Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
The Competition Continues - Game of Timers is a team-based competition based on solving GMAT questions to win epic prizes! Starting July 1st, compete to win prep materials while studying for GMAT! Registration is Open! Ends July 26th
Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
20 Apr 2016, 23:51
15
24
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) \(u<0<v\). Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
20 Apr 2016, 19:20
12
4
St1: t^2 can take values between 0 and 4 --> -2 < t < 2 When u and v have the same sign: v > u > 2 or v < u < -2 --> t does not lie between u and v When u and v have oppositie sign: u > 2 and v < -u < -2 or u < -2 and v > -u > 2 --> t lies between u and v
Illustrating the above statements: When t = 1; u = 3; v = 4, t does not lie between u and v When t = 1; u = -3; v = 4, t lies between u and v Not Sufficient.
St2: u is -ve and v is positive --> Clearly insufficient as we have no information about t
Combining St1 and St2: -2 < t < 2; u is negative --> u < -2 v is positive --> v > -u > 2 As shown in St1, when u and v have opposite signs, t lies between u and v. Sufficient
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
20 Apr 2016, 21:37
abhisheknandy08 wrote:
Hi Bunuel , Is this really a GMAT PREP Question .
Hi, the Q is a bit twisted but tests number properties.. and since it has been shown that the source is GMAT PREP EP2, we should be ready for such Qs
_________________
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
01 Jun 2017, 04:24
Bunuel wrote:
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) u<0<v. Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.
Answer: C.
Hope it's clear.
When you take the sq rt of 4 in this, shouldn't the result be +/- 2?
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
01 Jun 2017, 06:24
2
ailintan wrote:
Bunuel wrote:
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) u<0<v. Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.
Answer: C.
Hope it's clear.
When you take the sq rt of 4 in this, shouldn't the result be +/- 2?
Are you talking about t^2 < 4? What is your question?
t^2 < 4
|t| < 2 (which is the same as -2 < t < 2).
_________________
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
10 Aug 2017, 00:14
Bunuel wrote:
ailintan wrote:
Bunuel wrote:
Three points T, U and V on the number line have coordinates t, u, and v respectively. Is T between points U and V?
(1) \(t^2<4<u^2<v^2\). Since all parts of the inequality are non-negative, we can safely take the square root from it: \(|t| < 2 < |u| < |v|\). It's possible that T is between U and V, for example, if t=0, u=-3 and v=4, as well as it's possible that it's not, for example, t=0, u=3 and v=4. Not sufficient.
(2) u<0<v. Clearly insufficient.
(1) Since from (2) u<0<v, then from (1) we get \(|t| < 2 < -u < v\). If break it: we'll get \(u<-2\) (from 2 < -u), \(-2<t<2\) (from |t| < 2), and \(2<v\). T is between U and V. Sufficient.
Answer: C.
Hope it's clear.
When you take the sq rt of 4 in this, shouldn't the result be +/- 2?
Are you talking about t^2 < 4? What is your question?
t^2 < 4
|t| < 2 (which is the same as -2 < t < 2).
Yeah, It is a medium level question. I bit of guess/application work is needed to solve this question. Mentioned question can be solved only if we were given both information A and B.
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
18 Mar 2018, 07:17
kritikalal wrote:
How do I check the difficult level in terms of 660-650-700-750 level? It just shows easy/ medium on the timer :/
We have three grades of difficulty: easy, which corresponds to sub-600; medium, which corresponds to 600-700; and hard, which corresponds to 700+. You can check difficulty level of a question along with the stats on it in the first post. The difficulty level of a question is calculated automatically based on the timer stats from the users which attempted the question.
_________________
Re: Three points T, U and V on the number line have coordinates t, u, and
[#permalink]
Show Tags
21 Mar 2019, 14:23
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
close
69% (01:54) correct 
