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Bunuel
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Bunuel
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S1: not suff, (17,2),(-17,2) and other non integer values of P. Many values are possible. Not sufficient

S2: P is not a prime
P= 17^(1/3), Q=6
P=17^(1/5), Q=10...

Many values are possible. Not sufficient

Ans E

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Bunuel


\(P^Q = 289\). \(P – Q = ?\)

(1) Q is not 1.
(2) P is not a prime number.


Ask yourself:
Are the values of P and Q restrictive in terms of being integer or fraction or decimal.....NO

Now, remember:
P can take ANY value and there will be a CORRESPONDING value of Q.......So, INFINITE solution.

The statements just remove some values of P and Q. Still, we have infinite combinations.

Hit E and move ahead.
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