Last visit was: 21 Apr 2026, 05:16 It is currently 21 Apr 2026, 05:16
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,720
Own Kudos:
Given Kudos: 105,796
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,720
Kudos: 810,375
 [146]
12
Kudos
Add Kudos
134
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 21 Apr 2026
Posts: 109,720
Own Kudos:
Given Kudos: 105,796
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,720
Kudos: 810,375
 [33]
15
Kudos
Add Kudos
18
Bookmarks
Bookmark this Post
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,369
 [24]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,369
 [24]
15
Kudos
Add Kudos
9
Bookmarks
Bookmark this Post
General Discussion
User avatar
KS15
Joined: 21 May 2013
Last visit: 25 Jul 2019
Posts: 531
Own Kudos:
259
 [15]
Given Kudos: 608
Posts: 531
Kudos: 259
 [15]
13
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Machine B takes T hours, Machine A takes=T+2 hours
In 1 hours, they can make= (20/T+20/T+2)
Therefore, in 3 hours, they can make= 3* (20/T+20/T+2)
Solving for T, T=4, T+2=6
Therefore, if A can takes 6 hours to make 20 widgets, he will take 6*40/20=12 hours to make 40 widgets
Answer E
User avatar
anudeep133
Joined: 10 Aug 2015
Last visit: 14 Dec 2018
Posts: 94
Own Kudos:
282
 [6]
Given Kudos: 20
Posts: 94
Kudos: 282
 [6]
5
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Solution:

Let x and y be the no. of widgets made in one hour by A and B and n be the no. of hours taken by B to complete 20 widgets.
Then, ny=20 and (n+2)x=20 ==> y=20/n and x=20/(n+2) -->(1)
Given, 3(x+y) = 25 ==> 3*20(1/n + 1/(n+2)) = 25.
Solving, we get n=4

So, x=20/6.

Time taken for machine A to make 40 widgets = 2(Time taken for machine A to make 20 widgets) = 2(6) =12

Option, E.
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 19 Apr 2026
Posts: 6,976
Own Kudos:
16,890
 [16]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,976
Kudos: 16,890
 [16]
9
Kudos
Add Kudos
6
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

CONCEPT: Calculate one hour work of everyone to do further calculation

Let,
Time taken by Machine A to make 20 widgets = t hours
i.e. Time taken by Machine B to make 20 widgets = (t-2) hours

Calculating One hour work of each of them

Widgets made by Machine A in t Hour = 20
Widgets made by Machine A in 1 Hour = 20/t

Similarly,
Widgets made by Machine B in 1 Hour = 20/(t-2)

i.e. Widgets made by Machine A and B together in 1 Hour = (20/t) + [20/(t-2)] = 20(2t-2)/t(t-2)

But (Given),
Widgets made by Machine A and B together in 3 Hour = 25
i.e. Widgets made by Machine A and B together in 1 Hour = 25/3

i.e. 20(2t-2)/t(t-2) = 25/3
i.e. 4(2t-2)/t(t-2) = 5/3
i.e. 12(2t-2)=5t(t-2)
i.e. 24t-24 = 5t^2 - 10t
i.e. 5t^2 - 34t + 24 = 0
i.e. 5t^2 - 30t - 4t + 24 = 0
i.e. (t-6)(5t-4) = 0
i.e. t = 6 or 4/5
but 4/5 is not possible as (t-2) will be Negative in that case
therefore, t=6

i.e. A takes 6 hours to make 20 widgets
i.e. A will take 12 hours to make 40 widgets

Answer: option E
User avatar
santorasantu
Joined: 27 Aug 2014
Last visit: 06 Apr 2023
Posts: 242
Own Kudos:
461
 [2]
Given Kudos: 76
Location: Netherlands
Concentration: Finance, Strategy
Schools: ISB '21 LBS '22
GPA: 3.9
WE:Analyst (Energy)
Schools: ISB '21 LBS '22
Posts: 242
Kudos: 461
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.


took 4.5 mins but got it finally

Rate of B = 20/t
Rate of A = 20/(t+2)

for 25 widgets, time taken by B = 5t/4 = T1
for 25 widgets, time taken by A = 5(t+2)/4 =T2

using time for both working together as T1*T2/(T1+T2) = 3 and substituting T1 and T2 from above equations, we get a quadratic equation.
solving this: t = 4 hrs.

so, time for A to produce 20 widgets = 6 hrs
for 40 widgets it takes double the time so 12 hrs.

E
User avatar
mvictor
User avatar
Board of Directors
Joined: 17 Jul 2014
Last visit: 14 Jul 2021
Posts: 2,118
Own Kudos:
1,276
 [5]
Given Kudos: 236
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE:General Management (Transportation)
Products:
GMAT 1: 650 Q49 V30
Posts: 2,118
Kudos: 1,276
 [5]
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

i approached this one by plugging in numbers...started with C.
if 40 are made in 8 hours, then 20 are made in 4 hours. so time of A is 4, and time of B is 2.
rate together: 20/4 + 20/2 = 5+10 = 15. so in 1 hour, together make 15 widgets. in 3 hours = 45. way too much. we can eliminate right away C, B, and A - because B and A reduces the time - the total # of widgets made will be even higher.
now between D and E -> try only one ..if it doesn't work, then the other one is the answer.
i picked E:
12h to make 40 widgets, and 6 hours to make 20. this is the time of A. time of B=4 hours.
20/6 + 20/4 = 10/3 + 20/4
find LCM of 3 and 4 = 12. multiply first by 4, and second by 3:
40+60/12 = 100/12
divide by 4:
25/3
so this is the rate given.

E is the correct answer
User avatar
SVaidyaraman
Joined: 17 Dec 2012
Last visit: 11 Jul 2025
Posts: 566
Own Kudos:
1,833
 [2]
Given Kudos: 20
Location: India
Expert
Expert reply
Posts: 566
Kudos: 1,833
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Time actually worked / time it takes to do the complete job = 1
It takes 4.8 hrs together to complete 40 widgets.
A takes 4 hours more than B to complete 40 widgets
4.8/A + 4.8/(A-4) = 1
Substitute and find the answer.
A=12
avatar
cbh
Joined: 24 Jun 2017
Last visit: 30 Sep 2019
Posts: 87
Own Kudos:
212
 [2]
Given Kudos: 130
Posts: 87
Kudos: 212
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
I did the same calculations with solving a quadratic equation and it took me a while
There is a kind of shortcut which can be better option taking into account a tight GMAT time
Machine B rate 20/t
Machine A rate 20/(t+2)

let's write an equation to produce 25 widgets in 3 hours
(20/t + 20(t+2))* 3 = 25
60/t+ 60/(t+2) = 25

from now we can play a plug and guess game, we know that B has better performance so what number can be t to solve the equation for 25.
My second try was 4 and 6. Took me about a minute or a bit more for backward checking
User avatar
Mehemmed
Joined: 09 Apr 2017
Last visit: 19 Dec 2022
Posts: 109
Own Kudos:
Given Kudos: 135
Status:Turning my handicaps into assets
Posts: 109
Kudos: 50
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasPrepKarishma
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Here is how you can do it without any variables:

Together they make 25 widgets in 3 hrs
So to make 40 widgets, together they take 3*(40/25) = 4.8 hrs
So each individually will certainly take more than 4.8 hrs to make 40 widgets.

Machine A takes 2 extra hrs to make 20 widgets so it will take 4 extra hrs to make 40 widgets. So machine A will certainly take more than 8.8 hrs to make 40 widgets. So we need to pick out of (D) and (E) only.
Try (D) - If A takes 10 hrs, B takes 6 hrs and together they 1/(1/10 + 1/6) = 60/16 (less than 4 hrs)

Hence answer must be (E).


Dear VeritasPrepKarishma,

If all the options were more than 8.8, how would we solve this problem using this method? Should we test all the options?
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,369
 [1]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,369
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Mehemmed
VeritasPrepKarishma
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Here is how you can do it without any variables:

Together they make 25 widgets in 3 hrs
So to make 40 widgets, together they take 3*(40/25) = 4.8 hrs
So each individually will certainly take more than 4.8 hrs to make 40 widgets.

Machine A takes 2 extra hrs to make 20 widgets so it will take 4 extra hrs to make 40 widgets. So machine A will certainly take more than 8.8 hrs to make 40 widgets. So we need to pick out of (D) and (E) only.
Try (D) - If A takes 10 hrs, B takes 6 hrs and together they 1/(1/10 + 1/6) = 60/16 (less than 4 hrs)

Hence answer must be (E).


Dear VeritasPrepKarishma,

If all the options were more than 8.8, how would we solve this problem using this method? Should we test all the options?

\(\frac{1}{A} + \frac{1}{A + 4} = \frac{1}{4.8}\)

\(\frac{1}{A} + \frac{1}{A + 4} = \frac{5}{24}\)

Now note that if A is 10, A + 4 = 14. LCM would be 70 which is not a multiple of 24 so let's try another value.
If A = 12, A + 4 = 16. LCM would be 48, a multiple of 24 which is quite possible. Check it out.
and so on...
User avatar
jabhatta2
Joined: 15 Dec 2016
Last visit: 21 Apr 2023
Posts: 1,251
Own Kudos:
328
 [1]
Given Kudos: 188
Posts: 1,251
Kudos: 328
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Here is how you can do it without any variables:

Together they make 25 widgets in 3 hrs
So to make 40 widgets, together they take 3*(40/25) = 4.8 hrs
So each individually will certainly take more than 4.8 hrs to make 40 widgets.


Machine A takes 2 extra hrs to make 20 widgets so it will take 4 extra hrs to make 40 widgets.

So machine A will certainly take more than 8.8 hrs to make 40 widgets. So we need to pick out of (D) and (E) only.
Try (D) - If A takes 10 hrs, B takes 6 hrs and together they 1/(1/10 + 1/6) = 60/16 (less than 4 hrs)

Hence answer must be (E).

Hi VeritasKarishma

I did what you do till the red.

Then my logic was :

--- Given, Combined A + B can make 40 widgets in 4.8 hours
--- Then individually, if A and B were working at the same rate, then A and B would be able to complete 40 widgets at 9.6 hours (4.8 * 2) and B would be able to complete the job in 9.6 hours (4.8 hours * 2)

But we know A takes 4 hours more than B in terms of time when making 40 widgets

Hence the range would be 4 hours

Hence B is then taking 7.6 hours whereas A is taking 11.6 hours (the range is 4)

11.6 hours is closest to E and hence i chose E

Thoughts ?
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,369
 [2]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,369
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Here is how you can do it without any variables:

Together they make 25 widgets in 3 hrs
So to make 40 widgets, together they take 3*(40/25) = 4.8 hrs
So each individually will certainly take more than 4.8 hrs to make 40 widgets.


Machine A takes 2 extra hrs to make 20 widgets so it will take 4 extra hrs to make 40 widgets.

So machine A will certainly take more than 8.8 hrs to make 40 widgets. So we need to pick out of (D) and (E) only.
Try (D) - If A takes 10 hrs, B takes 6 hrs and together they 1/(1/10 + 1/6) = 60/16 (less than 4 hrs)

Hence answer must be (E).

Hi VeritasKarishma

I did what you do till the red.

Then my logic was :

--- Given, Combined A + B can make 40 widgets in 4.8 hours
--- Then individually, if A and B were working at the same rate, then A and B would be able to complete 40 widgets at 9.6 hours (4.8 * 2) and B would be able to complete the job in 9.6 hours (4.8 hours * 2)

But we know A takes 4 hours more than B in terms of time when making 40 widgets

Hence the range would be 4 hours

Hence B is then taking 7.6 hours whereas A is taking 11.6 hours (the range is 4)

11.6 hours is closest to E and hence i chose E

Thoughts ?

The logic is fine here when the options are not that close. Think about it - if the options had 11.5, would you choose 11.5 or 12?
Note that the average time taken would be harmonic mean of the two individual time taken and harmonic mean is less than arithmetic mean if the numbers are different. So when the numbers are 8 and 12, their arithmetic mean will be 10 but harmonic mean will be less than 10.
But if the numbers are say 7.5 and 11.5, the harmonic mean will be less than 9.5 hence 11.5 will not be possible.

Approximating is great but it becomes error free only when you know at which side your error lies. Here, it is perfectly reasonable to say that time taken by both individually, if equal would be 9.6 hrs and since there is a range of 4, the time taken by A will be more than 11.6 hrs.
User avatar
jabhatta2
Joined: 15 Dec 2016
Last visit: 21 Apr 2023
Posts: 1,251
Own Kudos:
Given Kudos: 188
Posts: 1,251
Kudos: 328
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma
VeritasKarishma
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Here is how you can do it without any variables:

Together they make 25 widgets in 3 hrs
So to make 40 widgets, together they take 3*(40/25) = 4.8 hrs
So each individually will certainly take more than 4.8 hrs to make 40 widgets.


Machine A takes 2 extra hrs to make 20 widgets so it will take 4 extra hrs to make 40 widgets.

So machine A will certainly take more than 8.8 hrs to make 40 widgets. So we need to pick out of (D) and (E) only.
Try (D) - If A takes 10 hrs, B takes 6 hrs and together they 1/(1/10 + 1/6) = 60/16 (less than 4 hrs)

Hence answer must be (E).

Hi VeritasKarishma

I did what you do till the red.

Then my logic was :

--- Given, Combined A + B can make 40 widgets in 4.8 hours
--- Then individually, if A and B were working at the same rate, then A and B would be able to complete 40 widgets at 9.6 hours (4.8 * 2) and B would be able to complete the job in 9.6 hours (4.8 hours * 2)

But we know A takes 4 hours more than B in terms of time when making 40 widgets

Hence the range would be 4 hours

Hence B is then taking 7.6 hours whereas A is taking 11.6 hours (the range is 4)

11.6 hours is closest to E and hence i chose E

Thoughts ?

The logic is fine here when the options are not that close. Think about it - if the options had 11.5, would you choose 11.5 or 12?
Note that the average time taken would be harmonic mean of the two individual time taken and harmonic mean is less than arithmetic mean if the numbers are different. So when the numbers are 8 and 12, their arithmetic mean will be 10 but harmonic mean will be less than 10.
But if the numbers are say 7.5 and 11.5, the harmonic mean will be less than 9.5 hence 11.5 will not be possible.

Approximating is great but it becomes error free only when you know at which side your error lies. Here, it is perfectly reasonable to say that time taken by both individually, if equal would be 9.6 hrs and since there is a range of 4, the time taken by A will be more than 11.6 hrs.


Hi VeritasKarishma - You are right per the highlighted in yellow. I don't know which side of 11.6 is the actual answer. In fact, i thought A was actually taking 11.6 hours exactly for 40 widgets !

I tried to understand the harmonic mean mentioned above but given i am a non math / business background, i didn't understand it.

Any logic as to why the answer for A would be MORE than 11.6 ? (without going into the concept of harmonic mean specifically)
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,369
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma
VeritasKarishma
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

Here is how you can do it without any variables:

Together they make 25 widgets in 3 hrs
So to make 40 widgets, together they take 3*(40/25) = 4.8 hrs
So each individually will certainly take more than 4.8 hrs to make 40 widgets.


Machine A takes 2 extra hrs to make 20 widgets so it will take 4 extra hrs to make 40 widgets.

So machine A will certainly take more than 8.8 hrs to make 40 widgets. So we need to pick out of (D) and (E) only.
Try (D) - If A takes 10 hrs, B takes 6 hrs and together they 1/(1/10 + 1/6) = 60/16 (less than 4 hrs)

Hence answer must be (E).

Hi VeritasKarishma

I did what you do till the red.

Then my logic was :

--- Given, Combined A + B can make 40 widgets in 4.8 hours
--- Then individually, if A and B were working at the same rate, then A and B would be able to complete 40 widgets at 9.6 hours (4.8 * 2) and B would be able to complete the job in 9.6 hours (4.8 hours * 2)

But we know A takes 4 hours more than B in terms of time when making 40 widgets

Hence the range would be 4 hours

Hence B is then taking 7.6 hours whereas A is taking 11.6 hours (the range is 4)

11.6 hours is closest to E and hence i chose E

Thoughts ?

The logic is fine here when the options are not that close. Think about it - if the options had 11.5, would you choose 11.5 or 12?
Note that the average time taken would be harmonic mean of the two individual time taken and harmonic mean is less than arithmetic mean if the numbers are different. So when the numbers are 8 and 12, their arithmetic mean will be 10 but harmonic mean will be less than 10.
But if the numbers are say 7.5 and 11.5, the harmonic mean will be less than 9.5 hence 11.5 will not be possible.

Approximating is great but it becomes error free only when you know at which side your error lies. Here, it is perfectly reasonable to say that time taken by both individually, if equal would be 9.6 hrs and since there is a range of 4, the time taken by A will be more than 11.6 hrs.


Hi VeritasKarishma - You are right per the highlighted in yellow. I don't know which side of 11.6 is the actual answer. In fact, i thought A was actually taking 11.6 hours exactly for 40 widgets !

I tried to understand the harmonic mean mentioned above but given i am a non math / business background, i didn't understand it.

Any logic as to why the answer for A would be MORE than 11.6 ? (without going into the concept of harmonic mean specifically)

Calculate the two cases:

1. A makes 8 widgets in 1 hour and B makes 12 widgets in 1 hr. If they work together, how many widgets will they make in 1 hr?

They will make 20 widgets in 1 hr together. This is equivalent to each having a rate of work of 10 widgets/hr if their rates were same.

This calculation average rate is arithmetic mean of the two rates.

2. A takes 8 hrs to complete a work and B takes 12 hrs to complete a work. If they both work together, how long will they take to complete the work?

Rate of A = 1/8 work/hrs
Rate of B = 1/12 work/hrs
Combined Rate = 1/8 + 1/12

Time taken = Work/Rate = 1/(1/8 + 1/12) = 24/5 = 4.8 hrs

This means that if each took 9.6 hrs to complete the work, they would finish it in 4.8 hrs.

This calculation of average time taken is the calculation of harmonic mean.
User avatar
jabhatta2
Joined: 15 Dec 2016
Last visit: 21 Apr 2023
Posts: 1,251
Own Kudos:
Given Kudos: 188
Posts: 1,251
Kudos: 328
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

We need to find the time taken by machine A to make 40 widgets. It will be best to take the time taken by machine A to make 40 widgets as the variable x. Then, when we get the value of x, we will not need to perform any other calculations on it and hence the scope of making an error will reduce. Also, value of x will be one of the options and hence plugging in to check will be easy.

Machine A takes x hrs to make 40 widgets.

Rate of work done by machine A = Work done/Time taken = \(\frac{40}{x}\)

Machine B take 2 hrs less than machine A to make 20 widgets hence it will take 4 hrs less than machine B to make 40 widgets. Think of it this way: Break down the 40 widgets job into two 20 widget jobs. For each job, machine B will take 2 hrs less than machine A so it will take 4 hrs less than machine A for both the jobs together.

Time taken by machine B to make 40 widgets = x – 4

Rate of work done by machine B = Work done/Time taken = \(\frac{40}{(x - 4)}\).

We know the combined rate of the machines is 25/3

So here is the equation:

\(\frac{40}{x} + \frac{40}{(x - 4)} = \frac{25}{3}\)

The steps till here are not complicated. Getting the value of x poses a bit of a problem.

Notice here that that the right hand side is not an integer. This will make the question a little harder for us, right? Wrong! Everything has its pros and cons. The 3 of the denominator gives us ideas for the values of x (as do the options). To get a 3 in the denominator, we need a 3 in the denominator on the left hand side too.

x cannot be 3 but it can be 6. If x = 6, \(\frac{40}{(6 - 4)} = 20\) i.e. the sum will certainly not be 20 or more since we have \(\frac{25}{3} = 8.33\) on the right hand side.

The only other option that makes sense is x = 12 since it has 3 in it.

\(\frac{40}{12} + \frac{40}{(12 - 4)} = \frac{10}{3} + 5 = \frac{25}{3}\)

Answer (E)

If we did not have the options, we might have tried x = 9 too before landing on x = 12. Nevertheless, these calculations are not time consuming at all since you can get rid of the incorrect numbers orally. Making a quadratic and solving it is certainly much more time consuming.

Another method could be to bring 3 to the left hand side to get the following equation:
\(\frac{120}{x} + \frac{120}{(x - 4)} = 25\)

This step doesn’t change anything but it helps if you face a mental block while working with fractions. Try to practice such questions using these techniques – they will save you a lot of time.


Hi VeritasKarishma -- Was reviewing the veritas prep official solution posted above.

From the yellow highlight specifically -- where can i learn more about this strategy /theory where because i see a "3" on the Right hand side, X on the left hand side has to be a multiple of 3 as well.

I wasn't aware that x on the Left hand side has to be multiple of three necessarily because i thought perhaps the numerator and denominator share a 3 and the three could cancel each other out (referring to the left hand side)

Any blog post on the veritas prep website can perhaps give me some more additional theory on this ?

i need some additional theory on this to inculcate on d-day !

thank you for everything you do !!!
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,369
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

We need to find the time taken by machine A to make 40 widgets. It will be best to take the time taken by machine A to make 40 widgets as the variable x. Then, when we get the value of x, we will not need to perform any other calculations on it and hence the scope of making an error will reduce. Also, value of x will be one of the options and hence plugging in to check will be easy.

Machine A takes x hrs to make 40 widgets.

Rate of work done by machine A = Work done/Time taken = \(\frac{40}{x}\)

Machine B take 2 hrs less than machine A to make 20 widgets hence it will take 4 hrs less than machine B to make 40 widgets. Think of it this way: Break down the 40 widgets job into two 20 widget jobs. For each job, machine B will take 2 hrs less than machine A so it will take 4 hrs less than machine A for both the jobs together.

Time taken by machine B to make 40 widgets = x – 4

Rate of work done by machine B = Work done/Time taken = \(\frac{40}{(x - 4)}\).

We know the combined rate of the machines is 25/3

So here is the equation:

\(\frac{40}{x} + \frac{40}{(x - 4)} = \frac{25}{3}\)

The steps till here are not complicated. Getting the value of x poses a bit of a problem.

Notice here that that the right hand side is not an integer. This will make the question a little harder for us, right? Wrong! Everything has its pros and cons. The 3 of the denominator gives us ideas for the values of x (as do the options). To get a 3 in the denominator, we need a 3 in the denominator on the left hand side too.

x cannot be 3 but it can be 6. If x = 6, \(\frac{40}{(6 - 4)} = 20\) i.e. the sum will certainly not be 20 or more since we have \(\frac{25}{3} = 8.33\) on the right hand side.

The only other option that makes sense is x = 12 since it has 3 in it.

\(\frac{40}{12} + \frac{40}{(12 - 4)} = \frac{10}{3} + 5 = \frac{25}{3}\)

Answer (E)

If we did not have the options, we might have tried x = 9 too before landing on x = 12. Nevertheless, these calculations are not time consuming at all since you can get rid of the incorrect numbers orally. Making a quadratic and solving it is certainly much more time consuming.

Another method could be to bring 3 to the left hand side to get the following equation:
\(\frac{120}{x} + \frac{120}{(x - 4)} = 25\)

This step doesn’t change anything but it helps if you face a mental block while working with fractions. Try to practice such questions using these techniques – they will save you a lot of time.


Hi VeritasKarishma -- Was reviewing the veritas prep official solution posted above.

From the yellow highlight specifically -- where can i learn more about this strategy /theory where because i see a "3" on the Right hand side, X on the left hand side has to be a multiple of 3 as well.

I wasn't aware that x on the Left hand side has to be multiple of three necessarily because i thought perhaps the numerator and denominator share a 3 and the three could cancel each other out (referring to the left hand side)

Any blog post on the veritas prep website can perhaps give me some more additional theory on this ?

i need some additional theory on this to inculcate on d-day !

thank you for everything you do !!!

Try this:

a + b = 25/3

Which two numbers without a denominator of 3 can you add to give 25/3? There needs to be a 3 in the denominator in at least one of a or b to get the sum of 25/3.

Similarly try a + b = 11/2
11/2 is 5.5. So the 0.5 has to come from somewhere to add up to 5.5
User avatar
GMATGuruNY
Joined: 04 Aug 2010
Last visit: 02 Apr 2026
Posts: 1,347
Own Kudos:
Given Kudos: 9
Schools:Dartmouth College
Expert
Expert reply
Posts: 1,347
Kudos: 3,904
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Machine A takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine A to make 40 widgets?

(A) 5
(B) 6
(C) 8
(D) 10
(E) 12

We can PLUG IN THE ANSWERS, which represent A's time to produce 40 widgets.
When the correct answer is plugged in, A and B will produce 25 widgets in 3 hours.

D: 10
Here, A can produce 40 widgets in 10 hours, implying that the time for A to produce 20 widgets = 5 hours.
Since A tales 2 hours longer than B, B's time to produce 20 widgets = 3 hours.

Since A takes 5 hours to produce 20 widgets, A's rate \( = \frac{work}{time} = \frac{20}{5} = 4\) widgets per hour.
Since B takes 3 hours to produce 20 widgets, B's rate \( = \frac{work}{time} = \frac{20}{3}\) widgets per hour.

Combined rate for A and B \(= 4+\frac{20}{3} = \frac{32}{3}\) widgets per hour.
Work produced by A and B in 3 hours \(= (rate)(time) = \frac{32}{3}*3 = 32\) widgets.

Here, A and B produce too many widgets and thus are working TOO FAST.
Implication:
For the rate to be reduced, A must take LONGER to produce 40 widgets, with the result that A and B will work more SLOWLY.

User avatar
plaverbach
User avatar
Retired Moderator
Joined: 25 Mar 2014
Last visit: 28 Sep 2021
Posts: 212
Own Kudos:
Given Kudos: 250
Status:Studying for the GMAT
Location: Brazil
Concentration: Technology, General Management
GMAT 1: 700 Q47 V40
GMAT 2: 740 Q49 V41 (Online)
WE:Business Development (Finance: Venture Capital)
Products:
GMAT 2: 740 Q49 V41 (Online)
Posts: 212
Kudos: 540
Kudos
Add Kudos
Bookmarks
Bookmark this Post
VeritasKarishma , thanks for the insights!

I came with an approach that I could not follow throw, can any one point me in the wright direction?

I tried to make sure that I was working with just one full work, and I thought that 100 widgets was a good number.

So A would take 10 more hours than machine B to make 100 widgets
AND
Working together, the machines can make 100 widgets in 12 hours

QUESTION
how long will it take machine A to make 40 widgets

Was this a good approach? How can one solve it?

[edit] I could solve in ~10 min, but this was not a good idea, right?
 1   2   
Moderators:
Math Expert
109720 posts
Tuck School Moderator
853 posts