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If a car traveled the first third of the distance at 80 km/h, the second third at 24 km/h, and the final third at 48 km/h, what was the car's average (arithmetic mean) speed for the entire journey?
A. 36 km/h B. 40 km/h C. 42 km/h D. 44 km/h E. 50 km/h
If a car traveled the first third of the distance at 80 km/h, the second third at 24 km/h, and the final third at 48 km/h, what was the car's average (arithmetic mean) speed for the entire journey?
A. 36 km/h B. 40 km/h C. 42 km/h D. 44 km/h E. 50 km/h
Let the total distance be \(3x\) kilometers. Then, the total time taken is given by \(\frac{x}{80} + \frac{x}{24} + \frac{x}{48} = \frac{18x}{240}\) hours.
The average speed is calculated as \(\frac{total \ distance}{total \ time}\). Thus, average speed \(= \frac{3x}{\frac{18x}{240}} = \frac{240*3}{18} = 40\) km/h.
Instead of using fractions to compute, one can use LCM as the total distance. Let, Distance travelled in each 1/3rd part = 240 km Total Distance = 240 * 3 km Time taken when travelling at 80 kmh = 240 / 80 = 3 hr Time taken when travelling at 24 kmh = 240 / 24 = 10 hr Time taken when travelling at 48 kmh = 240 / 48 = 5 hr
Hence, average speed for entire trip = Total Distance / Total time taken = 240 *3 / (3+10+5) = 240 *3 / 18 = 40 kmh
when distance is same for all 3 parts then why cant i just divide by 3
like 24+48+80/3
Bunuel
Official Solution:
If a car traveled the first third of the distance at 80 km/h, the second third at 24 km/h, and the final third at 48 km/h, what was the car's average (arithmetic mean) speed for the entire journey?
A. 36 km/h B. 40 km/h C. 42 km/h D. 44 km/h E. 50 km/h
Let the total distance be \(3x\) kilometers. Then, the total time taken is given by \(\frac{x}{80} + \frac{x}{24} + \frac{x}{48} = \frac{18x}{240}\) hours.
The average speed is calculated as \(\frac{total \ distance}{total \ time}\). Thus, average speed \(= \frac{3x}{\frac{18x}{240}} = \frac{240*3}{18} = 40\) km/h.
when distance is same for all 3 parts then why cant i just divide by 3
like 24+48+80/3
Bunuel
Official Solution:
If a car traveled the first third of the distance at 80 km/h, the second third at 24 km/h, and the final third at 48 km/h, what was the car's average (arithmetic mean) speed for the entire journey?
A. 36 km/h B. 40 km/h C. 42 km/h D. 44 km/h E. 50 km/h
Let the total distance be \(3x\) kilometers. Then, the total time taken is given by \(\frac{x}{80} + \frac{x}{24} + \frac{x}{48} = \frac{18x}{240}\) hours.
The average speed is calculated as \(\frac{total \ distance}{total \ time}\). Thus, average speed \(= \frac{3x}{\frac{18x}{240}} = \frac{240*3}{18} = 40\) km/h.
Answer: B
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You can’t just average the speeds as (80 + 24 + 48)/3 because average speed is not the arithmetic mean when time or speed varies. The car spends different amounts of time at each speed, so you need to use the formula: