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Bunuel
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ankitaprsd
Simplify (16^3-15^3)(16^2-15^2) =

A. 22468
B. 22351
C. 22216
D. 22192
E. 22106

Looking for a shortcut to solve this
OA soon

\((16^3 - 15^3)(16^2 - 15^2)\)

\(= (16-15)(16^2 + 16*15 + 15^2)(16+15)(16-15)\)

= (256+225+16*15) * 31

(256+225+16*15) >> This expression would give 1 at the units place

Multiplying it by 31 also gives 1 at the units place

Out of the 5 options, only 22351 qualifies

Answer = B
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ankitaprsd
Simplify (16^3-15^3)(16^2-15^2) =

A. 22468
B. 22351
C. 22216
D. 22192
E. 22106

Looking for a shortcut to solve this
OA soon

One More method

\((16^3-15^3)(16^2-15^2)\)

\(= 16^5 - 16^3 * 15^2 - 15^3 * 16^2 + 15^5\)

Writing down the last digits (Units digits) of the above 4 terms

= 6 - 0 - 0 + 5

= 1

Last digit comes to 1, only 22351 fits in

Answer = B
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Is there an alternate way to solve this problem? Or can someone explain how to know what the units digits will be please? :)
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DangerPenguin
Is there an alternate way to solve this problem? Or can someone explain how to know what the units digits will be please? :)

This might help: math-number-theory-88376.html
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