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Which of the following fractions is at least twice greater than 11/50?

A. 2/5
B. 11/34
C. 43/99
D. 8/21
E. 9/20

It looks very easy but what is the fastest way to solve it ?



Answer E


11/50=0.22
9/20=0.45 which is 0.01 greater than two times of 0.22
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Thx fellows !

Logically the answer will be the highest number of the answerchoice.

Since we're not allowed to use calculators, nt2010 method is the fastest I think.
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Answer = E

Rationalise the denominator, \(\frac{9}{20} = \frac{45}{100}\) is the highest
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You can also set them equal to each other, cross multiply, and compare:

A.) 2/5 = 11/50 --> 100 = 55 (more than half)
B.) 11/34 = 11/50 --> 550 = 374 (more than half)
C.) 43/99 = 11/50 --> 2,150 = 1,089 (more than half)
D.) 8/21 = 11/50 --> 400 = 231 (more than half)
E.) 9/20 = 11/50 --> 450 = 220 (less than half)

In problems like this it is fastest to skip the longer ones like B & C and jump to D & E
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Tagger


Which of the following fractions is at least twice greater than 11/50?

A. 2/5
B. 11/34
C. 43/99
D. 8/21
E. 9/20

It looks very easy but what is the fastest way to solve it ?

Hi,

I believe any choice given by GMAT invariably does not require too much of calculations BUT we should how to read the info provided by choices..

so first lets see the Q--


atleast twice greater than 11/50..

INFERENCE-


1) Only ONE choice will be > 2*11/50..
2) In a way we are also looking for the LARGEST number in choice
3) The above 2-point mean that we can eliminate choices by comparing with 22/50 and ALSO by comparing within each other..


lets see the choices-


A. 2/5 .. 2/5 = 4/20 < E. 9/20..... also 2/5=20/50 <22/50.. eliminate
B. 11/34 .. 11/34 = 22/68.. numerators are same but denominator>50 so <22/50.. eliminate
C. 43/99 .. 22/50 = 44/100... In the choice both numerator and denominator are less by one each so 43/99<44/100.. eliminate
D. 8/21 .. clearly 8/21<E.9/20.. eliminate
E. 9/20 .. Only one left 9/20 = 45/100 > 44/100.. ANSWER

E
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nt2010
The fastest way to solve this problem is to use POE and approx by making the denominator same

A) 2/ 5 = 20/50 numerator is less than 22 so out.
B) 11/34 = 550 / 170 numerator is less than 746 so out.
C) 43 / 99 = approx. 43 / 100 numerator is much less than 80 so out.
D. 8/21 = approx. 40 / 100 close to C so out..
E. 9/20 = 45 / 100 numerator is more than twice 22 so Answer is E

//Kudos please, if the above explanation is good.
­Hi Bunuel - can you please explain the answer to option B on why we are getting 550 in the numerator when the fraction is being multiplied by 5 and where does 746 come in from?

Got the answer to the question but was trying to understand the faster method with less calculation
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­Which of the following fractions is at least twice greater than 11/50?

A. 2/5
B. 11/34
C. 43/99
D. 8/21
E. 9/20

This is fantastic q as it tests multiple concepts of Numerator and Denominator of a fraction in one go.

Best way to solve this by realising that we can pick the greatest fraction from the options - as in GMAT we only have one answer. So we will use both strategy of comparing fraction with the Q asked and eliminating if we find them being less than other options.

To find : Fraction greater than 2 * (11/50) aka 22/50 aka 44/100 aka 0.44

A. 2/5
Make denominator same as it is evident we can do that so 2/5 = 40/100 which is less than 44/100 - Eliminate

B. 11/34
Cant make denominator common - but can make Numerator common - 44/136. Two fractions with same Numerator but denominator of this fraction is greater than what is required hence this is smaller than 44/100. Eliminate

C. 43/99
Cant make numerator or denominator smaller or greater. But if we add 1 to both N and D we get what is asked aka 44/100. Now When we add same constant to the numerator and denominator of a fraction and the original fraction is less than 1 (43/99 is less than 1) then the resultant fraction (44/100) is greater than original fraction. Eliminate

d.8/21
If we compare it with 9/20 that is last option we see - 8+1/21-1 = 9/20. We are adding in numerator and reducing from denominator which is perfect recipe of making resultant fraction greater than original. Which means 8/21 is not greatest fraction. Eliminate

e. 9/20
Make denominator same 9/20=45/100 which is greater than 44/100. Tada winner!
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