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# To meet a government requirement, a bottler must test 5 percent of its

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Senior Manager
Joined: 02 Jan 2017
Posts: 291
To meet a government requirement, a bottler must test 5 percent of its  [#permalink]

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22 Feb 2017, 20:29
00:00

Difficulty:

5% (low)

Question Stats:

93% (01:15) correct 7% (01:52) wrong based on 54 sessions

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To meet a government requirement, a bottler must test 5 percent of its spring water and 10 percent of its sparkling water for purity. If a customer ordered 120 cases of spring water and 80 cases of sparkling water, what percent of all the cases must the bottler test before it can send the water out?

○A○ 6.5%
○B○ 7.0%
○C○ 7.5%
○D○ 8.0%
○E○ 8.5%
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Re: To meet a government requirement, a bottler must test 5 percent of its  [#permalink]

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23 Feb 2017, 00:07
1
vikasp99 wrote:
To meet a government requirement, a bottler must test 5 percent of its spring water and 10 percent of its sparkling water for purity. If a customer ordered
120 cases of spring water and 80 cases of sparkling water, what percent of all the cases must the bottler test before it can send the water out?

○A○ 6.5%
○B○ 7.0%
○C○ 7.5%
○D○ 8.0%
○E○ 8.5%

5 percent of 120 cases of spring water = 0.05*120 = 6
10 percent of 80 cases of sparkling water = 0.10*80 = 8
so 14 bottles to be tested for both cases

percent of all the cases must the bottler test before it can send the water out = 100*(14/(120+80)) = 1400/200 = 7%

Hence Option B is correct
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Re: To meet a government requirement, a bottler must test 5 percent of its  [#permalink]

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24 Feb 2017, 12:14
Hi vikasp99,

This question is essentially just about doing the necessary arithmetic, but if you were low on time then you can use a logic 'pattern' to quickly eliminate a bunch of answers and take a good educated guess.

Since the bottler has to 'test' 5% of the spring water and 10% of the sparkling water that it sends out, IF there were equal numbers of spring water and sparkling water, then the bottler would need to test (5% + 10%)/2 = 7.5% of the bottles. However, the prompt tells us that there are MORE bottles of spring water being sent out than bottles of sparkling water being sent out, so the average has to be LESS than 7.5%.... so you can eliminate Answers C, D and E.

To find the exact answer, we need to calculate....

5% of 120 bottles = (.05)(120) = 6
10% of 80 bottles = (.1)(80) = 8
Total = 14 out of 200 bottles = 14/200 = 7/100 = 7%

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Re: To meet a government requirement, a bottler must test 5 percent of its  [#permalink]

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21 Jun 2017, 04:56
vikasp99 wrote:
To meet a government requirement, a bottler must test 5 percent of its spring water and 10 percent of its sparkling water for purity. If a customer ordered
120 cases of spring water and 80 cases of sparkling water, what percent of all the cases must the bottler test before it can send the water out?

○A○ 6.5%
○B○ 7.0%
○C○ 7.5%
○D○ 8.0%
○E○ 8.5%

120(.05) + 80(.10) /200 = 7

Thus
"B"
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Re: To meet a government requirement, a bottler must test 5 percent of its  [#permalink]

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18 Feb 2019, 19:16
vikasp99 wrote:
To meet a government requirement, a bottler must test 5 percent of its spring water and 10 percent of its sparkling water for purity. If a customer ordered 120 cases of spring water and 80 cases of sparkling water, what percent of all the cases must the bottler test before it can send the water out?

○A○ 6.5%
○B○ 7.0%
○C○ 7.5%
○D○ 8.0%
○E○ 8.5%

0.05 x 120 = 6 cases of spring water must be tested.
.
0.1 x 80 = 8 cases of sparkling water must be tested.

Thus, a total of (8 + 6)/(120 + 80) = 14/200 = 0.07 = 7% of all the cases must be tested.

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Re: To meet a government requirement, a bottler must test 5 percent of its   [#permalink] 18 Feb 2019, 19:16
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