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Bunuel
If n = 2×3×5×7×11×13×17, then which of the following statements must be true?

I. n^2 is divisible by 600

II. n + 19 is divisible by 19

III. (n + 4)/2 is even

A. I only
B. II only
C. III only
D. I and III
E. None of the above


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I. n^2 is divisible by 600
N^2 = 900 * 7×11×13×17*7×11×13×17 clearly not divisible by 600

II. n + 19 is divisible by 19
n is even and \(\frac{(E+19)}{19}\)will not be an integer.

III. (n + 4)/2 is even
n is 2*ODD , (2*ODD +4 )/2 = ODD + 2 = ODD

Answer E
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[quote="Bunuel"]If n = 2×3×5×7×11×13×17, then which of the following statements must be true?

I. n^2 is divisible by 600

II. n + 19 is divisible by 19

III. (n + 4)/2 is even

A. I only
B. II only
C. III only
D. I and III
E. None of the above

Statement I: 600 = (2^3)*(3)*(5^2)
n^2 will have 2 factors of 2 but 600 has 3 factors of 2. So this is NOT true.

Statement 2 Since n is not divisible by 19 so n+19 is also NOT divisible by 19. So this is NOT true.

Statement 3: (n+4)/2 = n/2 + 2
Now, n/2 is divisible by 2 since it contains 2. The remainder is 3*5*7*9*11*13*17 which is ODD.
So, ODD + 2 cannot be even.
So this is NOT true.

Hence option (E).

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Bunuel
If n = 2×3×5×7×11×13×17, then which of the following statements must be true?

I. n^2 is divisible by 600

II. n + 19 is divisible by 19

III. (n + 4)/2 is even

A. I only
B. II only
C. III only
D. I and III
E. None of the above


Kudos for a correct solution.

I. since n has 2, 3, 5 one time, n^2 will have 2,2,3,3,5,5. But to be divisible by 600 completely, it should have three 2's, (since 600 = 6*10*10 = 2.3.2.5.2.5)
Thus I is not true.

II. n+19 is divisible by 19, if n is divisible by 19 too, which clearly n is not. thus II is not true.

III. we know (n+4)/2 = n/2 + 2 = odd + even = odd. Thus III is also not true.

ans None = E.
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Answer = E. None of the above

I. n^2 is divisible by 600

\(600 = 2^3 * 3^1 * 5^2\)

\(n^2 = 2^2 * 3^2 * 5^2\) (Only the factor component)

This condition fails

II. n + 19 is divisible by 19

n does not have any factor of 19

This condition fails

III. (n + 4)/2 is even

\(\frac{n+4}{2} = \frac{n}{2} + 2\)

n has only 1 factor of 2, so after dividing by 2, remaining is ODD

ODD + EVEN = ODD

This condition fails as well
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1. n^2 = 100*3*3*(7*11*13*17)^2 is not divisible by 100 but not by 6 so not divisible by 600
2. Is n divisible by 19? no; n=2*3*5*7*11*13*17. so (n+19) is also not divisible by 19
3. n/2+2 =even; n has only one 2 so n/2 is odd; odd+2= odd; not even

Hence None of the options are correct.
Answer is E.

Thanks
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Bunuel
If n = 2×3×5×7×11×13×17, then which of the following statements must be true?

I. n^2 is divisible by 600

II. n + 19 is divisible by 19

III. (n + 4)/2 is even

A. I only
B. II only
C. III only
D. I and III
E. None of the above


Kudos for a correct solution.

MAGOOSH OFFICIAL SOLUTION:
Attachment:
whichmustbetrue_text.PNG
whichmustbetrue_text.PNG [ 17.29 KiB | Viewed 18998 times ]
FAQ: If option III is divisible by 2, isn't it even?

Let's look again at what exactly this question asks for: which of the statements, after all the math is carried out, are even?

2*3*5*7*11*13*17 + 4 is divisibly by 2, yes, and that means it's even. But statement III asks about the result of (2*3*5*7*11*13*17 + 4) / 2.
After the division by 2 is carried out, we are left with an odd number: 3*5*7*11*13*17 + 2

After we divide out that 2, the numbers that are left in the numerator don't add up to an even number.
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