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Bunuel
The first term of a sequence is -2 and the second term is 2. Each subsequent odd term is found by adding 2 to the previous term, and each subsequent even terms is found by multiplying the previous term by -1. What is the sum of the first 669 terms?

A. -4 B. -2 C. 0 D. 2 E. 4

Ans:B

Solution: from the statement we can find the sequence. Which is { -2,2,4,-4,-2,2,-4,4..... }
its repetitive sequence of 4 elements and sum of those four elements (first four terms) is 0
sum of 669 terms = 668+1 terms = 0 +( -2) = -2
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-2,2,4,-4

so cyclicity is 4. 669=167*4+1, where 1 is remainder. Means that 669th term is -2. Their sum is 0+(-2)=-2

B
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Bunuel
The first term of a sequence is -2 and the second term is 2. Each subsequent odd term is found by adding 2 to the previous term, and each subsequent even terms is found by multiplying the previous term by -1. What is the sum of the first 669 terms?

A. -4
B. -2
C. 0
D. 2
E. 4


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GROCKIT OFFICIAL SOLUTION:

Clearly, we are not looking to enter all 669 terms and see what the last one is. But, we can do a few and check out the pattern.

n = 1, \(a_n = -2\)

n = 2, \(a_n = 2\)

n = 3, \(a_n = 4\)

n = 4, \(a_n = -4\)

n = 5, \(a_n = -2\)

n = 6, \(a_n = 2\)

Since we can see that the pattern will repeat every 4 terms, we can solve for the remainder after dividing 669/4. Since 4 goes into 668 evenly, we know that the value will be equivalent to that of the first term, which = -2.
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Q1 = -2
Q2 = 2
Q3 = 4
Q4 = -4
Q5 = -2
Q6 = 2
Q7 = 4
Q8 = -4
Q9 = -2

each group of 4 numbers yield to a sum of 0
669/4 = 167 and the reminder is 1.
sum = 0*167+ -2 = -2
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Bunuel
The first term of a sequence is -2 and the second term is 2. Each subsequent odd term is found by adding 2 to the previous term, and each subsequent even terms is found by multiplying the previous term by -1. What is the sum of the first 669 terms?

A. -4
B. -2
C. 0
D. 2
E. 4


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Given:
1. The first term of a sequence is -2 and the second term is 2.
2. Each subsequent odd term is found by adding 2 to the previous term, and each subsequent even terms is found by multiplying the previous term by -1.

Asked: What is the sum of the first 669 terms?

a1 = -2
a2 = 2
a3 = 4
a4 = -4
a5 = -2
a6 = 2
a7 = 4
a8 = -4

The pattern {-2,2,4,-4} repeats after every 4 terms and sum of -2+2+4-4 = 0

669 = 4*167 + 1
sum of 167 such sequences of {-2,2,4,-4} will be 0.
a669 = a1 = -2

IMO B
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In this question, it may seem at the start that this question will take a lot of time to solve since we have to find the sum of 669 terms.
But, if you are able to establish a pattern, you will be able to work with this much faster.

Given that \(t_1\) = - 2 and \(t_2\) = 2. Also, \(t_3\) = 4, \(t_4\) = -4, \(t_5\) = -2, \(t_6\) = 2, \(t_7\) = 4 and \(t_8\) = -4.

From the above, we can see clearly that the terms are repeating in a cyclic manner with a cyclicity of 4. Also, we see that, in every cycle, the sum of the terms in that cycle is ZERO.
All that is left now is to see how many cycles are required to get closer to 669 terms.

The divisibililty rule for 4 says that the last 2 digits of the number should form a number divisible by 4. 69 is the number formed by the last 2 digits of 669.
69 is not divisible by 4 and leaves a remainder of 1 when divided by 4. This means that we will have the 1st term of the cycle left out.

669 = 167 * 4 + 1. This means there will be 167 cycles and the 1st term of the 168th cycle left out.

The sum of the terms in the 167 cycles is ZERO. The first term of any cycle is -2. Therefore the sum of the first 669 terms = -2.

The correct answer option is B.

Hope this helps!
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