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Bunuel
Line J has a y-intercept of 6 and passes through point (a,b). What is the slope of Line J in terms of a and b?

A. (a−6)/b
B. (a−b)/6
C. (6−a)/b
D. (6−b)/a
E. (b−6)/a

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The two points given here are (0,6) and (a,b)

Slope m =b-6/a

Answer: E
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Just another alternate way.

Equation of line :

y = mx + b, where b is the y-intercept & m is the slope.

We have given y-intercept of this line as 6 and the line passes through point(a,b).

Therefore,

b = ma + 6

ma = ( b - 6 )

m = \(\frac{( b - 6 )}{a}\)


Answer is E
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Bunuel
Line J has a y-intercept of 6 and passes through point (a,b). What is the slope of Line J in terms of a and b?

A. (a−6)/b
B. (a−b)/6
C. (6−a)/b
D. (6−b)/a
E. (b−6)/a

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VERITAS PREP OFFICIAL SOLUTION:

You know that the line goes through point (a,b) and the y-intercept of 6 tells you that the line also goes through point (0,6). So you can use the "rise over run" slope formula to calculate the slope. Recognizing that the five answer choices focus on a,b, and 6, you should see that you should subtract 0 and 6 (subtracting 0 is the same as doing nothing at all) to get your math looking like the answer choices. So you'll set up the equation:

(b−6)/(a−0), and end up with answer choice E.
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Bunuel
Line J has a y-intercept of 6 and passes through point (a,b). What is the slope of Line J in terms of a and b?

A. (a−6)/b
B. (a−b)/6
C. (6−a)/b
D. (6−b)/a
E. (b−6)/a

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when x = 0 then y= 6
when x = a then y=b

\(slope =\frac{y2-y1}{x2-x1}\)

\(slope =\frac{6-b}{a-0}\)

\(slope =\frac{6-b}{a}\)

Answer is E
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y-intercept is 6, therefore the line passes through the point (0,6). Also, given that the line also passes through point (a,b) therefore the slope of the line is (y2-y1)/(x2-x1)=(b-6)/a. Hence, option E
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