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Three points T, U and V on the number line have coordinates t, u, and
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20 Apr 2016, 15:32
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Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V? (1) \(t^2<4<u^2<v^2\) (2) \(u<0<v\)
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Three points T, U and V on the number line have coordinates t, u, and
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20 Apr 2016, 22:51
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are nonnegative, we can safely take the square root from it: \(t < 2 < u < v\). It's possible that T is between U and V, for example, if t=0, u=3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient. (2) \(u<0<v\). Clearly insufficient. (1) Since from (2) u<0<v, then from (1) we get \(t < 2 < u < v\). If break it: we'll get \(u<2\) (from 2 < u), \(2<t<2\) (from t < 2), and \(2<v\). T is between U and V. Sufficient. Answer: C. Hope it's clear.
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Re: Three points T, U and V on the number line have coordinates t, u, and
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20 Apr 2016, 18:20
St1: t^2 can take values between 0 and 4 > 2 < t < 2 When u and v have the same sign: v > u > 2 or v < u < 2 > t does not lie between u and v When u and v have oppositie sign: u > 2 and v < u < 2 or u < 2 and v > u > 2 > t lies between u and v
Illustrating the above statements: When t = 1; u = 3; v = 4, t does not lie between u and v When t = 1; u = 3; v = 4, t lies between u and v Not Sufficient.
St2: u is ve and v is positive > Clearly insufficient as we have no information about t
Combining St1 and St2: 2 < t < 2; u is negative > u < 2 v is positive > v > u > 2 As shown in St1, when u and v have opposite signs, t lies between u and v. Sufficient
Answer: C




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Re: Three points T, U and V on the number line have coordinates t, u, and
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20 Apr 2016, 20:03
Hi Bunuel , Is this really a GMAT PREP Question .
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Re: Three points T, U and V on the number line have coordinates t, u, and
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20 Apr 2016, 20:37
abhisheknandy08 wrote: Hi Bunuel , Is this really a GMAT PREP Question . Hi, the Q is a bit twisted but tests number properties.. and since it has been shown that the source is GMAT PREP EP2, we should be ready for such Qs
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Re: Three points T, U and V on the number line have coordinates t, u, and
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20 Apr 2016, 20:44
chetan2u wrote: abhisheknandy08 wrote: Hi Bunuel , Is this really a GMAT PREP Question . Hi, the Q is a bit twisted but tests number properties.. and since it has been shown that the source is GMAT PREP EP2, we should be ready for such Qs Absolutely sir..i think it should be 700 Qwrongly tagged i believe.
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Re: Three points T, U and V on the number line have coordinates t, u, and
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21 Apr 2016, 05:19
abhisheknandy08 wrote: Hi Bunuel , Is this really a GMAT PREP Question . Yes, it is from EP 2 (the newly launched EP). Sent from my SMG900T using Tapatalk



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Re: Three points T, U and V on the number line have coordinates t, u, and
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21 Apr 2016, 05:20
If everyone thinks it is 700 level, I will change the tag.
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Re: Three points T, U and V on the number line have coordinates t, u, and
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21 Apr 2016, 05:24



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Re: Three points T, U and V on the number line have coordinates t, u, and
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31 Jul 2016, 14:15
Tip: I found drawing the number line here instead of trying to write out inequalities got to the correct answer much quicker. ~2030 seconds



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Re: Three points T, U and V on the number line have coordinates t, u, and
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01 Jun 2017, 03:24
Bunuel wrote: Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are nonnegative, we can safely take the square root from it: \(t < 2 < u < v\). It's possible that T is between U and V, for example, if t=0, u=3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) u<0<v. Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(t < 2 < u < v\). If break it: we'll get \(u<2\) (from 2 < u), \(2<t<2\) (from t < 2), and \(2<v\). T is between U and V. Sufficient.
Answer: C.
Hope it's clear. When you take the sq rt of 4 in this, shouldn't the result be +/ 2?



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Re: Three points T, U and V on the number line have coordinates t, u, and
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01 Jun 2017, 05:24
ailintan wrote: Bunuel wrote: Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are nonnegative, we can safely take the square root from it: \(t < 2 < u < v\). It's possible that T is between U and V, for example, if t=0, u=3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) u<0<v. Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(t < 2 < u < v\). If break it: we'll get \(u<2\) (from 2 < u), \(2<t<2\) (from t < 2), and \(2<v\). T is between U and V. Sufficient.
Answer: C.
Hope it's clear. When you take the sq rt of 4 in this, shouldn't the result be +/ 2? Are you talking about t^2 < 4? What is your question? t^2 < 4 t < 2 (which is the same as 2 < t < 2).
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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Re: Three points T, U and V on the number line have coordinates t, u, and
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09 Aug 2017, 23:14
Bunuel wrote: ailintan wrote: Bunuel wrote: Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are nonnegative, we can safely take the square root from it: \(t < 2 < u < v\). It's possible that T is between U and V, for example, if t=0, u=3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) u<0<v. Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(t < 2 < u < v\). If break it: we'll get \(u<2\) (from 2 < u), \(2<t<2\) (from t < 2), and \(2<v\). T is between U and V. Sufficient.
Answer: C.
Hope it's clear. When you take the sq rt of 4 in this, shouldn't the result be +/ 2? Are you talking about t^2 < 4? What is your question? t^2 < 4 t < 2 (which is the same as 2 < t < 2). Yeah, It is a medium level question. I bit of guess/application work is needed to solve this question. Mentioned question can be solved only if we were given both information A and B. So Answer C



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Re: Three points T, U and V on the number line have coordinates t, u, and
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18 Mar 2018, 06:12
How do I check the difficult level in terms of 660650700750 level? It just shows easy/ medium on the timer :/



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Re: Three points T, U and V on the number line have coordinates t, u, and
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18 Mar 2018, 06:17




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