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yes.. made 2 right triangles n then found 2 hypotenus n added it... got 350 :?
should've got 3-4-5 triangle property
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Hi Dabhishek,

It's common to make mistakes during your training (that's one of the reasons why you train - to define your 'weak spots' and improve), so you shouldn't get too down on yourself. To properly improve though, you really have to be diligent with your review. With each question that you get wrong (especially if you get them wrong because of silly/little mistakes), you should redo the question from scratch. Do all of the work on the pad and repeat all of the steps. There's a 'mechanical' aspect to working through questions that many Test Takers do not account for. You can build your skills, knowledge, Tactics AND mechanics all at the same time, if you choose to.

GMAT assassins aren't born, they're made,
Rich
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NYCgirl15
There are two cars. One is 200 miles north of the other. Simultaneously, the car to the north is driven westward at 20 miles per hour and the other car is driven eastward at 30 miles per hour. How many miles apart are the cars after 3 hours?


A. 225
B. 250
C. 275
D. 300
E. 350


draw figure we get a rectangle figure
width = 200 and length = 150
diagonal = (200)^2+ (150)^2 ; 62500 = 250
IMO B
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The question never talks about the shortest distance. We are left tot guess whether we need the shortest arial distance or road distance.
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anmol950915
There are two cars. One is 200 miles north of the other. Simultaneously, the car to the north is driven westward at 20 miles per hour and the other car is driven eastward at 30 miles per hour. How many miles apart are the cars after 3 hours?

The question never talks about the shortest distance. We are left tot guess whether we need the shortest arial distance or road distance.

If nothing else is mentioned, “distance” always means the straight-line (shortest) distance between the two points. So here we need to calculate their separation using the Pythagorean Theorem: after 3 hours, the northern car has gone 60 miles west, the southern car has gone 90 miles east, so they are 150 miles apart horizontally and 200 miles apart vertically. The straight-line distance is \(\sqrt{150^2 + 200^2} = 250\) miles.
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isn't the shortest distance = perpendicular distance?

also, hypotenuse is the longest side of a triangle so it can't be the shortest distance?
Bunuel


If nothing else is mentioned, “distance” always means the straight-line (shortest) distance between the two points. So here we need to calculate their separation using the Pythagorean Theorem: after 3 hours, the northern car has gone 60 miles west, the southern car has gone 90 miles east, so they are 150 miles apart horizontally and 200 miles apart vertically. The straight-line distance is \(\sqrt{150^2 + 200^2} = 250\) miles.
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ashKing12
isn't the shortest distance = perpendicular distance?

also, hypotenuse is the longest side of a triangle so it can't be the shortest distance?

Please do not complicate a simple problem or overthink it. We are asked for the distance between two points, the cars. There is no such thing as a perpendicular distance between two points. The shortest distance between two points is always a straight line. The perpendicular distance applies only between a point and a line. In this problem, the distance between the two points happens to be the hypotenuse if we refer to the image posted in one of the posts above. Yes, the hypotenuse is the longest side of a triangle, but if we want to go from one end of the hypotenuse to the other, moving along the hypotenuse is the shortest path compared to going along the two legs.
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