vikasp99 wrote:
To meet a government requirement, a bottler must test 5 percent of its spring water and 10 percent of its sparkling water for purity. If a customer ordered
120 cases of spring water and 80 cases of sparkling water, what percent of all the cases must the bottler test before it can send the water out?
○A○ 6.5%
○B○ 7.0%
○C○ 7.5%
○D○ 8.0%
○E○ 8.5%
5 percent of 120 cases of spring water = 0.05*120 = 6
10 percent of 80 cases of sparkling water = 0.10*80 = 8
so 14 bottles to be tested for both cases
percent of all the cases must the bottler test before it can send the water out = 100*(14/(120+80)) = 1400/200 = 7%
Hence Option B is correct
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