously from the two vessels and the milk poured off from the first vessel was poured into the second vessel and milk poured off from the second vessel was poured into the first vessel. Then the price of milk in both the vessels, per litre, becomes the same. How much milk was poured from one vessel into the other?
A. 80
B. 90
C. 99
D. 160
E. Cannot be determined
Are You Up For the Challenge: 700 Level Questions
A. 80
B. 90
C. 99
D. 160
E. Cannot be determined
Are You Up For the Challenge: 700 Level Questions
There are 2 drums of oil of different prices, their volume being 220 gallons and 180 gallons. Equal quantities are drawn off from the 2 drums. The oil drawn from the first drum is poured into the second drum, and the oil drawn from the second drum is poured into the first drum. Then the price of oil per gallon in both drums becomes equal. How much is drawn from each drum?
02 Dec 2020, 03:20
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Price per liter of 220L vessel: A
Price per liter of 180L vessel: B
Amount moved from each vessel: L
Equation:
((220-L)*A + L*B)/220= ((180-L)*B + L*A)/180
Solving it gives you a result of L=99
Answer C
Price per liter of 180L vessel: B
Amount moved from each vessel: L
Equation:
((220-L)*A + L*B)/220= ((180-L)*B + L*A)/180
Solving it gives you a result of L=99
Answer C
General Discussion
02 Dec 2020, 03:25
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Explanation:
Vessel 1 per litre milk price which contains 220L milk = x, total price = 220x
Vessel 2 per litre milk price which contains 180L milk = y, total price = 180y
S Litre milk removed from each vessel
So, Price of vessel 1 = {(220 - S)x + S*y}/ 220
Price of vessel 2 = {(180 - S)y + S*x}/ 180
Price of vessel 1 = Price of vessel 2
{(220 - S)x + S*y}/ 220 = {(180 - S)y + S*x}/ 180
{(220 - S)x + S*y}/11 = {(180 - S)y + S*x}/9
9*(220x - S*x + S*y = 11*(180y - S*y + S*x}
1980x - 9S*x + 9S*y = 1980y - 11S*y + 11S*x
1980*(x-y) = 20(S*x - S*y)
1980 (x - y) = 20S(x - y)
1980 = 20S
S = 99
IMO-C
Vessel 1 per litre milk price which contains 220L milk = x, total price = 220x
Vessel 2 per litre milk price which contains 180L milk = y, total price = 180y
S Litre milk removed from each vessel
So, Price of vessel 1 = {(220 - S)x + S*y}/ 220
Price of vessel 2 = {(180 - S)y + S*x}/ 180
Price of vessel 1 = Price of vessel 2
{(220 - S)x + S*y}/ 220 = {(180 - S)y + S*x}/ 180
{(220 - S)x + S*y}/11 = {(180 - S)y + S*x}/9
9*(220x - S*x + S*y = 11*(180y - S*y + S*x}
1980x - 9S*x + 9S*y = 1980y - 11S*y + 11S*x
1980*(x-y) = 20(S*x - S*y)
1980 (x - y) = 20S(x - y)
1980 = 20S
S = 99
IMO-C
