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Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f

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Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f  [#permalink]

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New post 18 Feb 2019, 10:42
3
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

50% (02:04) correct 50% (02:15) wrong based on 24 sessions

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Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to from a chemical for washing white clothes. The quantity of chemical is altered so that the ratio of acids A&B is 1/3 and the ratio of the acids B&C is made 2/3, the new ratio of all three can now be used to form a chemical for washing colored clothes. What is the total volume of new chemical solution formed if it contains 30ml of acid B?

A. 36ml
B. 45ml
C. 52ml
D. 72ml
E. 92ml
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Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f  [#permalink]

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New post 18 Feb 2019, 20:56
kiran120680 wrote:
Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to from a chemical for washing white clothes. The quantity of chemical is altered so that the ratio of acids A&B is 1/3 and the ratio of the acids B&C is made 2/3, the new ratio of all three can now be used to form a chemical for washing colored clothes. What is the total volume of new chemical solution formed if it contains 30ml of acid B?

A. 36ml
B. 45ml
C. 52ml
D. 72ml
E. 92ml


A:B ---> 1x:3x
B:C ----> 2y:3y

Since the two ratios are linked through "B" I can get a ratio of of A:B:C by getting things in terms of x

Therefore 3x = 2y

Therefore y = (3/2)x = 1.5x

A:B:C -----> 1x:3x:3y ----> 1x:3x:3*1.5x ----> 1x:3x:4.5x

Total ml Solution = 1x + 3x + 4.5x = 8.5x

Since "B" = 30 ml -----> 3x = 30ml -----> x = 10

Therefore, total ml solution = 8.5 * 10 = 85ml.

Note: The ratio of the original mixture is irrelevant to this question.

Edit: Just realized 85ml isn't an answer choice. I think OP posted a bogus question. Is there a source for this question or did you make it up yourself. Check your numbers dude.
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Re: Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f  [#permalink]

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New post 18 Feb 2019, 21:16
Yeah ! I am getting 85 as the answer too ! Is this correct and if not, can someone post the correct answer
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Re: Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f  [#permalink]

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New post 18 Feb 2019, 21:41
Yes, it's not clear what the 4:5:6 ratio has to do with the actual problem, and I also get 85 as the answer. It's a standard 3-part ratio question where we have:

a to b to c
1 to 3
.......2 to 3

and getting the same number for b (multiplying the first row by 2, the second by 3) we get

a to b to c
2 to 6 to 9

So b is 6/17 of the total mixture (2 + 6 + 9 = 17), and if the actual value of b is 30 = 5*6, the total amount must be 5*17 = 85.

Since the 4:5:6 ratio at the start of the question ends up being irrelevant, I'd have to guess whoever wrote the question intended to ask something else, but as the question is written, there's something wrong with it or with the answer choices.
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Re: Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f  [#permalink]

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New post 02 Sep 2019, 06:21
A'/B' = 1/3*4/5 = 4/15
B'/C' = 2/3*5/6 =5/9
A':B':C' = 4:15:27
15x=30ml
x=2ml
total= 4+15+27 = 46x
total = 46*2 = 92ml
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Re: Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f  [#permalink]

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New post 02 Sep 2019, 07:28
I got it by eliminating options , after altering a/b=1:3,b:c=2:3, that indicates 3/4 th of a+b is b and also 2/5th of b+c is also b, remember that both quantities are equal so 3/4x= 2/5y cross multiplying it becomes 15x=8y >>>> x/y= 8/15 so x is 8/23 and y is 15/23 of total, in options the only multiple of 23 is 92 , so E is the answer

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Re: Three acids A, B and C are mixed in the ratio 4:5:6 respectively, to f   [#permalink] 02 Sep 2019, 07:28
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