Last visit was: 23 Apr 2026, 03:23 It is currently 23 Apr 2026, 03:23
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
keiraria
Joined: 05 Apr 2012
Last visit: 01 May 2017
Posts: 29
Own Kudos:
210
 [42]
Given Kudos: 12
Posts: 29
Kudos: 210
 [42]
2
Kudos
Add Kudos
38
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,773
Own Kudos:
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,773
Kudos: 810,735
 [15]
5
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
General Discussion
User avatar
LalaB
User avatar
Current Student
Joined: 23 Oct 2010
Last visit: 17 Jul 2016
Posts: 227
Own Kudos:
1,378
 [2]
Given Kudos: 73
Location: Azerbaijan
Concentration: Finance
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
Posts: 227
Kudos: 1,378
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
manwiththeharmonica
Joined: 13 May 2012
Last visit: 05 Mar 2014
Posts: 24
Own Kudos:
27
 [3]
Given Kudos: 2
Schools: LBS '16 (A)
GMAT 1: 760 Q50 V41
Schools: LBS '16 (A)
GMAT 1: 760 Q50 V41
Posts: 24
Kudos: 27
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Nitpicking, but if 24 students scored better then Lena, then wouldnt she have scored better than 200 - 25 = 175 students?

We should count her score as well?

Posted from my mobile device
User avatar
EvaJager
Joined: 22 Mar 2011
Last visit: 31 Aug 2016
Posts: 513
Own Kudos:
2,370
 [1]
Given Kudos: 43
WE:Science (Education)
Posts: 513
Kudos: 2,370
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
manwiththeharmonica
Nitpicking, but if 24 students scored better then Lena, then wouldnt she have scored better than 200 - 25 = 175 students?

We should count her score as well?

Posted from my mobile device

There are two categories: one, the students who scored better than Lena, so their scores are definitely greater than her scores; two, those who didn't score better then Lena, so their scores are less than or equal to Lena's scores. Lena, herself is in the second category. The information that nobody has Lena's score is not relevant. What is important is how many outscored her:
on the first test - 0.2*120 = 24
on the second test - 24
In total, 24 + 24 = 48 out of 120 + 200 = 320 outscored Lena, and represent 48/320 = 15%. Therefore, Lena's score is in the 100 - 15 = 85th percentile.
avatar
154238
Joined: 09 Sep 2012
Last visit: 22 Oct 2012
Posts: 25
Own Kudos:
261
 [1]
Given Kudos: 33
Location: United States
Posts: 25
Kudos: 261
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
EvaJager
manwiththeharmonica
Nitpicking, but if 24 students scored better then Lena, then wouldnt she have scored better than 200 - 25 = 175 students?

We should count her score as well?

Posted from my mobile device

There are two categories: one, the students who scored better than Lena, so their scores are definitely greater than her scores; two, those who didn't score better then Lena, so their scores are less than or equal to Lena's scores. Lena, herself is in the second category. The information that nobody has Lena's score is not relevant. What is important is how many outscored her:
on the first test - 0.2*120 = 24
on the second test - 24
In total, 24 + 24 = 48 out of 120 + 200 = 320 outscored Lena, and represent 48/320 = 15%. Therefore, Lena's score is in the 100 - 15 = 85th percentile.

Hi Eva,

I am still not convinced with the above explanaton. Can you please explain again?
Its clearly written in the question that 24 students out of 200 scored better than Lena means she scored better than 175 students !! (Please correct me)

Thanks :)
User avatar
EvaJager
Joined: 22 Mar 2011
Last visit: 31 Aug 2016
Posts: 513
Own Kudos:
2,370
 [3]
Given Kudos: 43
WE:Science (Education)
Posts: 513
Kudos: 2,370
 [3]
3
Kudos
Add Kudos
Bookmarks
Bookmark this Post
154238
EvaJager
manwiththeharmonica
Nitpicking, but if 24 students scored better then Lena, then wouldnt she have scored better than 200 - 25 = 175 students?

We should count her score as well?

Posted from my mobile device

There are two categories: one, the students who scored better than Lena, so their scores are definitely greater than her scores; two, those who didn't score better then Lena, so their scores are less than or equal to Lena's scores. Lena, herself is in the second category. The information that nobody has Lena's score is not relevant. What is important is how many outscored her:
on the first test - 0.2*120 = 24
on the second test - 24
In total, 24 + 24 = 48 out of 120 + 200 = 320 outscored Lena, and represent 48/320 = 15%. Therefore, Lena's score is in the 100 - 15 = 85th percentile.

Hi Eva,

I am still not convinced with the above explanaton. Can you please explain again?
Its clearly written in the question that 24 students out of 200 scored better than Lena means she scored better than 175 students !! (Please correct me)

Thanks :)

There were two tests. What is important is how many outscored her on both tests:
on the first test - 0.2*120 = 24
on the second test - 24
In total, 24 + 24 = 48 out of 120 + 200 = 320 outscored Lena, and they represent 48/320 = 15%. Therefore, Lena's score is in the 100 - 15 = 85th percentile.
avatar
154238
Joined: 09 Sep 2012
Last visit: 22 Oct 2012
Posts: 25
Own Kudos:
Given Kudos: 33
Location: United States
Posts: 25
Kudos: 261
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Got it thanks :-D !!
Kudos for you :) !!
User avatar
pacifist85
Joined: 07 Apr 2014
Last visit: 20 Sep 2015
Posts: 322
Own Kudos:
Given Kudos: 169
Status:Math is psycho-logical
Location: Netherlands
GMAT Date: 02-11-2015
WE:Psychology and Counseling (Other)
Posts: 322
Kudos: 459
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi,

Great, but did the problem also give answer options? It is quite good to see what the offered answers are in order to get an idea of how test makers would trick you into giving the wrong answer!
User avatar
HardWorkBeatsAll
Joined: 17 Aug 2015
Last visit: 19 Jul 2020
Posts: 89
Own Kudos:
Given Kudos: 341
Location: India
Concentration: Strategy, General Management
GMAT 1: 750 Q49 V42
GPA: 4
WE:Information Technology (Finance: Investment Banking)
GMAT 1: 750 Q49 V42
Posts: 89
Kudos: 344
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sorry, but there still seems to be some discrepancy. If xth percentile means that x%people score BELOW you then with that explanation, EITHER (1) should be - 96 scored below so Leena was 97th and thus 23 people outscored her.
OR that Leena was 175th and she outscored 174, so overall percentile will be (174+96)/320.

Bunuel or EvaJager, can you help me understand this/confirm if my reasoning is right?
User avatar
anox
Joined: 17 Feb 2014
Last visit: 23 Sep 2022
Posts: 88
Own Kudos:
Given Kudos: 31
Location: United States (CA)
GMAT 1: 700 Q49 V35
GMAT 2: 740 Q48 V42
WE:Programming (Computer Software)
GMAT 2: 740 Q48 V42
Posts: 88
Kudos: 674
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
keiraria
Is there any formula about Percentile and percentile ranks

Lena’s first test score was at the 80th percentile in a class of 120 students. On another test, 24 out of 200 students scored better than Lena. If nobody had Lena’s score, what is Lena’s percentile after the two tests?

This is taken from the Gmat club download flashcards

thanks for your time


best regards

0A is 85TH

ORIGINAL QUESTION IS:

Lena’s grade was in the 80th percentile out of 120 grades in her class. In another class of 200 students there were 24 grades higher than Lena’s. If nobody had Lena’s grade, then Lena was what percentile of the two classes combined?

If someone's grade is in \(x_{th}\) percentile of the \(n\) grades, this means that \(x%\) of people out of \(n\) has the grades less than this person.

So, being in 80th percentile out of 120 grades means Lena outscored \(120*0.8=96\) classmates.

In another class she would outscored \(200-24=176\) students.

So, in combined classes she outscored \(96+176=272\). As there are total of \(120+200=320\) students, so Lena is in \(\frac{272}{320}=0.85=85%\), or in 85th percentile.

The concept is explained here: math-number-theory-percents-91708.html

Hope it helps.

Hi Bunuel,

In reference to number of students she outscored in second class (highlighted in red), shouldn't that number be 175 instead? (because 24 students scored more than her, she herself is 25th highest scorer and the remaining class of 175 student are the ones who scored less then her).

Although, working with 176 makes calculation easier by quickly reducing the fraction to 17/20 which is clearly .85

I am just trying to understand the correct logic for working with percentile. Will really appreciate your help.

Thanks!
User avatar
stonecold
Joined: 12 Aug 2015
Last visit: 09 Apr 2024
Posts: 2,231
Own Kudos:
Given Kudos: 893
GRE 1: Q169 V154
GRE 1: Q169 V154
Posts: 2,231
Kudos: 3,643
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Students with score greater than Lena in class A=> 20/100 *120 => 24

Students with score greater than Lena in class B => 24


Combined class strength = 120+200 = 320

Students with score greater than Lena in class A=> 20/100 *120 => 24

Students with score greater than Lena => 24+24 = 48

48 is 15 percent of 320
Hence Lena's percentile rank => 85
User avatar
Shruti0805
Joined: 24 Dec 2016
Last visit: 02 Sep 2021
Posts: 91
Own Kudos:
Given Kudos: 145
Location: India
Concentration: Finance, General Management
WE:Information Technology (Computer Software)
Kudos
Add Kudos
Bookmarks
Bookmark this Post
keiraria
Lena’s grade was in the 80th percentile out of 120 grades in her class. In another class of 200 students there were 24 grades higher than Lena’s. If nobody had Lena’s grade, then Lena was what percentile of the two classes combined?

If Lena's score is 80%, then she has outscored : (80*120)/100 people, i.e., 96 people.
Thus, 24 people have a score greater than her in her own class.

Also, in the other class there are another 24 people who would outscore her, making it a total of 48 people to outscore her.

(48*100)/320 = 15 % people to outscore her.

Thus, Lena's score would be 85% overall.

B.
User avatar
VIGHNESHKAMATH
Joined: 28 Sep 2021
Last visit: 21 Nov 2022
Posts: 146
Own Kudos:
Given Kudos: 259
Posts: 146
Kudos: 54
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
keiraria
Is there any formula about Percentile and percentile ranks

Lena’s first test score was at the 80th percentile in a class of 120 students. On another test, 24 out of 200 students scored better than Lena. If nobody had Lena’s score, what is Lena’s percentile after the two tests?

This is taken from the Gmat club download flashcards

thanks for your time


best regards

0A is 85TH

ORIGINAL QUESTION IS:

Lena’s grade was in the 80th percentile out of 120 grades in her class. In another class of 200 students there were 24 grades higher than Lena’s. If nobody had Lena’s grade, then Lena was what percentile of the two classes combined?

If someone's grade is in \(x_{th}\) percentile of the \(n\) grades, this means that \(x%\) of people out of \(n\) has the grades less than this person.

So, being in 80th percentile out of 120 grades means Lena outscored \(120*0.8=96\) classmates.

In another class she would outscored \(200-24=176\) students.

So, in combined classes she outscored \(96+176=272\). As there are total of \(120+200=320\) students, so Lena is in \(\frac{272}{320}=0.85=85%\), or in 85th percentile.

The concept is explained here: https://gmatclub.com/forum/math-number-t ... 91708.html

Hope it helps.


But doesn't this question assume that 120 grades = 120 students, couldn't there be more than one student with the same grade?

Regards
Vighnesh
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,959
Own Kudos:
Posts: 38,959
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109773 posts
Tuck School Moderator
853 posts