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To find: The percent of students that passed the exam. Or we can find the number of students that passed the exam, which will also give us the answer.

Statement 1
\(\frac{7}{10}\) of boys passed. So number of boys has to be a multiple of 10.
Possible number of boys: 10,20,30. Those are all the possibilities. Next multiples of 10 will exceed the total number, 36.

12.5% of girls passed. You should know by heart that this is \(\frac{1}{8}\). So number of girls has to be a multiple of 8.
Possible number of girls: 8,16,24,32. Those are all the possibilities. Next multiples of 8 will exceed the total number, 36.

To summarize,
Possible number of boys: 10,20,30.
Possible number of girls: 8,16,24,32.
You can quickly scan these 2 sets to see which number of boys and which number of girls will sum to 36. Only boys=20 and girls=16 works. We found the number of boys in the class and the number of girls in the class, thus can find how many passed.

Sufficient

Statement 2
No info about how many passed.
Not sufficient

Answer: A
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Out of total 36 students in a class, what percent of students passed the talent hunt exam, if each of the 36 students appeared for the exam?

(1) 70% of boys and 12.5% of girls passed the talent hunt exam.

(2) There are more than 12 boys in the class.

Boys + girls = 36

(1)

means that 0,7*boys and 0,25*girls must be an integer.
there could be X girls and Y boys:
X must be a multiplier of 0,25: 4,8,12,16,20,24,28,32
Now, Y must be a multiplier of 0,7, and the number must be 36-X. We have only one option - 20. There were 36-20= 16 girls and 20 boys. 4 girls and 14 boys passed the exam. (28/36)*100= 2800/36 [%] passed the exam.

(2)

clearly not sufficient.
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(A)
70% guys = 7/10 passed while 3/10 failed
12.5% girls = 1/8 passed while 7/8 failed

Total number is 36 which can only be achieved doing 10+10+8+8 = 36

(B) Insufficient

A is answer
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