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langtuprovn2007
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither Updated on: 27 Jul 2014, 17:34
Originally posted by langtuprovn2007 on 27 Jul 2014, 17:30.
Last edited by Bunuel on 27 Jul 2014, 17:34, edited 1 time in total.
Edited the question and added the OA.
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D
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86% (02:05) correct 14% (02:39) wrong based on 488 sessions

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Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 20 boys and 40 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?

(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
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D
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 27 Jul 2014, 17:41
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langtuprovn2007
Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 20 boys and 40 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?

(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
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Check the table below:
Attachment:
Untitled.png
Untitled.png [ 5.53 KiB | Viewed 9849 times ]
Numbers in black are given and in red are calculated.

Answer: D.

Hope it's clear.
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PareshGmat
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 27 Jul 2014, 23:07
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Answer = 8 =D

Refer matrix below

Values in pink are calculated
Attachments

pink.png
pink.png [ 4.23 KiB | Viewed 9599 times ]

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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 02 Mar 2015, 19:40
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Is it possible to solve this question via a venn diagram approach? I'd greatly appreciate a solution that uses venn diagrams.
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 02 Mar 2015, 20:21
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GhostA
Is it possible to solve this question via a venn diagram approach? I'd greatly appreciate a solution that uses venn diagrams.
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Venn diagrams are useful for multiple values of a single variable e.g. State of mind - happy/sad/neither. When you have two or more variables such as here where you have gender - boy/girl too, it becomes unwieldy. In this case, either use the table or logic.

Table method is shown above; here is how you will use logic:

There are 6 happy boys.
There are 4 sad girls but total 10 sad children. So rest 6 sad children must be sad boys.

We have 6 happy boys and 6 sad boys. Total we have 20 boys. So 20 - 6 - 6 = 8 boys must be neither happy nor sad.

Answer (D)
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 02 Mar 2015, 20:27
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Thanks Karishma. That's what I guessed. I usually prefer venn diagrams and just wanted to explore if there are any options besides the table. Thanks again!
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 21 Jan 2018, 20:01
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langtuprovn2007
Of 60 children, 30 are happy, 10 are sad, and 20 are neither happy nor sad. There are 20 boys and 40 girls. If there are 6 happy boys and 4 sad girls, how many boys are neither happy nor sad?

(A) 2
(B) 4
(C) 6
(D) 8
(E) 10
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Since there are 6 happy boys, there must be 24 happy girls.

Since there are 4 sad girls, there must be 6 sad boys.

Since there are a total of 20 boys, then there must be 20 - 6 - 6 = 8 boys who are neither sad nor happy.

Answer: D
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Of 60 children, 30 are happy, 10 are sad, and 20 are neither 05 Oct 2024, 00:34
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