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Three points T, U and V on the number line have coordinates t, u, and
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mbaspire
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Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  20 Apr 2016, 15:32
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Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?


(1) \(t^2<4<u^2<v^2\)

(2) \(u<0<v\)
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Bunuel
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Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  20 Apr 2016, 22:51
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Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?

(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.

(2) \(u<0<v\). Clearly insufficient.

(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.

Answer: C.

Hope it's clear.
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  20 Apr 2016, 18:20
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St1: t^2 can take values between 0 and 4 --> -2 < t < 2
When u and v have the same sign: v > u > 2 or v < u < -2 --> t does not lie between u and v
When u and v have oppositie sign: u > 2 and v < -u < -2 or u < -2 and v > -u > 2 --> t lies between u and v

Illustrating the above statements:
When t = 1; u = 3; v = 4, t does not lie between u and v
When t = 1; u = -3; v = 4, t lies between u and v
Not Sufficient.

St2: u is -ve and v is positive --> Clearly insufficient as we have no information about t

Combining St1 and St2:
-2 < t < 2;
u is negative --> u < -2
v is positive --> v > -u > 2
As shown in St1, when u and v have opposite signs, t lies between u and v.
Sufficient

Answer: C
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TheKingInTheNorth
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  20 Apr 2016, 20:03
Hi Bunuel ,
Is this really a GMAT PREP Question .
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  20 Apr 2016, 20:37
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abhisheknandy08 wrote:
Hi Bunuel ,
Is this really a GMAT PREP Question .



Hi,
the Q is a bit twisted but tests number properties..
and since it has been shown that the source is GMAT PREP EP2, we should be ready for such Qs
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  20 Apr 2016, 20:44
chetan2u wrote:
abhisheknandy08 wrote:
Hi Bunuel ,
Is this really a GMAT PREP Question .



Hi,
the Q is a bit twisted but tests number properties..
and since it has been shown that the source is GMAT PREP EP2, we should be ready for such Qs


Absolutely sir..i think it should be 700 Q---wrongly tagged i believe.
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  21 Apr 2016, 05:19
abhisheknandy08 wrote:
Hi Bunuel ,
Is this really a GMAT PREP Question .

Yes, it is from EP 2 (the newly launched EP).

Sent from my SM-G900T using Tapatalk
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  21 Apr 2016, 05:20
If everyone thinks it is 700 level, I will change the tag.

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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  21 Apr 2016, 05:24
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mbaspire wrote:
If everyone thinks it is 700 level, I will change the tag.

Sent from my SM-G900T using Tapatalk


No need. the difficulty level is adjusted automatically based on stats from timer.
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  31 Jul 2016, 14:15
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Tip: I found drawing the number line here instead of trying to write out inequalities got to the correct answer much quicker. ~20-30 seconds
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  01 Jun 2017, 03:24
Bunuel wrote:
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?

(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.

(2) u<0<v. Clearly insufficient.

(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.

Answer: C.

Hope it's clear.


When you take the sq rt of 4 in this, shouldn't the result be +/- 2?
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  01 Jun 2017, 05:24
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ailintan wrote:
Bunuel wrote:
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?

(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.

(2) u<0<v. Clearly insufficient.

(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.

Answer: C.

Hope it's clear.


When you take the sq rt of 4 in this, shouldn't the result be +/- 2?


Are you talking about t^2 < 4? What is your question?

t^2 < 4

|t| < 2 (which is the same as -2 < t < 2).
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  09 Aug 2017, 23:14
Bunuel wrote:
ailintan wrote:
Bunuel wrote:
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?

(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.

(2) u<0<v. Clearly insufficient.

(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.

Answer: C.

Hope it's clear.


When you take the sq rt of 4 in this, shouldn't the result be +/- 2?


Are you talking about t^2 < 4? What is your question?

t^2 < 4

|t| < 2 (which is the same as -2 < t < 2).



Yeah, It is a medium level question. I bit of guess/application work is needed to solve this question. Mentioned question can be solved only if we were given both information A and B.

So Answer C
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  18 Mar 2018, 06:12
How do I check the difficult level in terms of 660-650-700-750 level? It just shows easy/ medium on the timer :/
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Re: Three points T, U and V on the number line have coordinates t, u, and [#permalink] New post  18 Mar 2018, 06:17
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kritikalal wrote:
How do I check the difficult level in terms of 660-650-700-750 level? It just shows easy/ medium on the timer :/


We have three grades of difficulty: easy, which corresponds to sub-600; medium, which corresponds to 600-700; and hard, which corresponds to 700+. You can check difficulty level of a question along with the stats on it in the first post. The difficulty level of a question is calculated automatically based on the timer stats from the users which attempted the question.
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