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I got this question right through intuition but can someone diagram it for me? I don't actually understand the logic behind this question.
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The longest line we can inscribe in a square is its diagnol(BD). let length of a side of square is a. Then diagnol (BD) = aroot2 (45-45-90).
Now lets draw point O near to B making OC approximately equal to BC (OC=a). Now according to question OD=2OC but we know that BD is the longest and its value is just aroot 2. So a square cannot be drawn.
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what if the point is between A and B but not on A/B. since question states Point O is on side of AB. So the location is not clarified.

if that's the case, 1 is insufficient.

Even 2 is insufficient and ofcourse both are still insufficient. In my view answer is E. Can someone advice on my approach?
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[quote="bhargavasrikantha"]what if the point is between A and B but not on A/B. since question states Point O is on side of AB. So the location is not clarified.

if that's the case, 1 is insufficient.

Even 2 is insufficient and ofcourse both are still insufficient. In my view answer is E. Can someone advice on my approach?[/quote]

Hello

The MAX ratio of OD to OC you will get will be when point O coincides with point B. Because in that case OD will be diagonal and OC will be the side, and thus the required ratio will be √2 : 1.

If instead you take point somewhere else between A and B then OD : OC will be less than √2 : 1.

So if the Max possible ratio in this case of a square is √2 : 1,then it can never be 2:1.

That's why statement 1 is sufficient

[size=80][b][i]Posted from my mobile device[/i][/b][/size]
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