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Bunuel
When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 2. What is the value of 13y – x ?

A. -4
B. -2
C. 0
D. 2
E. 4

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X= 11*Y + 4 --------1st
2X= 8*3Y + 2 -------2nd

2nd - 1st
X= 13Y -2
so 13Y - X = 2

answer D
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Bunuel
When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 2. What is the value of 13y – x ?

A. -4
B. -2
C. 0
D. 2
E. 4

Kudos for a correct solution.

Number = Quotient * Divisor + Remainder
So, x = 11y + 4
And, 2x = 24y + 2
Solve these 2, we get,
x = 37 and y = 3.
So, 13y - x = 2
Hence option (D).

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Equation 1: x=11y+4
Equation 2: x=12y+11
from equation 1& 2 we know y=3; putting this value to find out x=37
Hence 13y-x=39-37=2

Hence answer is D
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Bunuel
When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 2. What is the value of 13y – x ?

A. -4
B. -2
C. 0
D. 2
E. 4

Kudos for a correct solution.

MAGOOSH OFFICIAL SOLUTION:
Attachment:
remainders13yminusx_text.PNG
remainders13yminusx_text.PNG [ 15.77 KiB | Viewed 14712 times ]
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x = 11y + 4
2x = 24y + 2 (-)
-x = -13y + 2
13y - x = 2

Ans = D
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Sorry but how are you getting the equations that are being used to solve? There seems to be no explanation of how you get from x/11=yR4 to x=11y+4?

Can someone please explain?
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Bunuel
When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 2. What is the value of 13y – x ?

A. -4
B. -2
C. 0
D. 2
E. 4

Kudos for a correct solution.

From the question stem, we can get two equations as below:

x=11y+4
2x=8(3y)+2

Solving both

x=37 and y=3

So, 13y-x = 13(3)-37 = 2

OA: D
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forrgrav
Sorry but how are you getting the equations that are being used to solve? There seems to be no explanation of how you get from x/11=yR4 to x=11y+4?

Can someone please explain?


The equation is really X/11 = y+4/11 since Remainder for written out is 4/11 so when you multiply both sides by 11 the 4/11 goes to 4. Equation becomes X = 11y+4
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Bunuel
When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 2. What is the value of 13y – x ?

A. -4
B. -2
C. 0
D. 2
E. 4

Kudos for a correct solution.

x = 11y + 4 ....... (I)
2x = 8*3y + 2 = 24y + 2 ..... (II)

(II) - (I)

x = 13y - 2
13y - x = 2

Answer (D)

This is not a remainders question. It is just algebraic manipulation.
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Bunuel
When positive integer x is divided by 11, the quotient is y and the remainder is 4. When 2x is divided by 8, the quotient is 3y and the remainder is 2. What is the value of 13y – x ?

A. -4
B. -2
C. 0
D. 2
E. 4
­\(x = 11y + 4\)----------(I)
\(2x = 8*3y + 2\)----------(II)

\((I)*2 = (II)\)

\(24y + 2 = 22y + 8\)

So, \(y = 3\)

From (I) 

\(x = 33 + 4 => 37\)

Now, \(13y – x = 13*3 - 37 => 2\), Answer must be (D)

 
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Deconstructing the Question

From the first condition,

\(x = 11y + 4\)

From the second condition,

\(2x = 8(3y) + 2\)

We solve the system to find \(x\) and \(y\).

Step-by-step

Simplify the second equation:

\(2x = 24y + 2\)

Divide by 2:

\(x = 12y + 1\)

Now set equal to the first expression for \(x\):

\(11y + 4 = 12y + 1\)

Solve:

\(4 = y + 1\)

\(y = 3\)

Find \(x\):

\(x = 11\cdot 3 + 4 = 37\)

Compute:

\(13y - x = 13\cdot 3 - 37 = 2\)

Answer: D
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