James started from his home and drove eastwards at a constant speed.

Question

James started from his home and drove eastwards at a constant speed. Exactly 90 minutes after James stated from his home, his brother Patrick started from the same point and drove in the same direction as James did at a different constant speed. Patrick overtook James exactly 90 minutes after Patrick started his journey and then continued driving at the same speed for another 2 hours. By what percentage should Patrick reduce his speed so that James could catch up with Patrick in exactly 8 hours after Patrick overtook James?
A. 25%
B. 33%
C. 50%
D. 67%
E. 75%

let p=P's speed
p/2=J's speed
x=fraction of p driven for last 6 hours
in the 8 hours after overtaking J,
P drives 2p+6xp miles
while J drives 8*(p/2) miles
2p+6xp=4p
x=1/3
P should reduce his speed by 2/3=67%
D

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chetan2u · Accepted Answer

Hi
Since the distance covered by James in (90+90) minutes is same as Patrick in 90 minutes, speed of P is TWICE that of J..

Now it will be easier to give a number to each..
Let J's speed be 1kph, so P's speed will be 2kph....

We are looking for both to meet after 8 hour..
So in 8 HR , J will travel at constant rate @1kph= 8*1=8km..
P travels at 2kph for 2 hrs so travels 4km...
Remaining Kms=8-4=4...
So Phase to travel 4km in remaining 6hr...
So speed becomes 4/6=2/3kph...
Reduction=2-2/3=4/3
%=(4/3)/2*100=4/6*100=200/3=66.667%

EgmatQuantExpert  pl correct your choices as you are asking for "meeting in EXACT 8 hrs"..

EgmatQuantExpert · Answer

The official solution has been posted. Looking forward to a healthy discussion..

varundixitmro2512 · Answer

Well i seriously think we dont expect such questions in GMAT. Although we should be prepared for the worst, but still one might not expect such questions on GMAT( my own perception)

As for the explanation. After James(J) travels for 90 min of 1.5 hours Patrick(P) starts and in 90 minutes he crosses J. So P covers a distance in 90 minutes what J covers in 180 minutes. So speed of P is double that of J. Let speed of J be x km/ph and speed of P be 2x km/hr. Then they continue to travel for 2 hours. So in this 2 hours P travels a distance of 4x( 2x x 2) and J travels a distance of 2x. Distance between them will be 2x(4x - 2x). Now in order to catch P in 8 hours, J must travel faster than P. Let new slower speed of P be "p". so the eqaution now becomes (2x/x-p) = 8.

x-p will be relative speed
2x distance between them
8 hours as given in the question that J must take.

So value of new speed of P will be 3/4x

so he has to reduce the speed from 2x to 3/4 x which is around 62.5 not in the options

gracie · Answer

James started from his home and drove eastwards at a constant speed. Exactly 90 minutes after James stated from his home, his brother Patrick started from the same point and drove in the same direction as James did at a different constant speed. Patrick overtook James exactly 90 minutes after Patrick started his journey and then continued driving at the same speed for another 2 hours. By what percentage should Patrick reduce his speed so that James could catch up with Patrick in exactly 8 hours after Patrick overtook James?
A. 25%
B. 33%
C. 50%
D. 67%
E. 75%

let p=P's speed
p/2=J's speed
x=fraction of p driven for last 6 hours
in the 8 hours after overtaking J, 
P drives 2p+6xp miles
while J drives 8*(p/2) miles
2p+6xp=4p
x=1/3
P should reduce his speed by 2/3=67%
D

EgmatQuantExpert · Answer

Hey, I agree with your point that we should be prepared for the worst in GMAT and hence this question.

The main idea of this question was to see if the students can recognise the pitfall in the question. A few of them missed it and made a mistake.

Would you like to revisit your solution and focus on the last line of the question - "By what percentage should Patrick reduce his speed so that James could catch up with Patrick in exactly 8 hours after Patrick overtook James ?" Is the solution correct or will we get a different answer?

Thanks,
Saquib
Quant Expert
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EgmatQuantExpert · Answer

Hey, I agree they are meeting in exactly 8 hours, but then the last line clearly states - "in exactly 8 hours after Patrick overtook James? " In the given solution presented here, you have considered 8+2 hours, which is incorrect. Please Note: The percentages have been rounded off in the options. But then if you find the correct solution, it will be easy to figure out the correct option.

Thanks,
Saquib
Quant Expert
e-GMAT

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EgmatQuantExpert · Answer

Solution

Given

• Patrick started 90 minutes = 1.5 hours after James started his journey
 o So, James would have travelled for 1.5 hours when Patrick started his journey   
• Patrick overtook James exactly after 1. 5 hours of Patrick starting his journey
 o So, by the time Patrick overtook James, James would have travelled for 1.5 + 1.5 = 3 hours 
• Patrick drove at the same speed for another 2 hours after overtaking James and then reduces his speed
 o So, by that time James would have travelled a total of 3 + 2 = 5 hours
o Also, let Patrick reduce his speed by x%
o So, patrick’s reduced speed = P – x% of P kilometres per hour 
• James has to catch up with Patrick exactly 8 hours after Patrick overtook James
 o As Patrick overtook James when James had travelled for 3 hours, James would catch up with Patrick when James would have travelled for 3 + 8 = 11 hours

https://e-gmat.com/blogs/wp-content/uploads/2017/03/PQS460S-e1490618992335.png

To Find  : Value of x in percentage

Approach  :

1. We need to find the reduced speed of Patrick in terms of the initial speed of Patrick. 
2. Distance = Speed * Time. Since we know the time for which Patrick travelled, if we can find the distance travelled by Patrick, we would be able to find his speed.
3. Now, we can see from the diagram above that at certain points, Patrick and James are together. As they started from the same point, they would have travelled the same distance in reaching those points.
 a. So, we would try to find the distance travelled by James and then equate it with distance travelled by Patrick to find the reduced speed of Patrick 
4. We know that the speed of James is constant throughout the journey. Hence, the distance covered by him in time t will be J*t kilometres, where J is the constant speed of James. Therefore, the total distance covered by him in 11 hours is 11J.
5. We know that Partick starts 1.5 hrs later than James. He travels for 3.5 hrs with a speed P and then reduces his speed to P’ for the next 6 hours. Therefore, the distance covered by Patrick overall is 3.5P+6P’.
6. We know that there are 2 times in the journey when Patrick and James are together.
 a. Time 1: When James has travelled for 3 hours and Patrick has travelled for 1.5 hrs.
 i. 3J=1.5P  
 b. Time 2: At the end of 11 hours after James commenced his Journey.
 i. 11J=3.5P+6P’.  
7. Using these equations, we can find the relationship between P and P’. Once we find this relationship, we can then find out by how much percent did Patrick reduce his speed, by:
 a.  \mathrm x=\frac{\mathrm P-\mathrm P’}{\mathrm P}\ast100

Working Out 
 
 1. Total Distance travelled by James = 11J….(1)
2. Total Distance travelled by Patrick = 3.5 P + 6P’, where P’ = P – x% of P….(2)
3. Since the total Distance covered by James = total distance covered by Patrick, we can equate (1) and (2) to get
 a. 11J = 3.5 P + 6P’…..(3) 
4. Also, as Patrick overtook James at t =3 hours, distance covered by James (till t = 3 hours) = Distance covered by Patrick (till t= 3 hours). So, we have
 a. 3J = 1.5 P
b. J = 0.5 P….(4) 
5. Substituting (4) in (3), we have
 a. 5.5P = 3.5P + 6P’
b. 0.33*P = P’
c. P – 67% of P = P – x% of P
d. So, x = 67%

Correct Answer = 67% = Option D

nks2611 · Answer

the answer should be D,here is my solution-
let's take J's speed=10 km/h so he has traveled for 3 hrs initially that is 10*3=30km.
 now take P's speed =20km/h as we get to know that the time at which they have met is 90 minutes after J has traveled so p has also traveled 
1.5*20=30kms.

now P has traveled for the same constant rate for 2 hours after meeting so he has traveled in 3.5 hours = 30+20+20=70 kms. and as J has to catch him in 8hours after first meeting with P, so in reaming 6hrs . P must have reduced his speed, and he has traveled in remaining 6hrs that will be 6*20=80 so total distance covered by P is 70+80=150kms.

now j's speed has been constant during the whole journey so he must have traveled 8*10+30=110kms .
so the difference btw those distance is 40 , now look for option suppose if p had to reduce his speed with 50% then he must have traveled in remaining 6hrs for 60+70=130kms that is still more so take 67%which almost 2/3 so his current speed for 6 hours will be 20*1/3 and he has traveled 20*1/3*6=40 and total distance covered will be 110(70+40) . hence D is the answer

thanks 
please kudos if you it helped .

ScottTargetTestPrep · Answer

We can let James’ speed be 60 mph. Thus, when James drove 180 minutes (or 3 hours), Patrick drove only 90 minutes. So James drove 60 x 3 = 180 miles. Although Patrick only drove 90 minutes (or 1.5 hours), he drove the same distance as James (since he overtook James exactly in 90 minutes), so Patrick drove at a speed of 180/1.5 = 120 mph. He continued at this speed for another 2 hours, which means he drove another 2 x 120 = 240 miles. He will drive another 6 hours, however, at a different speed, so that James could catch up with him exactly 8 hours after overtaking James. We can let this new speed be x. So the total distance Patrick travels is 180 + 240 + 6x = 420 + 6x.

Now let’s look at the distance James traveled. Recall that he had to catch up with Patrick exactly 8 hours after Patrick overtook him. When Patrick overtook him, each had driven 180 miles. Since James’ speed was 60 mph (and he continued to drive at that speed), then, in another 8 hours, he will have driven 60 x 8 = 480 miles. Thus the total distance James will have traveled is 180 + 480 = 660.

Now we can equate the distances traveled by the two brothers as follows:

420 + 6x = 660

6x = 240

x = 40

Since Patrick’s original speed was 120 mph and his new speed is 40 mph, he must have reduced his original speed by 2/3, or 67%.

Answer: D

Redwhite387 · Answer

ScottTargetTestPrep 
Thankyou for your answer. 
How do we know for which questions we can assume values. Assuming values definately decreases a lot of time. Can we say that for this questions, a ratio/% decrease was asked so taking value was safe?

adewale223 · Answer

Made a mistake the first time and got 75%. So here is it.

Let James speed be X and Patrick initial speed be Y.

James will cover 9x/6 before Patrick moves.

He catches up 90 minutes later to give.

9/6 = 9x/ 6y - 6x

54y = 108x
y = 2x.

After Patrick overtakes James he travels a distance of 2y. After which his speed reduces to b and covers 6b.

To meet up, James will have to cover a distance of 8x.

So 
2y + 6b = 8x

Since y = 2x

4x + 6b = 8x

6b = 8x - 4x

b = 4x/6

b = 2x/3

So percentage decrease in Patrick speed =

2x - 2x/3 = 4x/3

4x/3 X 1/2x X 100 = 67% D.

Posted from my mobile device

Wadree · Answer

James drove for 90 minutes... Then Patrick started from home and caught up to james in another 90 minutes.... So all this time.... James was still driving... So james drove total 90 + 90 = 180 minutes.... And Patrick drove 90 minutes..... But because they both started from home and later Patrick caught up to james.....it means they both went same distance.....
Now.... They both went same distance...but Patrick took half time of james to go same distance.....so Patrick's speed is double of James' speed ....
Now.... Lets take Patrick speed = 100
And James' speed = 50
So.... Patrick passes james... And still drives for 2 more hours.... So in these 2 hours... Patrick goes 100 × 2 = 200....
And.... James goes 50 × 2 = 100 ....
So their difference is 100 distance....now we gotta lessen Patrick's speed so that James can catch up to him.....
But James' speed is 50.... So Patrick's speed must become less than 50.... Otherwise their difference will keep getting more and more.....lets say Patrick's speed becomes X less than 50..... Lets say Patrick's speed becomes   ......
Now every hour james will go 50....and Patrick will go   .... 
......So every hour their difference will lessen by 50 - ( 50 - X ) = X ......
Now....james will catch up to Patrick after 8 hours from when Patrick overtook james....but remember they already drove 2 more hours after Patrick had passed james.... So james will catch up to Patrick in 6 more hours......
So.... Their difference = 100
In 1 hour... Their difference lessens by = X
In 6 hours....their difference will lessen by = 6X = 100
So..... X = 100 / 6 = 16.67 ≈ 17 
Now... Patrick's original speed was = 100
Patrick's new speed = 50 - X = 50 - 17 = 33
So Patrick needs to decrease his speed by 67 % ........

!nah id win!

James started from his home and drove eastwards at a constant speed.

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James started from his home and drove eastwards at a constant speed.

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