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A: 20%

B: 50%

C: 80%

P(A&B) = 0,2 * 0,5 = 0,10 --> Must be less than or equal to 20%
P(B or C or both) = 0,5 + 0,8 - (0,5*0,8) = 0.9 --> Must be greater than or equal to 80%
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Quote:
And select for B or C or Both a description that must be true of the probability that B or C or both will occur

If we were to calculate B or C or Both, this is our standard n(B or C) given by formula
n(B or C) =  n(B) + n(C) - n(Both)
Recall we subtract Both because it is counted twice. 'Both B and C' will be maximum 50 because B is 50. 

So minimum value of B or C = 50 + 80 - 50 = 80

ANSWER: Must be greater than or equal to 80%

In case there are any doubts in this method, check: 
https://youtu.be/HRnuURqGhmg
https://youtu.be/oLKbIyb1ZrI 
­Thanks Karishma 
I am having difficulty making sense of this part
n(B or C) =  n(B) + n(C) - n(Both),
this comes to
= 50+80-(50*80) = 90% for me, and not 80%. 

While I understand the ans. choice would still be valid, as when we state above 80%, it still covers 90%, but I wonder why you are getting 80% here and what I might be missingm, if I wanted to treat this purely as a probability Q and not a sets question.­

@KarishmaB 
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Hi KarishmaB,

Thank you for the explanation. While I followed a similar train of thought when working on this problem, I was confused about whether I could assume that the universal set represents 100 (total probability is 100%). The question didn't provide any explicit conditions, or contexts, regarding these events, so I wasn't sure if events A, B, and C are part of the same universal set, (totaling 100%), or if A and B belong to one set while B and C belong to another. Essentially, your approach uses Venn Diagrams to calculate probability, which aligns with my thought process. However, I'm not sure how to define the universal set (S) and its relationship to these three events.
KarishmaB

guddo
­Events A, B, and C have the following probabilities of future occurrence:


A: 20%

B: 50%

C: 80%
On the basis of these probabilities, select for Both A and B a description that must be true of the probability that both A and B will occur. And select for B or C or Both a description that must be true of the probability that B or C or both will occur. Make only two selections, one in each column.­
­I think of these as Sets questions, not probability.

A = 20
B = 50
C = 80
(Total = 100)


Select for Both A and B a description that must be true of the probability that both A and B will occur.

If we were to calculate both A and B, it will have a maximum value of 20 because A itself is 20. So both cannot be more than that.
ANSWER: Must be less than or equal to 20%


And select for B or C or Both a description that must be true of the probability that B or C or both will occur

If we were to calculate B or C or Both, this is our standard n(B or C) given by formula
n(B or C) = n(B) + n(C) - n(Both)
Recall we subtract Both because it is counted twice. 'Both B and C' will be maximum 50 because B is 50.

So minimum value of B or C = 50 + 80 - 50 = 80

ANSWER: Must be greater than or equal to 80%

In case there are any doubts in this method, check:
https://youtu.be/HRnuURqGhmg
https://youtu.be/oLKbIyb1ZrI
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TargetMBA007
Quote:
And select for B or C or Both a description that must be true of the probability that B or C or both will occur

If we were to calculate B or C or Both, this is our standard n(B or C) given by formula
n(B or C) = n(B) + n(C) - n(Both)
Recall we subtract Both because it is counted twice. 'Both B and C' will be maximum 50 because B is 50.

So minimum value of B or C = 50 + 80 - 50 = 80

ANSWER: Must be greater than or equal to 80%

In case there are any doubts in this method, check:
https://youtu.be/HRnuURqGhmg
https://youtu.be/oLKbIyb1ZrI
­Thanks Karishma
I am having difficulty making sense of this part
n(B or C) = n(B) + n(C) - n(Both),
this comes to
= 50+80-(50*80) = 90% for me, and not 80%.

While I understand the ans. choice would still be valid, as when we state above 80%, it still covers 90%, but I wonder why you are getting 80% here and what I might be missingm, if I wanted to treat this purely as a probability Q and not a sets question.­
I think you have assumed they are independent events.
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hey, a slightly stupid question but why did you subtract the probability of both occurring (0.5*0.8). Not sure, but my natural instinct assumed it would be [(0.5+0.8) + (0.5*0.8)]

this is obviously incorrect since the answer is like 170%
demawtf
A: 20%

B: 50%

C: 80%

P(A&B) = 0,2 * 0,5 = 0,10 --> Must be less than or equal to 20%
P(B or C or both) = 0,5 + 0,8 - (0,5*0,8) = 0.9 --> Must be greater than or equal to 80%
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deepshikhasuvi
hey, a slightly stupid question but why did you subtract the probability of both occurring (0.5*0.8). Not sure, but my natural instinct assumed it would be [(0.5+0.8) + (0.5*0.8)]

this is obviously incorrect since the answer is like 170%


The solution you are referring to is not correct. Check correct solutions HERE and HERE. Hope it helps.
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