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26 Apr 2017, 08:06
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
94% (01:08) correct
6%
(02:23)
wrong
based on 18
sessions
History
Date
Time
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Not Attempted Yet
Tom and Steven are riding motorcycles down the highway at constant speeds. If Tom is now 2 miles ahead of Steven, how many minutes before Tom is 3 miles ahead of Steven?
(1) Tom and Steven are traveling a total distance of 75 miles.
(2) Five minutes ago, Tom was 1 mile ahead of Steven.
(1) Tom and Steven are traveling a total distance of 75 miles.
(2) Five minutes ago, Tom was 1 mile ahead of Steven.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
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26 Apr 2017, 20:27
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Bunuel
Hi...
We are looking at either the exact speeds or the relative speed..
Statement I gives us distance, which is of no use in present context..
Insufficient
Statement II gives us the relative distance between the two.
If T was 1 mile ahead of S 5 mins ago and NOW is 2 miles ahead, MEANING T is increasing 1 mile in 5 mins..
So after 5 mins, T will be 3 miles ahead of S.
Sufficient
B
Hi Bunuel , one odd typo in the Q.
Right now, T is 2 miles ahead, we are looking for how many mins BEFORE he was 3 miles ahead.
Means :- S is faster and covering up.
But statement II tells us that T was 1 mile ahead sometime back, this means T is increasing the gap.
Means:- T is faster.
May be BEFORE should be changed to AFTER in main Q.
Or 5 mins ago should be 5mins after, he will be 1 miles ahead.
03 Jun 2017, 07:40
Kudos
Bookmarks
Statement 1 is clearly insufficient as no information can be derived regarding speed.
Statement 2:
We can say in 5 min 1 mile is covered
Relative Distance= Relative Speed* Time
So 1 mile= S* (5/60)
Therefore, relative speed is 12 Mph.
Now the distance between them is 2 miles and the question ask about the time when the distance becomes 3 miles so
Relative Distance = 3-2 Miles
Relative Speed = 12 Mph
Time=?
using Relative Distance= Relative Speed* Time
1=12*t
t=(1/12) hr = (1/12)*60 = 5min.
Bunuel please let me know if my approach is correct or not
Statement 2:
We can say in 5 min 1 mile is covered
Relative Distance= Relative Speed* Time
So 1 mile= S* (5/60)
Therefore, relative speed is 12 Mph.
Now the distance between them is 2 miles and the question ask about the time when the distance becomes 3 miles so
Relative Distance = 3-2 Miles
Relative Speed = 12 Mph
Time=?
using Relative Distance= Relative Speed* Time
1=12*t
t=(1/12) hr = (1/12)*60 = 5min.
Bunuel please let me know if my approach is correct or not
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
