In the table above is shown the percent reduction in the

Question

Date of Purchase
 Percent Reduction
 
July 1 through July 7
 5%
 
July 8 through July 14
 30%
 
July 15 through July 21
 55%
 
July 22 through July 28
 70%
 
In the table above is shown the percent reduction in the price of every item in a store off the original price of that item on June 30 of that year. The table is for the 28 days immediately after June 30 of that year. If on July n of that year, Bill bought a suit that originally cost $450, what is the value of n?

(1) Bill paid $112.50 less than he would have if he had bought it the day before.

(2) Bill paid $202.50 for the suit.

bschool83 · Accepted Answer

fluke,

You really don't have to solve this and waste the precious time. Think about it strategically.

From 1) if Bill paid $112.5 less than the price a day before, he basically saved 25% on the suit. So it could either be July 8th or July 15th. Hence, eliminate A and D.

From 2) if Bill paid $202.5 for the suit, you can figure out the week that particular sale price was on, but not the exact date. Hence, eliminate B.

If both are true, it is easy to just pick the date which falls within the week from 2). Hence, C is correct.

No math is required except 112.5/450 which is easy 25%.

Hope this helps you.

fluke · Answer

Can't do much about it except solving: 1) 450*0.95=427.5 450*0.7=315 450*0.45=202.5 450*0.3=135.0 427.5-315=112.5 => n=8 315-202.5=112.5 => n=15 Not Sufficient. 2) 15<=n<=21 Not Sufficient. Together: n=15 Ans: "C"

agdimple333 · Answer

interesting question..

i think i will choose A for this... only statement 1 is sufficient...

how i solved?
B - of course is sufficient.. $202.50 .. falls under 3rd category BUT i dont know which day in 3rd category.. it can be any from july 15th through 21st...

now for A to be correct there is hint... to see if 55% of 450 - 30% of 450 = 112.50 and i think it is.
so it is the 15th day of july

DmitryFarberMPrep · Answer

Fluke is right. This is a typical DS trap. If we see that a difference of 112.50 show up at the junction of two date ranges, we figure we have the answer and start congratulating ourselves. However, it's really important to check and see if there is more than one junction where that particular difference shows up. Assume that there will be, and you can be pleasantly surprised if you're wrong!

rohit8865 · Answer

(1) insuff..because we don't know the discounted price/any price for which he would have paid $112.5.
(2)202.5 is what percent less of 450...
450(1-x/100)=202.5
x=55%
date "n" could be anything between july15-july21...not suff....

Combining both Bill paid $112.50 less than he would have if he had bought it the day before
means bill paid (202.5+112.5=$315) if he bought with any previous discount a day before.
315 is 30% less than 450.
So he must bought on july 15
Ans C

aserghe1 · Answer

Algebraic approach:

Statement 1 
Let  x  be the discount Bill received and let  y  be the previous period's discount. So we get this equation:
 450(1-x) = 450(1-y) - 112.50 
Which reduces to:
 x-y = 0.25 
This means that in the previous period, the discount was 25% less. Thus, Bill either bought his suit on July 8 or July 15. July 1 is not possible because there was no discount the day before. And July 22 is not possible because the discount was 15% less the day before. 
Not sufficient.
Note that if the equation reduced to  x-y = 0.15 , Statement 1 alone would have been sufficient.

Statement 2 
 202.50 = 450(1-x)  where  x  is the discount Bill received.
 x = 0.55 
So Bill could have bought his suit on any day July 15 through July 21.
Not sufficient.

Combining both statements 
In Statement 1, we narrowed down the answer to July 8 or July 15.
In Statement 2, we narrowed down the answer to July 15 through July 21.
The only date common do both is July 15.
Sufficient.

PocusFocus · Answer

Here are my two cents: This is a solution with almost no calculations

1W = P - 5%P
2W = P - 30%P
3W = P- 55%P
4W = P - 70%P

1)The purchase should be done in the last day of 1st week, or 2nd week or 3rd week to get that difference,so:
Possibles differences are: 25%P (1st week to second week) or 25%P (second week to third week) or 15%P (3rd week to fourth week)

As the suit cost $450 and the difference indicated is $112.5, there are two possible scenarios, so we can not determine the exact day
 So, 1) is not enough

2) Bill paid $202.50, and the cost is $450, so I paid a little less then 50%, I can infere that I bought the suit in the 3rd week, but I don't know the exact day, so 2) is not enough

1 & 2) We can infere that the suit was bought in the first day of the third week...15th July

Answer is C

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