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18 Jan 2024, 02:30
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:42) correct
19%
(02:07)
wrong
based on 215
sessions
History
Date
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Not Attempted Yet
To create 10 gallons of a 20% acid liquid solution, x gallons of a 10% acid liquid solution are mixed with y gallons of a 50% acid liquid solution. How many gallons of the 50% acid liquid solution were used?
A. 1
B. 1.5
C. 2
D. 2.5
E. 3
A. 1
B. 1.5
C. 2
D. 2.5
E. 3
The 20% acid liquid solution is produced by adding a gallons of 10% acid liquid solution to b gallons of 50% acid liquid solution. To get 10 gallons of 20% acid liquid solution, how many gallons of 50% acid liquid solution are needed?
18 Jan 2024, 07:00
Kudos
Bookmarks
Bunuel
OA is D
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18 Jan 2024, 07:09
Kudos
Bookmarks
So, 10 gallons of 20% acid solution, and you have 10% and 50% acidic solutions.
Total quantity = x + y = 10
So, x = y - 10
y - 10 gallons of 10% acidic solution and y gallons of 50% acidic solution.
Using weighted averages (I actually used alligation),
0.2(10) = 0.1(10 - y) + 0.5(y)
2 = 1 - 0.1y + 0.5y
y = 10/4 = 2.5
The answer is D - 2.5
Total quantity = x + y = 10
So, x = y - 10
y - 10 gallons of 10% acidic solution and y gallons of 50% acidic solution.
Using weighted averages (I actually used alligation),
0.2(10) = 0.1(10 - y) + 0.5(y)
2 = 1 - 0.1y + 0.5y
y = 10/4 = 2.5
The answer is D - 2.5
