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03 Mar 2021, 15:05
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
54% (02:55) correct
46%
(02:44)
wrong
based on 278
sessions
History
Date
Time
Result
Not Attempted Yet
There is a tribal area in Australia called Xiamer and the existing tribal population is concentrated in that area. It is found that 45 percent of the men (above 18 years adult men) in that area are married to 25 percent of the women (who are above 18 and considered adult) in that area. What percentage of the total adult population is married?(One man marries one woman)
A 35
B 32.1
C 30.9
D 25
E Cannot be Determined
A 35
B 32.1
C 30.9
D 25
E Cannot be Determined
05 Mar 2021, 01:41
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CrackVerbalGMAT
I believe the question means that there are no marriages outside the tribe.
Let the number of men and women be m and n.
Since 45% of men are married to 25% of women, \(\frac{45m}{100}=\frac{25w}{100}........w=\frac{9m}{5}\)
Total strength = \(m+w=m+\frac{9m}{5}=\frac{14m}{5}\)
Total married people = Twice of men married, as for each man , there will be a woman married
\(=2*\frac{45m}{100}=\frac{9m}{10}\)
%\(=\frac{\frac{9m}{10}}{\frac{14m}{5}}*100=\frac{9*5}{10*14}*100=32.14\)
B
General Discussion
Archit3110
Major Poster
10 Jul 2021, 09:07
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total population = men + women
given that married population is
.45*m = .25*w
we get w = 9/5 * m
let m = 10 so w = 18
total population = 28
(.45*10)+(.25*18)/ 28 ; 9/28 ;32.1
option B
given that married population is
.45*m = .25*w
we get w = 9/5 * m
let m = 10 so w = 18
total population = 28
(.45*10)+(.25*18)/ 28 ; 9/28 ;32.1
option B
CrackVerbalGMAT
