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Volume of cube A/Volume of cube B = [Side of cube A/ side of cube B] ^3

here Volume of Cube A = 64
Volume of Cube B = half of 64 = 32
side of cube A = 64^(1/3) = 4
side of cube B = x

putting values

(64/32) = (4/x)^3

2^(1/3) = 4/x
x = 4/2^(1/3) = 2^2/2^(1/3) = 2^(5/3) =2*2^(2/3) =2 * cubic root (4)

Hence Answer is E
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Luning1
A certain clay cube has volume 64 cubic inches. If a smaller clay cube is formed and has half the volume of the original cube, how many inches long is an edge of the smaller cube?

A. 2
B. 4
C. 8
D. \(\sqrt[3]{4}\)
E. \(2 \sqrt[3]{4}\)

Volume of cube = 64 in^3
Volume of smaller cube = 32 in^3

So side of smaller cube = \(\sqrt[3]{32}\) = \(2 \sqrt[3]{4}\)

Answer E
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Volume of cube = 64
volumne of smaller cube= 64/2 = 32

side of smaller cube = ?
formulae of volume of cube = side^3
32 = side^3
side = 2 3√2 (2*2*2*2*2)

ANSWER E
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Luning1
A certain clay cube has volume 64 cubic inches. If a smaller clay cube is formed and has half the volume of the original cube, how many inches long is an edge of the smaller cube?

A. 2
B. 4
C. 8
D. \(\sqrt[3]{4}\)
E. \(2 \sqrt[3]{4}\)


Volume of cube=(side)^3

Volume of original cube= (s)^3=64

Volume of new cube= (n)^3=32.
Edge of the cube(n)=\sqrt[3]{32}= [m]2 \sqrt[3]{4}[/m
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