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16 Jan 2014, 04:52
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (01:10) correct
9%
(01:47)
wrong
based on 1709
sessions
History
Date
Time
Result
Not Attempted Yet
In triangle ABC above, what is x in terms of z ?
(A) z + 73
(B) z -73
(C) 70 - z
(B) z - 70
(E) 73 - z
Attachment:
Untitled.png [ 15.2 KiB | Viewed 37430 times ]
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16 Jan 2014, 04:53
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SOLUTION
In triangle ABC above, what is x in terms of z ?
(A) z + 73
(B) z -73
(C) 70 - z
(B) z - 70
(E) 73 - z
The sum of the degree measures of the angles in a triangle equals 180°, thus we have that \(x+(37+z)+70=180\) --> \(x=73-z\).
Answer: E.
In triangle ABC above, what is x in terms of z ?
(A) z + 73
(B) z -73
(C) 70 - z
(B) z - 70
(E) 73 - z
The sum of the degree measures of the angles in a triangle equals 180°, thus we have that \(x+(37+z)+70=180\) --> \(x=73-z\).
Answer: E.
General Discussion
16 Jan 2014, 05:33
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We know that the sum of internal angles in a triangle is 180 so:
70+37+z+x = 180
Putting in terms of X we have
107-180+z=-x
-73+z=-x Multiplying all the equation for -1
73-z=x
So E is the answer
70+37+z+x = 180
Putting in terms of X we have
107-180+z=-x
-73+z=-x Multiplying all the equation for -1
73-z=x
So E is the answer
