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My approach

Area of rectangle = LB
216= LB.

From figure we can infer B= Diagonal of small square and L= diagonal of square*3 (because 3 square are placed above one another) Let diagonal of square be x so we can say LB=3x*x

Hence 216=3x*x
216= 3x^2
216/3= x^2
72=x^2
36* 2=x^2
6 root 2= x

Diagonal of square is root2*side of square (Property)

Hence we can say side of square is 6 and hence area of square will be 6 square = 36

Experts let me know if anything wrong with my approach.

Thanks.
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accountingnerd30
My approach

Area of rectangle = LB
216= LB.

From figure we can infer B= Diagonal of small square and L= diagonal of square*3 (because 3 square are placed above one another) Let diagonal of square be x so we can say LB=3x*x

Hence 216=3x*x
216= 3x^2
216/3= x^2
72=x^2
36* 2=x^2
6 root 2= x

Diagonal of square is root2*side of square (Property)

Hence we can say side of square is 6 and hence area of square will be 6 square = 36

Experts let me know if anything wrong with my approach.

Thanks.



Hey, this is pretty similar to what I did, I noted that the area of 216 = L*W, where L = 3*diagonal of square and W= 1*diagonal of square.

We know that the diagonal of a square has a length of x*root(2); where 'x' = the length of a side of the square. This is a general rule as when you cut a square from its diagonal it forms a 45-45-90 triangle with legs of length 'x' (same as the sides of the square) and a hypotenuse of x*root(2).

Hence the L = 3*x*root(2) and W = x*root(2)

Therefore, the area of the rectangle can be expressed as L*W = (3*x*root(2))*(x*root(2)) = 216

So 6x^2 = 216 thus x = 6 (where 'x' is a side of the square); so Area of a square = 6*6 = 36
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